Casati, Paolo, Fabrica, et uso del compasso di proportione, dove insegna à gli artefici il modo di fare in esso le necessarie divisioni, e con varij problemi ...

Table of figures

< >
[Figure 51]
Page: 185
[Figure 52]
Page: 185
[Figure 53]
Page: 188
[Figure 54]
Page: 190
[Figure 55]
Page: 192
[Figure 56]
Page: 198
[Figure 57]
Page: 199
[Figure 58]
Page: 200
[Figure 59]
Page: 203
[Figure 60]
Page: 207
[Figure 61]
Page: 211
[Figure 62]
Page: 213
[Figure 63]
Page: 219
[Figure 64]
Page: 221
[Figure 65]
Page: 224
[Figure 66]
Page: 226
[Figure 67]
Page: 242
[Figure 68]
Page: 242
[Figure 69]
Page: 254
[Figure 70]
Page: 255
[Figure 71]
Page: 260
[Figure 72]
Page: 263
[Figure 73]
Page: 267
[Figure 74]
Page: 268
[Figure 75]
Page: 272
< >
page |< < (197) of 279 > >|
    <echo version="1.0RC">
      <text xml:lang="it" type="free">
        <div xml:id="echoid-div119" type="section" level="1" n="63">
          <p>
            <s xml:id="echoid-s3796" xml:space="preserve">
              <pb o="197" file="0215" n="219" rhead="Linea de’Poligoni"/>
            con tal’interuallo dall’ eſtremità A, & </s>
            <s xml:id="echoid-s3797" xml:space="preserve">B della linea data ſi de-
              <lb/>
              <figure xlink:label="fig-0215-01" xlink:href="fig-0215-01a" number="63">
                <image file="0215-01" xlink:href="http://echo.mpiwg-berlin.mpg.de/zogilib?fn=/permanent/library/xxxxxxxx/figures/0215-01"/>
              </figure>
            ſcriuano due archetti, che ſi tagliano
              <lb/>
            in C, e con quello ſteſſo interuallo dal
              <lb/>
            centro C ſi deſcriua il circolo ABD-
              <lb/>
            EF, nel quale replicata la linea A B,
              <lb/>
            s’haurà il pentagono cercato.</s>
            <s xml:id="echoid-s3798" xml:space="preserve"/>
          </p>
          <p>
            <s xml:id="echoid-s3799" xml:space="preserve">Che ſeſolo ſicercaſſe di far’vn’ an-
              <lb/>
            golo del Pentagono all’ eſtremità A
              <lb/>
            della linea data, trouato come prima
              <lb/>
            il centro C, baſterà deſcriuere occul-
              <lb/>
            tamente l’arco A F, & </s>
            <s xml:id="echoid-s3800" xml:space="preserve">ad eſſo applicare la linea A B, ſiche ſra
              <lb/>
            la retta A F, e ſarà fatto l’angolo BAF del pentagono. </s>
            <s xml:id="echoid-s3801" xml:space="preserve">Il che
              <lb/>
            è vn pran compendio d’operare per chi hà da far in grande il
              <lb/>
            diſſegno d’vna fortezza regolare.</s>
            <s xml:id="echoid-s3802" xml:space="preserve"/>
          </p>
          <p>
            <s xml:id="echoid-s3803" xml:space="preserve">Quindi è, che ſe la linea data foſſe molto grande, in modo,
              <lb/>
            che non ſi poteſſe prender tutta col Compaſſo, ò non capiſſe
              <lb/>
            nell’interuallo dello Stromento, baſterà ſolo pigliarne vna
              <lb/>
            parte nell’eſtremità, qualunque ella ſia ad arbitrio, ò ſia ali-
              <lb/>
            quota, ò nò, e con quella far l angolo deſiderato del poligo-
              <lb/>
            no, nel modo che s’è detto: </s>
            <s xml:id="echoid-s3804" xml:space="preserve">perche allongata poi queſta linea
              <lb/>
            tirata per far l’angolo, ſinche ſia tanto quanto la prima, fatto
              <lb/>
            nella ſua eſtremità vn angolo vguale al già trouato, e co-
              <lb/>
            sì di mano in mano verrà à compirſi la figura bramata. </s>
            <s xml:id="echoid-s3805" xml:space="preserve">Co-
              <lb/>
            me per eſſempio, ſe c’imaginiamo la linea A B prolongata
              <lb/>
            alla lunghezza di quattro palmi, queſta non può tutta capire
              <lb/>
            nello Stromento: </s>
            <s xml:id="echoid-s3806" xml:space="preserve">perciò ne prendo ſolo la parte A B, e come
              <lb/>
            ſe con quella ſola doueſſi operare, quella applico nello Stro-
              <lb/>
            mento, & </s>
            <s xml:id="echoid-s3807" xml:space="preserve">opero come s’è detto: </s>
            <s xml:id="echoid-s3808" xml:space="preserve">poiche prolongata poi A F
              <lb/>
            tanto ch’anch’ella ſia di quattro palmi, nella ſua eſtremità fac-
              <lb/>
            cio vn’altr’angolo vguale all’ angolo BAF, e così di mano in
              <lb/>
            mano ſin che ſia compita la figura.</s>
            <s xml:id="echoid-s3809" xml:space="preserve"/>
          </p>
        </div>
      </text>
    </echo>
Impressum