Jordanus de Nemore, [Liber de ratione ponderis], 1565

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              <p>
                <s id="id.2.2.02.09">
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            <subchap1>
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                <s id="id.2.3.00.01">Quaestio secunda.
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              </p>
              <p>
                <figure id="id.049.01.009.1.jpg" xlink:href="049/01/009/1.jpg" number="2"/>
                <figure id="id.049.01.009.2.jpg" xlink:href="049/01/009/2.jpg" number="3"/>
                <s id="id.2.3.01.01">Quum aequilibris fuit positio aequalis aequis ponderibus ap­
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                pensis ab aequalitate non discedet: et si á rectitudine separa­
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                tur, ad aequalitatis situm reuertetur. </s>
                <s id="id.2.3.01.02">Si uero inaequalia appen­
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                dantur, ex parte grauioris usque ad directionem declinare co
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                getur. </s>
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                <s id="id.2.3.02.01">Aequilibris dicitur quando á
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                centro circunuolutionis bra­
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                chia regulae sunt aequalia. </s>
                <s id="id.2.3.02.02">Sit
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                ergo centrum a, et regula b, a, c, ap­
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                pensa b, et c, perpendiculum f, a. </s>
                <s id="id.2.3.02.03">Cir
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                cunducto igitur circulo per b, et c,
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                in medio cuius inferioris medietatis
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                sit e, manifestum quoniam descensus
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                tam b, quám c, e, per circunferentiam
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                circuli uersus e, et cum aeque obli­
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                quus sit hinc inde descensus, quum sint
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                aeque ponderosa, non mutabit alter­
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                utrum. </s>
                <s id="id.2.3.02.04">Ponatur item quód submit­
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                atur ex parte b, et ascendat ex par
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                te c, dico quoniam redibit ad aequali­
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                tatem. est enim minus obliquus de­
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                scensus a, ad aequalitatem, quám a, b,
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                uersus e. </s>
                <s id="id.2.3.02.05">Sumantur enim sursum ar
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                cus aequales, quantumlibet parui qui
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                sint c, d, et h, b, et ductis lineis ad ae
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                quidistantiam aequalitatis, quae sint,
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                c, 2, l, et d, m, n. </s>
                <s id="id.2.3.02.06">Item b, k, h, 6, y, t, di
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                mittatur orthogonaliter descendens
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                diametrum quae sit f, 2, m, a, k, y, e,
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                erit quód 2, m, maior k, y, quia sum­
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                pto uersus f, arcu ex eo quód sit aequa
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                lis c, d, et ducta ex transuerso linea
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                x, r, s, erit r, 2, minor 2, m, quód facile demonstrabis. </s>
                <s id="id.2.3.02.07">Et quia r, 2, est ae­
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                qualis k, y, erit 2, m, maior k, y. </s>
                <s id="id.2.3.02.08">Quia igitur quilibet arcus sub c, plus ca­
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                piat de directo quám ei aequalis sub b, directo est descensus a, c, quám a, b,
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                et ideo in altiori situ grauius erit c, quám b, redibit ergo ad aequalitatem.</s>
              </p>
            </subchap1>
          </chap>
        </body>
      </text>
    </archimedes>
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