Galilei, Galileo
,
Mechanics
,
1665
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weigh equally it would be neceſſary to hang it nearer to the
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Perpendicular C, as
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v. </
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<
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in E: and look how many times the Di
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ſtance C A ſhall contain A E, ſo many times ſhall the Metal
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weigh more than the Water. </
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>Let us therefore ſuppoſe that the
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Weight in B be Gold, and that weighed in the Water it with
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draws the Counterpoiſe D into E; and then doing the ſame with
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pure Silver, let us ſuppoſe that its Counterpoiſe, when afterwards
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it is weighed in the Water, returneth to F: which point ſhall be
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nearer to the point C, as Experience ſheweth, becauſe the Silver
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is leſs grave than the Gold: And the Diſtance that is between
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A and F ſhall have the ſame Difference with the Diſtance A E,
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that the Gravity of the Gold hath with that of the Silver. </
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>But if
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we have a Mixture of Gold and Silver, it is clear, that by reaſon it
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participates of Silver, it ſhall weigh leſs than the pure Gold, and
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by reaſon it participates of Gold, it ſhall weigh more than the
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pure Silver: and therefore being weighed in the Air, and deſiring
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that the ſame Counterpoiſe ſhould counterpoiſe it, when that
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Mixture ſhall be put into the Water it will be neceſſary to draw
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the ſaid Counterpoiſe more towards the Perpendicular C, than the
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point E is, which is the term of the Gold; and more from C
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than F is, which is the term of the pure Silver; Therefore it ſhall
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fall between the points E and F: And the proportion into which
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the Diſtance EF ſhall be divided, ſhall exactly give the proportion
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of the two Metals which compound that Mixture. </
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<
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>As for exam
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ple: Let us ſuppoſe the Mixture of Gold and Silver to be in B,
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counterpoiſed in
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the Air by D,
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which Counter
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poiſe when the
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Compound Me
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tal is put into the Water returneth into G: I ſay now, that the
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Gold and the Silver which compound this Mixture are to one ano
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ther in the ſame proportion, as the Diſtance F G is to the Diſtance
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G E. </
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>But you muſt know that the Diſtance G F terminated in
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the mark of the Silver, ſhall denote unto us the quantity of the
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Gold, and the Diſtance G E, terminated in the mark of the Gold,
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ſhall ſhew us the quantity of the Silver: inſomuch that if F G
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ſhall prove double to G E, then that Mixture ſhall be two parts
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Gold, and one part Silver: and in the ſame method proceeding in
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the examination of other Mixtures, one ſhall exactly find the
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quantity of the ſimple Metals.</
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>To compoſe the Ballance, therefore, take a Rod at leaſt a yard
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long, (and the longer it is, the exacter the Inſtrument ſhall be)
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and divide it in the midſt, where place the Perpendicular: then
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adjuſt the Arms that they may ſtand in
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Equilibrium,
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by filing or </
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