Bernoulli, Daniel, Hydrodynamica, sive De viribus et motibus fluidorum commentarii

Table of Notes

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204190HYDRODYNAMICÆ cæ indirectis; placet tamen hujus rei demonſtrationem dare ex natura vectis
petitam, quia mechanici eo omnia reducere amant.
Helicem conſiderabimus a 1 b ex figura quinquageſima ſecunda ſeor-
ſim deſumtam, ad evitandam linearum confuſionem, conſervatis denomi-
nationibus art.
IV. adhibitis. Sic igitur in Figura 53. erit rurſus angulus
11Fig. 53. N M G angulus quem facit nucleus cum horizonte, cujus ſinus = N, ſi-
nusque anguli a M H = n;
a 1 b eſt una ſpiralis circumvolutio: baſis nuclei
eſt circulus a c M p a;
ſinus anguli p a l eſt ut ante = m, ejusque coſinus M;
puncta vero l & o ſunt extremitates aquæ in ſpirali quieſcentis & in ea-
dem altitudine ab horizonte poſita, ex iſtis punctis ductæ ſunt ad periphe-
riam baſis rectæ l c &
o p ad baſin perpendiculares. In parte helicis quam
aqua occupat ſumta ſunt duo puncta infinite propinqua m &
n & per hæc du-
ctæ ſunt rectæ n f &
m g rurſus ad baſin perpendiculares. Denique ex pun-
ctis c, f, g, p ductæ ſunt ad diametrum a M perpendiculares c d, f h, g i &

p q;
atque centrum baſis ponitur in e, radiusque e a = 1. Sit jam arcus
ſpiralis l 1 o aqua plenus = c &
conſequenter arcus circularis eidem reſpon-
dens c M p = M c;
a l = e; a c = M e; a d (ſeu ſinus verſus arcus ac) = f;
a q = g;
pondus aquæ in l s o = p: arcus a l n = x; n m = d x; a c f = M x;
f g = M d x;
a b = y; h i = d y; h f = √2y - yy, erit pondus guttulæ in
nm = {p d x/c};
ſi vero linea h f multiplicetur per ſinum anguli a M H, divida-
turque per ſinum totum, habetur vectis quo particula n m cochleam circum-
agere tentat:
eſtigitur vectis iſte = n √ (2y - yy) qui multiplicatus per præ-
fatum guttulæ pondus {p d x/c} dat ejusdem momentum {n p d x/c} √ (2y - y y)}.

Sed ex natura circuli eſt M d x = {dy√ (2y - yy):
hoc igitur valore ſubſtituto
pro d x, fit idem guttulæ n m momentum = {n p d y/M c}, cujus integralis, ſub-
tracta debita conſtante, eſt {n p (y - f)/Mc}, denotatque momentum aquæ in ar-
cu l n;
hinc igitur momentum omnis aquæ in l 1 o eſt = {n p (g - f)/Mc}: quod
diviſum per vectem potentiæ in f applicatæ ſeu per 1 relinquit potentiam
iſtam quæſitam pariter = {n p (g - f)/Mc}.
Q. E. I.

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