Gravesande, Willem Jacob 's
,
An essay on perspective
Text
Text Image
Image
XML
Thumbnail overview
Document information
None
Concordance
Notes
Handwritten
Figures
Content
Thumbnails
page
|<
<
(120)
of 237
>
>|
<
echo
version
="
1.0RC
">
<
text
xml:lang
="
en
"
type
="
free
">
<
div
xml:id
="
echoid-div394
"
type
="
section
"
level
="
1
"
n
="
211
">
<
pb
o
="
120
"
file
="
0196
"
n
="
225
"
rhead
="
An ESSAY, &c.
"/>
</
div
>
<
div
xml:id
="
echoid-div396
"
type
="
section
"
level
="
1
"
n
="
212
">
<
head
xml:id
="
echoid-head232
"
style
="
it
"
xml:space
="
preserve
">A Demonſtration of the Inclination of the Looking-
<
lb
/>
Glaſs.</
head
>
<
p
>
<
s
xml:id
="
echoid-s2597
"
xml:space
="
preserve
">48. </
s
>
<
s
xml:id
="
echoid-s2598
"
xml:space
="
preserve
">Let A B be a Ray, proceeding from ſome
<
lb
/>
<
note
position
="
left
"
xlink:label
="
note-0196-01
"
xlink:href
="
note-0196-01a
"
xml:space
="
preserve
">Fig, 75.</
note
>
Point of an Object. </
s
>
<
s
xml:id
="
echoid-s2599
"
xml:space
="
preserve
">We are to demonſtrate,
<
note
symbol
="
*
"
position
="
left
"
xlink:label
="
note-0196-02
"
xlink:href
="
note-0196-02a
"
xml:space
="
preserve
">19.</
note
>
if the Line D I hath the Inclination given to a
<
lb
/>
Picture, and the Looking-Glaſs G H hath the In-
<
lb
/>
clination we have preſcribed, that the Angle
<
lb
/>
B a F, will be equal to the Angle B C D. </
s
>
<
s
xml:id
="
echoid-s2600
"
xml:space
="
preserve
">Now to
<
lb
/>
prove this, draw the Line F I parallel to the Ho-
<
lb
/>
rizon, then the two Angles I D F and D F I, of
<
lb
/>
the Triangle I D F, are together equal to the
<
lb
/>
Angle D I E; </
s
>
<
s
xml:id
="
echoid-s2601
"
xml:space
="
preserve
">but the Angle D F I, which is the
<
lb
/>
Inclination of the Looking-Glaſs, is equal
<
note
symbol
="
*
"
position
="
left
"
xlink:label
="
note-0196-03
"
xlink:href
="
note-0196-03a
"
xml:space
="
preserve
">16. 47.</
note
>
half the Angle D I E, leſs half the Angle I F a;
<
lb
/>
</
s
>
<
s
xml:id
="
echoid-s2602
"
xml:space
="
preserve
">and conſequently it is leſs than the Angle F D I,
<
lb
/>
by the Quantity of the whole Angle I F a: </
s
>
<
s
xml:id
="
echoid-s2603
"
xml:space
="
preserve
">
<
lb
/>
Therefore if the Angle I F a be added to the An-
<
lb
/>
gle D F I, we ſhall have the Angle D F a, equal
<
lb
/>
to the Angle F D I: </
s
>
<
s
xml:id
="
echoid-s2604
"
xml:space
="
preserve
">Therefore the Angle
<
lb
/>
Fa B will be likewiſe equal to the Angle BCD.</
s
>
<
s
xml:id
="
echoid-s2605
"
xml:space
="
preserve
">
<
note
symbol
="
*
"
position
="
left
"
xlink:label
="
note-0196-04
"
xlink:href
="
note-0196-04a
"
xml:space
="
preserve
">19.</
note
>
Which was to he demonſtrated.</
s
>
<
s
xml:id
="
echoid-s2606
"
xml:space
="
preserve
"/>
</
p
>
<
p
>
<
s
xml:id
="
echoid-s2607
"
xml:space
="
preserve
">In reaſoning nearly after the ſame Manner,
<
lb
/>
we demonſtrated what is mentioned
<
note
symbol
="
*
"
position
="
left
"
xlink:label
="
note-0196-05
"
xlink:href
="
note-0196-05a
"
xml:space
="
preserve
">47.</
note
>
ning the Inclination of the Mirrour, when the
<
lb
/>
Box is inclin’d a little backwards.</
s
>
<
s
xml:id
="
echoid-s2608
"
xml:space
="
preserve
"/>
</
p
>
</
div
>
<
div
xml:id
="
echoid-div399
"
type
="
section
"
level
="
1
"
n
="
213
">
<
head
xml:id
="
echoid-head233
"
xml:space
="
preserve
">FINIS.</
head
>
<
figure
number
="
73
">
<
image
file
="
0196-01
"
xlink:href
="
http://echo.mpiwg-berlin.mpg.de/zogilib?fn=/permanent/library/xxxxxxxx/figures/0196-01
"/>
</
figure
>
</
div
>
</
text
>
</
echo
>