Gravesande, Willem Jacob 's
,
An essay on perspective
Text
Text Image
Image
XML
Thumbnail overview
Document information
None
Concordance
Notes
Handwritten
Figures
Content
Thumbnails
Page concordance
<
1 - 30
31 - 60
61 - 90
91 - 120
121 - 150
151 - 180
181 - 210
211 - 237
>
Scan
Original
121
58
122
123
124
125
59
126
60
127
128
129
130
61
131
62
132
63
133
64
134
135
136
137
65
138
66
139
67
140
68
141
142
143
144
69
145
70
146
71
147
72
148
149
150
<
1 - 30
31 - 60
61 - 90
91 - 120
121 - 150
151 - 180
181 - 210
211 - 237
>
page
|<
<
(65)
of 237
>
>|
<
echo
version
="
1.0RC
">
<
text
xml:lang
="
en
"
type
="
free
">
<
div
xml:id
="
echoid-div227
"
type
="
section
"
level
="
1
"
n
="
119
">
<
p
>
<
s
xml:id
="
echoid-s1563
"
xml:space
="
preserve
">
<
pb
o
="
65
"
file
="
0119
"
n
="
137
"
rhead
="
on PERSPECTIVE.
"/>
being produced, will meet each other in the
<
lb
/>
Horizontal Line.</
s
>
<
s
xml:id
="
echoid-s1564
"
xml:space
="
preserve
"/>
</
p
>
</
div
>
<
div
xml:id
="
echoid-div229
"
type
="
section
"
level
="
1
"
n
="
120
">
<
head
xml:id
="
echoid-head126
"
xml:space
="
preserve
">CHAP. V.</
head
>
<
p
style
="
it
">
<
s
xml:id
="
echoid-s1565
"
xml:space
="
preserve
">Of throwing Figures into Perſpective, when
<
lb
/>
the Perſpective Plane is conſider’d as being
<
lb
/>
inclined.</
s
>
<
s
xml:id
="
echoid-s1566
"
xml:space
="
preserve
"/>
</
p
>
</
div
>
<
div
xml:id
="
echoid-div230
"
type
="
section
"
level
="
1
"
n
="
121
">
<
head
xml:id
="
echoid-head127
"
xml:space
="
preserve
">
<
emph
style
="
sc
">Problem</
emph
>
I.</
head
>
<
p
style
="
it
">
<
s
xml:id
="
echoid-s1567
"
xml:space
="
preserve
">81. </
s
>
<
s
xml:id
="
echoid-s1568
"
xml:space
="
preserve
">TO find the Perſpective of a Figure in the
<
lb
/>
<
note
position
="
right
"
xlink:label
="
note-0119-01
"
xlink:href
="
note-0119-01a
"
xml:space
="
preserve
">Fig. 44.</
note
>
Geometrical Plane.</
s
>
<
s
xml:id
="
echoid-s1569
"
xml:space
="
preserve
"/>
</
p
>
<
p
>
<
s
xml:id
="
echoid-s1570
"
xml:space
="
preserve
">Let X be the Vertical Plane; </
s
>
<
s
xml:id
="
echoid-s1571
"
xml:space
="
preserve
">S I the Station
<
lb
/>
Line, S the Station Point, and H the Interſecti-
<
lb
/>
on of the Station Line and Baſe Line. </
s
>
<
s
xml:id
="
echoid-s1572
"
xml:space
="
preserve
">Now
<
lb
/>
draw the Vertical Line H V through the Point H,
<
lb
/>
making an Angle with S I, equal to the Angle
<
lb
/>
of Inclination of the perſpective Plane; </
s
>
<
s
xml:id
="
echoid-s1573
"
xml:space
="
preserve
">then
<
lb
/>
raiſe the Perpendicular I O to S I, in the Sta-
<
lb
/>
tion Point S, equal to the Height of the Eye;
<
lb
/>
</
s
>
<
s
xml:id
="
echoid-s1574
"
xml:space
="
preserve
">and through the Extremity of the ſaid Perpen-
<
lb
/>
dicular, draw the principal Ray O V, paral-
<
lb
/>
lel to S I, and cutting H V in the Point of
<
lb
/>
Sight V.</
s
>
<
s
xml:id
="
echoid-s1575
"
xml:space
="
preserve
"/>
</
p
>
<
p
>
<
s
xml:id
="
echoid-s1576
"
xml:space
="
preserve
">Now it is evident, that O V determines the
<
lb
/>
Length of the principal Ray, and H V the Di-
<
lb
/>
ſtance from the Baſe Line to the Horizontal
<
lb
/>
Line; </
s
>
<
s
xml:id
="
echoid-s1577
"
xml:space
="
preserve
">and ſince the Demonſtration of the
<
lb
/>
Problems in the aforegoing Chapters regarding
<
lb
/>
the Geometrical Plane, have alſo Relation to
<
lb
/>
the perſpective Plane being inclined, the ſaid
<
lb
/>
Problems may be here uſed; </
s
>
<
s
xml:id
="
echoid-s1578
"
xml:space
="
preserve
">and conſequently,
<
lb
/>
this inclined perſpective Plane is reduced to a
<
lb
/>
Perpendicular one, view’d by an Eye, whoſe
<
lb
/>
Height is H V, and Diſtance O V.</
s
>
<
s
xml:id
="
echoid-s1579
"
xml:space
="
preserve
"/>
</
p
>
</
div
>
</
text
>
</
echo
>