Bošković, Ruđer Josip, Abhandlung von den verbesserten dioptrischen Fernröhren aus den Sammlungen des Instituts zu Bologna sammt einem Anhange des Uebersetzers

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          <p>
            <s xml:id="echoid-s1444" xml:space="preserve">
              <pb o="116" file="0120" n="120" rhead="Abhandlung"/>
            ein großes hölzernes Lineal, das man vermittels
              <lb/>
            einer Schnur auf der Wand auf-und ablaſſen
              <lb/>
            kann, ſo, daß ſeine Stellung jederzeit hori-
              <lb/>
            zonkal, und mit der Achſe des Prisma paral-
              <lb/>
            lel verbleibe. </s>
            <s xml:id="echoid-s1445" xml:space="preserve">Dieſes Lineal läßt man bis Gg
              <lb/>
            herunter, daß ſeine unterſte Schneide den Rand
              <lb/>
            des ſcheinbaren Gegenſtandes R E r berühre,
              <lb/>
            wenn es dem Auge O in einer mäßigen Ent-
              <lb/>
            fernung von dem Prisma, mit dem oberen
              <lb/>
            Theile des Papiers T t durch die ungebrochenen
              <lb/>
            Straalen H T O, h t O zuſammen zu ſtoſſen
              <lb/>
            ſcheinet. </s>
            <s xml:id="echoid-s1446" xml:space="preserve">Auf dieſe Weiſe erhält man die Lage
              <lb/>
            des Punktes E auf der Wand, welches ſonſt
              <lb/>
            von dem Prisma verdecket wird, nämlich durch
              <lb/>
            die über das Prisma hinaus laufenden Theile
              <lb/>
            des Lineals H G, h g.</s>
            <s xml:id="echoid-s1447" xml:space="preserve"/>
          </p>
          <p>
            <s xml:id="echoid-s1448" xml:space="preserve">178. </s>
            <s xml:id="echoid-s1449" xml:space="preserve">Iſt nun der Ort E, an welchem der
              <lb/>
            unterſte Theil A des Gegenſtandes (Fig. </s>
            <s xml:id="echoid-s1450" xml:space="preserve">16
              <lb/>
              <note position="right" xlink:label="note-0120-01" xlink:href="note-0120-01a" xml:space="preserve">Fig. 16
                <lb/>
              Tab. I.</note>
            Tab. </s>
            <s xml:id="echoid-s1451" xml:space="preserve">I.) </s>
            <s xml:id="echoid-s1452" xml:space="preserve">A a erſcheinet, richtig bemerket worden,
              <lb/>
            ſo fiudet man die Brechung der rothen Straa-
              <lb/>
            len, und den ihnen gebührenden Werth m.
              <lb/>
            </s>
            <s xml:id="echoid-s1453" xml:space="preserve">Eben alſo verfährt man in der Beſtimmung
              <lb/>
            des ſcheinbaren Ortes e, allwo der oberſte Theil
              <lb/>
            a des Gegenſtandes geſehen wird, und erhält
              <lb/>
            hierdurch das m für die violeten Straalen,
              <lb/>
            folglich auch d m.</s>
            <s xml:id="echoid-s1454" xml:space="preserve"/>
          </p>
          <p>
            <s xml:id="echoid-s1455" xml:space="preserve">179. </s>
            <s xml:id="echoid-s1456" xml:space="preserve">Laſſen es die Umſtände nicht zu,
              <lb/>
            daß (Fig. </s>
            <s xml:id="echoid-s1457" xml:space="preserve">20 Tab. </s>
            <s xml:id="echoid-s1458" xml:space="preserve">II) D A mit der Vertical-
              <lb/>
              <note position="left" xlink:label="note-0120-02" xlink:href="note-0120-02a" xml:space="preserve">Fig. 20
                <lb/>
              Tab. II.</note>
            linie A E einen rechten Winkel mache, ſo be-
              <lb/>
            merke man den Punkt V, auf welchen die Ho-
              <lb/>
            rizontallinie D V fällt, und meſſe die V A,
              <lb/>
            V E, das iſt, die Tangenten der Winkel V D A,
              <lb/>
            V D E, derer Summe, oder Differenz die
              <lb/>
            ganze Brechung A D E giebt, im Anſehen </s>
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