Bošković, Ruđer Josip
,
Abhandlung von den verbesserten dioptrischen Fernröhren aus den Sammlungen des Instituts zu Bologna sammt einem Anhange des Uebersetzers
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Von verbeß. Fernröhren.
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<
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<
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xml:space
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">Nachdem man entweder auf itzt an-
<
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geführte Weiſe, oder nach einer der vorigen
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Methoden, die mittleren Werthen m, M, wie
<
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auch die Brechungen r, R im Falle, da nur
<
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zwey Winkel ſind, gefunden hat, kann man auch
<
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das Verhältniß d M zu d m aus der Formel
<
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(161) {d M/d m} = {coſ. </
s
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<
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xml:space
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">{C + R/2}/coſ. </
s
>
<
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xml:id
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xml:space
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">{c + r/2}} x {ſin. </
s
>
<
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xml:id
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xml:space
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">{1/2}c/ſin. </
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>
<
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xml:space
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">{1/2}C} ſuchen,
<
lb
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weil in derſelben {d R/d r} = 1 wird, da ſich die
<
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widrigen Brechungen aufheben. </
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<
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xml:space
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preserve
">Wenn man
<
lb
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drey Winkel hat, und bey einem c′, r′ jenes gilt,
<
lb
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was bey dem gleichgearteten c, r; </
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>
<
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xml:space
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">hat man aus
<
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der Formel (160) d r = {2 d m ſin. </
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<
s
xml:id
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"
xml:space
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">{1/2}c/coſ. </
s
>
<
s
xml:id
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"
xml:space
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">{c + r/2}}, dr′ =
<
lb
/>
{2 d m ſin. </
s
>
<
s
xml:id
="
echoid-s1633
"
xml:space
="
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">{1/2} c′/coſ. </
s
>
<
s
xml:id
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echoid-s1634
"
xml:space
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preserve
">{c′ + r′/2}}, d R = {2 d M ſin. </
s
>
<
s
xml:id
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echoid-s1635
"
xml:space
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">{1/2} C/coſ. </
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<
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xml:id
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xml:space
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">{C + R/2}}; </
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<
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xml:space
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">und
<
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/>
weil d r + d r′ = d R, ſo ſtehet d M : </
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<
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xml:id
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xml:space
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">d m =
<
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/>
{ſin. </
s
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<
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xml:id
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xml:space
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">{1/2} C/coſ.</
s
>
<
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xml:id
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xml:space
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">{C + R/2}} : </
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>
<
s
xml:id
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xml:space
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">{ſin. </
s
>
<
s
xml:id
="
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"
xml:space
="
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">{1/2} c/coſ. </
s
>
<
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xml:id
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xml:space
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">{c + r/2}} + {ſin. </
s
>
<
s
xml:id
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xml:space
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">{1/2} c′/coſ. </
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>
<
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xml:id
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xml:space
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">{c′ + r′/2}}. </
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<
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xml:space
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doch wird erfodert, daß man bey dieſem </
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