Huygens, Christiaan, Christiani Hugenii opera varia; Bd. 2: Opera geometrica. Opera astronomica. Varia de optica

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[217] Pg. 700TAB. LIII.4 3 2 1 Annu Sat. lus
[218] 4 3 2 1 Jup.
[219] Luna Tellus
[220] Pag. 704.TAB. LIV.Fig. 1.Satu@@i. Jovis. Martis. Telluris. veneris. M@rc. ♎ Sol. ♈ VS
[221] Fig. 2Saturnus. Tellus. Luna. A C D R S K M G H T V N L Q Y P E F B
[222] Pag. 712.TAB. LV.Fig. 1.Sol.Sat.Jup.MarsTellusVenusMerc.
[223] Fig. 2.D A C B E
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[234] pag. 776.Tab. lvi.Fig. 1.B H V C K E T D F X P Z Q I Y O R S A
[235] Fig. 2.D S Y A d I M N d X D O Z B M E C R
[236] Fig. 3.Y T V A M N Z B E C R
[237] Fig. 4.L A M F H N G E D K B C
[238] Fig. 5.h A P O R Q G F D Z H E K L C B M
[239] Fig. 6.D A P r N O e Q K I V F H C L B M
[240] Fig. 7.C B C D A A
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234501GEOMET. VARIA. atque A F, F B, hoc eſt x & y. Nempe ſi in æquatione
propoſita pro x ſubſtituatur ubique x + e, &
pro y, ubique
y + {ey/z}, debebit æquatio hinc formata terminos omnes ha-
bere æquales nihilo;
hoc eſt
x3 + [3exx] + 3eex + e3, + y3 + [{3ey3/z}] + {3eey3/zz} + {e3y3/z3} = 0.
- axy - [aey] - [{aeyx/z}] - {aeey/z}
In hac autem æquatione conſtat neceſſario terminos prio-
ris æquationis, ex qua formata eſt, contineri debere, nem-
pe x3 + y3 - axy:
qui cum ſint æquales nihilo ex proprie-
tate curvæ, idcirco his in æquatione deletis, neceſſe eſt etiam
reliquos nihilo æquari, in quibus ſingulis manifeſtum quoque
eſt vel unum e vel plura reperiri, ideoque omnes per e divi-
di poſſe.
Qui autem poſt hanc diviſionem non amplius ha-
bebunt e, eos, neglectis reliquis, ſcio nihilo æquari debe-
re, quantitatemque lineæ z ſive F E oſtenſuros;
ſi nempe
B E jam tanquam tangens conſideretur, ideoque F G, ſeu
e, infinitè parva.
Nam termini in quibus adhuc e ſupereſt,
etiam quantitates infinite parvas ſive omnino evaneſcentes
continebunt.
Et his quidem hactenus Fermatianæ regulæ
origo ac ratio declaratur:
nunc porro oſtendemus quomodo
eadem ad tantam brevitatem perducta ſit.
Video itaque ex
æquatione totâ noviſſimâ, tantum eos terminos ſeribi neceſ-
ſe eſſe quibus ineſt e ſimplex, velut hic 3exx + {3ey3/z} - aey -
{aeyx/z} = 0.
Qui termini quomodo facili negotio ex datis æqua-
tionis terminis x3 + y3 - axy = 0, deſcribi poſſint, dein-
ceps explicandum.
Et primò quidem apparet 3exx +
{3ey3/z} nihil aliud eſſe quam ſecundos terminos cuborum

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