Vitruvius, I Dieci Libri dell' Architettvra di M. Vitrvvio, 1556

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        <div xml:id="echoid-div687" type="section" level="1" n="120">
          <p style="it">
            <s xml:id="echoid-s20226" xml:space="preserve">
              <pb o="237" file="0247" n="256" rhead="NONO."/>
            imaginatione e il fondamẽto di tutti gli horologi, & </s>
            <s xml:id="echoid-s20227" xml:space="preserve">cirappreſenta il Cielo la terra, & </s>
            <s xml:id="echoid-s20228" xml:space="preserve">tutte le diuiſioni, ſecõdo che il Sole d’hora in hora com
              <lb/>
            parte gli ſpatij delle predette ſoperficie, e piani, ne i quali ſi poſſono formare tutti gli horologi, perche l’Orizonte ci da la ſoperficie piana, la
              <lb/>
            dritta, ci da la ſoperficie delle torri, & </s>
            <s xml:id="echoid-s20229" xml:space="preserve">de muri, doue ſi fanno gli horologi, l’Equinottiale ci da una ſoperficie attrauerſata, & </s>
            <s xml:id="echoid-s20230" xml:space="preserve">leuata ſecondo
              <lb/>
            l’altezza dello Equinottiale, & </s>
            <s xml:id="echoid-s20231" xml:space="preserve">i dodici circoli ſono per li partimenti delle 24 hore del giorno in ciaſcuna ſoperficie, doue auuertir ſi deue, che
              <lb/>
            ſe la ſoperficie Equinottiale e fatta mobile di modo, che la ſi poſſa alzare, & </s>
            <s xml:id="echoid-s20232" xml:space="preserve">abbaſſare, ſecondo diuerſe eleuationi, ſopra eſſa ſi fa l’horologio
              <lb/>
            uniuerſale, alzaſi ſopra una quarta di circolo diuiſa in parti 90. </s>
            <s xml:id="echoid-s20233" xml:space="preserve">& </s>
            <s xml:id="echoid-s20234" xml:space="preserve">fermata in una di quelle parti, allaquale ſi alza ſecondo la eleuatione Me-
              <lb/>
            ridiana del Sole Equinottiale, auuertendo quanto ella ſi leua nel paeſe doue uolemo adoperar l’horologio. </s>
            <s xml:id="echoid-s20235" xml:space="preserve">Queſta ſoperficie (come ho detto)
              <lb/>
            e ſempre partita in 24 parti eguali di modo, che quanto al compartimento ella non ſi muta mai, & </s>
            <s xml:id="echoid-s20236" xml:space="preserve">ė la regola delle altre ſoperficie, lequali ſo-
              <lb/>
            no nella sſera dritta, da i predetti 12 circoli horarij egualmente in parti 24 diuiſi, ma ſe gli Orizonti ſono obliqui tanto piu ſono quegli ſpa-
              <lb/>
            cij diſſeguali, quanto piu le regioni s’allontanano dallo Equinottiale, & </s>
            <s xml:id="echoid-s20237" xml:space="preserve">quella linea doue concorrono tutte le predette ſoperficie, e detta linea
              <lb/>
              <note position="left" xlink:label="note-0247-01" xlink:href="note-0247-01a" xml:space="preserve">10</note>
            della contingentia, ò linea del toccamento, ma che la ſoperficie Equinottiale ſia regola di tutte le diuiſioni dell’ altre ſi uede in queſto modo.
              <lb/>
            </s>
            <s xml:id="echoid-s20238" xml:space="preserve">Facciaſi la quarta parte di un circolo, & </s>
            <s xml:id="echoid-s20239" xml:space="preserve">ſia quella a b c. </s>
            <s xml:id="echoid-s20240" xml:space="preserve">la linea a b. </s>
            <s xml:id="echoid-s20241" xml:space="preserve">rappreſenta lo Orizonte, la linea a c. </s>
            <s xml:id="echoid-s20242" xml:space="preserve">il dritto a d. </s>
            <s xml:id="echoid-s20243" xml:space="preserve">lo Equinottiale eleua
              <lb/>
            to à 45 gradi ſecondo la eleuatione di Venetia. </s>
            <s xml:id="echoid-s20244" xml:space="preserve">K o f. </s>
            <s xml:id="echoid-s20245" xml:space="preserve">lo aſſe del mondo che ad anguli dritti taglia lo Equinottiale. </s>
            <s xml:id="echoid-s20246" xml:space="preserve">Queſto quadrante ci ſer-
              <lb/>
            uera à quel fondamento de gli horologi, che uolemo fare, in queſto modo, come dice il Munstero. </s>
            <s xml:id="echoid-s20247" xml:space="preserve">Fa un circolo non molto grande, & </s>
            <s xml:id="echoid-s20248" xml:space="preserve">con due
              <lb/>
            diametri lo partir ai in quattro parti equali, ſia b t. </s>
            <s xml:id="echoid-s20249" xml:space="preserve">il diametro perpendiculare, & </s>
            <s xml:id="echoid-s20250" xml:space="preserve">a q. </s>
            <s xml:id="echoid-s20251" xml:space="preserve">il Diametro trauerſo, che taglia ad anguli giuſti la li-
              <lb/>
            nea b.</s>
            <s xml:id="echoid-s20252" xml:space="preserve">t. </s>
            <s xml:id="echoid-s20253" xml:space="preserve">partirai la quarta q t. </s>
            <s xml:id="echoid-s20254" xml:space="preserve">in ſei in ſei parti eguali con occulti punti, & </s>
            <s xml:id="echoid-s20255" xml:space="preserve">pigliato lo ſpatio d’una parte con la ſeſta ripportela di quà, & </s>
            <s xml:id="echoid-s20256" xml:space="preserve">di là dal
              <lb/>
            punto t. </s>
            <s xml:id="echoid-s20257" xml:space="preserve">benche io piglierei la diſtanza dal quadrato, quella che è dal centro a al punto o. </s>
            <s xml:id="echoid-s20258" xml:space="preserve">& </s>
            <s xml:id="echoid-s20259" xml:space="preserve">ſia ſegnato, m dalla ſinistra, & </s>
            <s xml:id="echoid-s20260" xml:space="preserve">l. </s>
            <s xml:id="echoid-s20261" xml:space="preserve">dalla deſtra, il
              <lb/>
            medeſimo ſi fara di quà, & </s>
            <s xml:id="echoid-s20262" xml:space="preserve">di là dal punto o. </s>
            <s xml:id="echoid-s20263" xml:space="preserve">ſegnando con le lettere k.</s>
            <s xml:id="echoid-s20264" xml:space="preserve">n. </s>
            <s xml:id="echoid-s20265" xml:space="preserve">è tirando dal l. </s>
            <s xml:id="echoid-s20266" xml:space="preserve">al K. </s>
            <s xml:id="echoid-s20267" xml:space="preserve">& </s>
            <s xml:id="echoid-s20268" xml:space="preserve">dal m. </s>
            <s xml:id="echoid-s20269" xml:space="preserve">all’n. </s>
            <s xml:id="echoid-s20270" xml:space="preserve">due linee manifeſte, paralelle al
              <lb/>
            Diametro b t. </s>
            <s xml:id="echoid-s20271" xml:space="preserve">Oltra di queſto partirai la quarta a t. </s>
            <s xml:id="echoid-s20272" xml:space="preserve">in 90 parti, & </s>
            <s xml:id="echoid-s20273" xml:space="preserve">numera la eleuatione dello Equinottiale dal punto a uerſo’lt. </s>
            <s xml:id="echoid-s20274" xml:space="preserve">e tira una
              <lb/>
            linea dritta dal centro c al ſuo termine, & </s>
            <s xml:id="echoid-s20275" xml:space="preserve">doue quella linea taglia la linea l K. </s>
            <s xml:id="echoid-s20276" xml:space="preserve">ui imponerai la letterad. </s>
            <s xml:id="echoid-s20277" xml:space="preserve">Similmente numera dall’a uer-
              <lb/>
              <note position="left" xlink:label="note-0247-02" xlink:href="note-0247-02a" xml:space="preserve">20</note>
            ſo il b. </s>
            <s xml:id="echoid-s20278" xml:space="preserve">la eleuatione del Polo, & </s>
            <s xml:id="echoid-s20279" xml:space="preserve">doue la linea tirata dal centro c, al termine della eleuatione del Polo taglia la linea l K. </s>
            <s xml:id="echoid-s20280" xml:space="preserve">ſegna e. </s>
            <s xml:id="echoid-s20281" xml:space="preserve">Dapoi ſopra
              <lb/>
            il centro c fa un circolo, & </s>
            <s xml:id="echoid-s20282" xml:space="preserve">lo partir ai in 24 parti eguali, & </s>
            <s xml:id="echoid-s20283" xml:space="preserve">tira dal centro linee, che poi le posſi leuare per quelle parti di quà, & </s>
            <s xml:id="echoid-s20284" xml:space="preserve">di là alle
              <lb/>
            linee m n. </s>
            <s xml:id="echoid-s20285" xml:space="preserve">l K. </s>
            <s xml:id="echoid-s20286" xml:space="preserve">e da ciaſcun punto della linea m n. </s>
            <s xml:id="echoid-s20287" xml:space="preserve">tira le linee delle hore riſpondenti à i punti nella linea l K. </s>
            <s xml:id="echoid-s20288" xml:space="preserve">Oltra di queſto doue il Diametro
              <lb/>
            a q. </s>
            <s xml:id="echoid-s20289" xml:space="preserve">taglia la linea l K. </s>
            <s xml:id="echoid-s20290" xml:space="preserve">fa il punto f. </s>
            <s xml:id="echoid-s20291" xml:space="preserve">doue taglia la linea m n. </s>
            <s xml:id="echoid-s20292" xml:space="preserve">fa il punto h. </s>
            <s xml:id="echoid-s20293" xml:space="preserve">quelli punti ſono delle dodici hore.</s>
            <s xml:id="echoid-s20294" xml:space="preserve"/>
          </p>
          <p style="it">
            <s xml:id="echoid-s20295" xml:space="preserve">Et fatto queſto piglia lo ſpacio c d, & </s>
            <s xml:id="echoid-s20296" xml:space="preserve">posto il piede della ſesta nel punto f. </s>
            <s xml:id="echoid-s20297" xml:space="preserve">eſteſo
              <lb/>
              <figure xlink:label="fig-0247-01" xlink:href="fig-0247-01a" number="138">
                <variables xml:id="echoid-variables59" xml:space="preserve">c k a 90 80 o 70 f 60 50 d 45 40 30 20 b 10 9 5 4 c 8 7 6 t 90 80 70 60 l 7 m e 50 l’eguin. 45 40 30 8 7 6 20 4 5 6 7 8 d 9 8 10 9 10 10 9 10 11 11 11 a g f c 12 h 12 i q 1 1 1 2 2 2 3 3 4 e 3 4 5 5 8 7 6 6 4 45 ilpolo k 5 6 n</variables>
              </figure>
            l’altro uerſo l’a. </s>
            <s xml:id="echoid-s20298" xml:space="preserve">far ai la nota g. </s>
            <s xml:id="echoid-s20299" xml:space="preserve">benche quella diſtanza io la piglierei dal quadrãte
              <lb/>
            dal centro a. </s>
            <s xml:id="echoid-s20300" xml:space="preserve">al punto f. </s>
            <s xml:id="echoid-s20301" xml:space="preserve">con ſimile ragione trapporta lo ſpacio c. </s>
            <s xml:id="echoid-s20302" xml:space="preserve">e dallo huerſo’l
              <lb/>
            q. </s>
            <s xml:id="echoid-s20303" xml:space="preserve">& </s>
            <s xml:id="echoid-s20304" xml:space="preserve">nell’ eſtremo fa il punto.</s>
            <s xml:id="echoid-s20305" xml:space="preserve">i. </s>
            <s xml:id="echoid-s20306" xml:space="preserve">et ancho queſto ſpacio io lo piglierei dal quadrante
              <lb/>
            dal cẽtro a al punto K. </s>
            <s xml:id="echoid-s20307" xml:space="preserve">benche nella eleuatione di gradi 45 lo ſpacio a K. </s>
            <s xml:id="echoid-s20308" xml:space="preserve">ſia equa-
              <lb/>
            le allo ſpacio a f. </s>
            <s xml:id="echoid-s20309" xml:space="preserve">perche i Diametri di due ſuperficie, cioè della Orizõtale, & </s>
            <s xml:id="echoid-s20310" xml:space="preserve">della
              <lb/>
              <note position="left" xlink:label="note-0247-03" xlink:href="note-0247-03a" xml:space="preserve">30</note>
            Verticale, ſono eguali, ilche non aduiene in minore, ò in maggiore eleuatione, Ti-
              <lb/>
            ra poi una linea dritta per lo punto g. </s>
            <s xml:id="echoid-s20311" xml:space="preserve">par alella alla linea l K. </s>
            <s xml:id="echoid-s20312" xml:space="preserve">& </s>
            <s xml:id="echoid-s20313" xml:space="preserve">coſi per lo punto
              <lb/>
            i, tirerai un’altra linea paralella alla m n. </s>
            <s xml:id="echoid-s20314" xml:space="preserve">& </s>
            <s xml:id="echoid-s20315" xml:space="preserve">fatto questo fa un circolo ſopra il cen
              <lb/>
            tro i, & </s>
            <s xml:id="echoid-s20316" xml:space="preserve">un’altro ſopra il centro g. </s>
            <s xml:id="echoid-s20317" xml:space="preserve">di quella diſtanza, che è dallo i all’h. </s>
            <s xml:id="echoid-s20318" xml:space="preserve">& </s>
            <s xml:id="echoid-s20319" xml:space="preserve">dal g.
              <lb/>
            </s>
            <s xml:id="echoid-s20320" xml:space="preserve">all’f. </s>
            <s xml:id="echoid-s20321" xml:space="preserve">& </s>
            <s xml:id="echoid-s20322" xml:space="preserve">da gli ſtesſi centri tira le linee
              <lb/>
            à i pũti ſegnati nelle linee K l. </s>
            <s xml:id="echoid-s20323" xml:space="preserve">& </s>
            <s xml:id="echoid-s20324" xml:space="preserve">m n. </s>
            <s xml:id="echoid-s20325" xml:space="preserve">
              <lb/>
            & </s>
            <s xml:id="echoid-s20326" xml:space="preserve">nota i numeri delle hore come uedi
              <lb/>
            nella figura diſſegnata, & </s>
            <s xml:id="echoid-s20327" xml:space="preserve">coſi hauerai
              <lb/>
            due horologi, uno orizõtale, che é quel
              <lb/>
            lo, che ha il centro g. </s>
            <s xml:id="echoid-s20328" xml:space="preserve">& </s>
            <s xml:id="echoid-s20329" xml:space="preserve">l’altro dal mu
              <lb/>
              <note position="left" xlink:label="note-0247-04" xlink:href="note-0247-04a" xml:space="preserve">40</note>
            ro, che è quello, che ha il centro i. </s>
            <s xml:id="echoid-s20330" xml:space="preserve">& </s>
            <s xml:id="echoid-s20331" xml:space="preserve">
              <lb/>
            quello dal muro, nõ può hauer piu che
              <lb/>
            dodici hore, perche il muro taglia il ue
              <lb/>
            ro Leuante, & </s>
            <s xml:id="echoid-s20332" xml:space="preserve">il uero Ponente, quan-
              <lb/>
            do egli ė uolto al mezzodì, et il Sole la
              <lb/>
            ſtate naſce nella quarta tra Leuãte, e
              <lb/>
            Trãmontana, & </s>
            <s xml:id="echoid-s20333" xml:space="preserve">ſi corca nella quarta
              <lb/>
            tra Ponente è trãmontana, & </s>
            <s xml:id="echoid-s20334" xml:space="preserve">pero il
              <lb/>
            reſtante dello horologio ſi ſegna nel-
              <lb/>
            la facciata uolta alla Trammontana
              <lb/>
              <note position="left" xlink:label="note-0247-05" xlink:href="note-0247-05a" xml:space="preserve">50</note>
            che ſono alcune hore la mattina auan
              <lb/>
            ti le ſei, & </s>
            <s xml:id="echoid-s20335" xml:space="preserve">alcune la ſera dopo le ſei,
              <lb/>
            come dimoſtra la figura c. </s>
            <s xml:id="echoid-s20336" xml:space="preserve">Ma quan-
              <lb/>
            to hauemo detto delle tre ſoperficie,
              <lb/>
            & </s>
            <s xml:id="echoid-s20337" xml:space="preserve">de i circoli delle hore, & </s>
            <s xml:id="echoid-s20338" xml:space="preserve">delle li-
              <lb/>
            nee del toccamento che ſono K l. </s>
            <s xml:id="echoid-s20339" xml:space="preserve">& </s>
            <s xml:id="echoid-s20340" xml:space="preserve">
              <lb/>
            m n. </s>
            <s xml:id="echoid-s20341" xml:space="preserve">ſi uede con iſperienza, quando
              <lb/>
            ſi mette al Sole drizzato al mezzo
              <lb/>
            di un’horologio fatto con tutte tre le
              <lb/>
            dette ſoperficie, imperoche l’ombra
              <lb/>
              <note position="left" xlink:label="note-0247-06" xlink:href="note-0247-06a" xml:space="preserve">60</note>
            d’un filo, che pasſi per tutti que cen-
              <lb/>
            tri dimoſtra nella linea, doue quelle ſo
              <lb/>
            perficie concorrono i circoli horari,
              <lb/>
            & </s>
            <s xml:id="echoid-s20342" xml:space="preserve">queſto auuertimẽto ce inſegna piu
              <lb/>
            che le parole.</s>
            <s xml:id="echoid-s20343" xml:space="preserve"/>
          </p>
        </div>
      </text>
    </echo>
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