Bion, Nicolas, Traité de la construction et principaux usages des instruments de mathématique, 1723

Table of Notes

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            <s xml:id="echoid-s8922" xml:space="preserve">
              <pb o="282" file="298" n="298" rhead="CONSTRUCT. ET USAGES DES INSTRUMENS"/>
            côté AB ſont des Méridiens, & </s>
            <s xml:id="echoid-s8923" xml:space="preserve">toutes celles qui ſont paralleles
              <lb/>
            an côté AC ſont des lignes Eſt & </s>
            <s xml:id="echoid-s8924" xml:space="preserve">Oüeſt.</s>
            <s xml:id="echoid-s8925" xml:space="preserve"/>
          </p>
          <p>
            <s xml:id="echoid-s8926" xml:space="preserve">Ce quart de cercle eſt diviſé premierement en 8 parties égales, par
              <lb/>
            7 raïons tirez du centre A, pour repreſenter les {8/4} de vent de chaque
              <lb/>
            quart de la Bouſſole ou de l'horiſon; </s>
            <s xml:id="echoid-s8927" xml:space="preserve">chacun de ces quarts de vent
              <lb/>
            vaut 11 d. </s>
            <s xml:id="echoid-s8928" xml:space="preserve">15 m. </s>
            <s xml:id="echoid-s8929" xml:space="preserve">comme nous avons dit ci-devant en parlant de la
              <lb/>
            Bouſſole.</s>
            <s xml:id="echoid-s8930" xml:space="preserve"/>
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          <p>
            <s xml:id="echoid-s8931" xml:space="preserve">La circonference BC eſt auſſi diviſée en 90 d. </s>
            <s xml:id="echoid-s8932" xml:space="preserve">& </s>
            <s xml:id="echoid-s8933" xml:space="preserve">chaque degré eſt
              <lb/>
            ſubdiviſé de 12 en 12 m. </s>
            <s xml:id="echoid-s8934" xml:space="preserve">par le moyen des lignes tranſverſales, ti-
              <lb/>
            rées de degré en degré, & </s>
            <s xml:id="echoid-s8935" xml:space="preserve">de 6 cercles concentriques, y compris les
              <lb/>
            2 extrêmes. </s>
            <s xml:id="echoid-s8936" xml:space="preserve">On attache de plus au centre un fil, comme AL, lequel
              <lb/>
            étant arrêté ſur tel degré que l'on veut du quart de cercle, ſert à di-
              <lb/>
            viſer l'horiſon de telle maniere qu'on trouve à propos. </s>
            <s xml:id="echoid-s8937" xml:space="preserve">La figure 20
              <lb/>
            fait aſſez connoitre le reſte de la conſtruction de cet Inſtrument.</s>
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          <head xml:id="echoid-head427" style="it" xml:space="preserve">Vſage du Luartier de réduction.</head>
          <p>
            <s xml:id="echoid-s8939" xml:space="preserve">ON forme ſur le Quartier de réduction des triangles ſemblables
              <lb/>
            à ceux de la Navigation, & </s>
            <s xml:id="echoid-s8940" xml:space="preserve">les côtez de ces triangles ſont me-
              <lb/>
            ſurez par les intervales égaux qui ſont entre les quarts de cercle & </s>
            <s xml:id="echoid-s8941" xml:space="preserve">
              <lb/>
            entre les lignes N & </s>
            <s xml:id="echoid-s8942" xml:space="preserve">S E & </s>
            <s xml:id="echoid-s8943" xml:space="preserve">O.</s>
            <s xml:id="echoid-s8944" xml:space="preserve"/>
          </p>
          <p>
            <s xml:id="echoid-s8945" xml:space="preserve">On a diſtingué ces cercles & </s>
            <s xml:id="echoid-s8946" xml:space="preserve">ces lignes en les marquant de 5 en
              <lb/>
            5 par des traits plus gros que les autres; </s>
            <s xml:id="echoid-s8947" xml:space="preserve">de ſorte que ſi l'on prend
              <lb/>
            chaque intervale pour une lieuë, il y aura 5 lieuës depuis une groſſe
              <lb/>
            ligne juſqu'à l'autre; </s>
            <s xml:id="echoid-s8948" xml:space="preserve">de même ſi on prend chaque intervale pour 4
              <lb/>
            lieuës, il y aura 20 lieuës qui ſont un degré de Marine depuis un
              <lb/>
            gros trait juſqu'à l'autre.</s>
            <s xml:id="echoid-s8949" xml:space="preserve"/>
          </p>
          <p>
            <s xml:id="echoid-s8950" xml:space="preserve">Suppoſons, par exemple, avoir couru 150 lieuës NE quart N, qui
              <lb/>
            eſt le 3
              <emph style="sub">me</emph>
            quart de vent, faiſant depuis le Nord un angle de 33 d. </s>
            <s xml:id="echoid-s8951" xml:space="preserve">45
              <lb/>
            m. </s>
            <s xml:id="echoid-s8952" xml:space="preserve">Nous avons donc 2 choſes connuës; </s>
            <s xml:id="echoid-s8953" xml:space="preserve">ſçavoir, le rumb de vent & </s>
            <s xml:id="echoid-s8954" xml:space="preserve">
              <lb/>
            les lieuës de diſtance, par le moyen deſquelles on peut former ſur le
              <lb/>
            quartier de réduction un triangle ſemblable à celui de Navigation
              <lb/>
            pour trouver le reſte qui nous eſt inconnu; </s>
            <s xml:id="echoid-s8955" xml:space="preserve">ce qui ſe fait en cette
              <lb/>
            ſorte.</s>
            <s xml:id="echoid-s8956" xml:space="preserve"/>
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            <s xml:id="echoid-s8957" xml:space="preserve">On prendra le centre A pour le point du départ, & </s>
            <s xml:id="echoid-s8958" xml:space="preserve">l'on comptera
              <lb/>
            par les arcs le long du rumb de vent ſuppoſé AD, les 150 lieuës de
              <lb/>
            diſtance depuis A juſqu'à D, & </s>
            <s xml:id="echoid-s8959" xml:space="preserve">ce point D ſera le lieu de l'arrivée
              <lb/>
            lequel on marquera par une petite pointe, & </s>
            <s xml:id="echoid-s8960" xml:space="preserve">on conduira DE pa-
              <lb/>
            rallele au côté AC, pour former le triangle rectangle AED, ſembla-
              <lb/>
            ble à celui de la Navigation; </s>
            <s xml:id="echoid-s8961" xml:space="preserve">le côté AE de ce triangle donnera 125
              <lb/>
            lieuës de difference en latitude vers le Nord, qui valent 6 d. </s>
            <s xml:id="echoid-s8962" xml:space="preserve">15 m.
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            </s>
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