Valerio, Luca
,
De centro gravitatis solidorvm libri tres
Text
Text Image
Image
XML
Thumbnail overview
Document information
None
Concordance
Figures
Thumbnails
Page concordance
<
1 - 30
31 - 60
61 - 90
91 - 120
121 - 150
151 - 180
181 - 210
211 - 240
241 - 270
271 - 283
>
Scan
Original
141
142
143
144
145
146
147
148
149
150
151
152
153
154
155
156
157
158
159
160
161
162
163
164
165
166
167
168
169
170
<
1 - 30
31 - 60
61 - 90
91 - 120
121 - 150
151 - 180
181 - 210
211 - 240
241 - 270
271 - 283
>
page
|<
<
of 283
>
>|
<
archimedes
>
<
text
>
<
body
>
<
chap
>
<
p
type
="
main
">
<
s
>
<
pb
xlink:href
="
043/01/146.jpg
"
pagenum
="
59
"/>
tij ad quartum, & ſic ſemper deinceps vſque ad vltimum
<
lb
/>
XF (duplicatæ enim ſunt talium cylindrorum rationes
<
lb
/>
earum, quas inter ſe habent diametri æqualibus exceſsibus
<
lb
/>
differentes circulorum, qui ſunt ſectiones coni, & baſes cy
<
lb
/>
lindrorum, ex quibus conſtat figura cono EDF circum
<
lb
/>
ſcripta, ſumpta progreſſione proportionum eodem ordine
<
lb
/>
gradatim à minima diametro vſque ad maximam EF) ita
<
lb
/>
erit cylindrorum deficientium, ex quibus conſtat figura
<
lb
/>
circumſcripta reliquo cylindri AF, dempto ABC hemi
<
lb
/>
ſphærio, minimi, cuius axis DL ad ſecundum minor pro
<
lb
/>
portio, quàm ſecundi ad tertium, & ſic deinceps, vſque ad
<
lb
/>
<
expan
abbr
="
maximũ
">maximum</
expan
>
XF, communiter ad conum EDF, & prædictum
<
lb
/>
reſiduum pertinentem, ſicut & eorum baſes circuli deficien
<
lb
/>
tes, quæ ſunt dicti reſidui ſectiones. </
s
>
<
s
>Cum igitur tam maxi
<
lb
/>
mi cylindri XF communis, quàm binorum quorumque reli
<
lb
/>
quorum cylindrorum circa conum EDF, & prædictum reſi
<
lb
/>
duum inter eadem plana parallela conſiſtentium, quorum
<
lb
/>
axis communis in BD, commune centrum grauitatis in axe
<
lb
/>
BD exiſtat, erit ex antecedenti punctum K, quod pono
<
lb
/>
centrum grauitatis coni EDF, idem reſidui ex cylindro
<
lb
/>
AF, dempto ABC, hemiſphærio centrum grauitatis.
<
lb
/>
</
s
>
<
s
>Quoniam igitur quarum partium eſt octo axis BD talium
<
lb
/>
eſt BG quinque, & BK duarum (ponimus enim nunc K
<
lb
/>
coni EDF centrum grauitatis) qualium eſt BD octo, ta
<
lb
/>
lium erit GK trium: ſed KH eſt æqualis BK; qualium
<
lb
/>
igitur partium eſt GK trium, talium erit KH duarum, ta
<
lb
/>
liſque vna GH; dupla igitur KH ipſius GH: ſed ABC
<
lb
/>
hemiſphærium duplum eſt prædicti reſidui, cum ſit cylin
<
lb
/>
dri AF, ſubſeſquialterum; vt igitur eſt
<
expan
abbr
="
hemiſphæriũ
">hemiſphærium</
expan
>
ABC,
<
lb
/>
ad prædictum reſiduum, ita ex contraria parte erit
<
expan
abbr
="
lõgitudo
">longitudo</
expan
>
<
lb
/>
KH, adlongitudinem GH: ſed H eſt centrum grauitatis
<
lb
/>
totius cylindri AF & K, prædicti reſidui dempto ABC
<
lb
/>
hemiſphærio; ergo ABC hemiſphærij centrum grauitatis
<
lb
/>
erit G. </
s
>
<
s
>Quod demonſtrandum erat. </
s
>
</
p
>
</
chap
>
</
body
>
</
text
>
</
archimedes
>