Stelliola, Niccol� Antonio, De gli elementi mechanici, 1597

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        <body>
          <chap id="N1013B">
            <pb xlink:href="041/01/006.jpg" pagenum="5"/>
            <p id="N10190" type="main">
              <s id="N10192">Percioche eſſendo le C G H F eguali. </s>
              <s id="N10194">e le G D E H
                <lb/>
              anco eguali: ma le eguali ſono proportionali: ſono
                <expan abbr="dũque">dunque</expan>
                <lb/>
              come C G ad E H, coſi H F ad G D: ilche hauea da mo­
                <lb/>
              ſtrarſi. </s>
            </p>
          </chap>
          <chap id="N1019F">
            <p id="N101A0" type="head">
              <s id="N101A2">
                <emph type="italics"/>
              PROPOSITIONE.
                <emph.end type="italics"/>
                <lb/>
              II. </s>
            </p>
            <p id="N101AA" type="main">
              <s id="N101AC">Se alla linea della ſtatera ſi applicano continuatamen­
                <lb/>
              te due corpi: li centri delli corpi applicati, ſono diſtanti
                <lb/>
              dal centro di tutto il compoſto, di diſtanze proportio­
                <lb/>
              nali alli peſi, pigliati reciprocamente. </s>
            </p>
            <figure id="id.041.01.006.1.jpg" xlink:href="041/01/006/1.jpg" number="5"/>
            <p id="N101B7" type="head">
              <s id="N101B9">
                <emph type="italics"/>
              Dimoſtratione.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="N101BF" type="main">
              <s id="N101C1">
                <emph type="italics"/>
              Sia la linea della ſtatera, A B, l'vn delli corpi applicati ſia
                <lb/>
              B C, l'altro ſia C A, e l'applicatione del corpo B C occupi la parte di li­
                <lb/>
              nea B D, e del corpo C A, la parte A D, e diuidaſi B D, in par­
                <lb/>
              ti vguali al ponto E: & A D in parti eguali il ponto F: è manifesto
                <lb/>
              che del corpo applicato à B D, il ponto del momento ſia E, e del cor­
                <lb/>
              po applicato a D A, il ponto del momento ſia F, dico che diuiſa B A
                <lb/>
              tutta per metà nel ponto G, che è ponto di
                <expan abbr="momẽto">momento</expan>
                <lb/>
              della grauezza tut­
                <lb/>
              ta compoſta di ambedue: c'habbia la diſtanza F G a G E la ragione
                <lb/>
              che'l peſo di B C al peſo di C A. </s>
              <s id="N101DA">Si moſtra percioche la ragione del
                <lb/>
              peſo di B C, al peſo di C A, e l'iſteſſa che delli corpi: e delli corpi
                <emph.end type="italics"/>
                <emph.end type="italics"/>
              </s>
            </p>
          </chap>
        </body>
      </text>
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