Gravesande, Willem Jacob 's, An essay on perspective

Table of Notes

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              <pb o="17" file="0039" n="41" rhead="on PERSPECTIVE."/>
            the Appearance of the Line A E, is a Part
              <note symbol="*" position="right" xlink:label="note-0039-01" xlink:href="note-0039-01a" xml:space="preserve">13.</note>
            the Line E D. </s>
            <s xml:id="echoid-s520" xml:space="preserve">Now, ſince the Point A is in
              <lb/>
            the two Lines A B, A E; </s>
            <s xml:id="echoid-s521" xml:space="preserve">the Appearance of
              <lb/>
            the ſaid Point will likewiſe be in the Appear-
              <lb/>
            ances of the aforeſaid two Lines, and conſequent-
              <lb/>
            ly is in the Point a, the common Section of B V
              <lb/>
            and E D.</s>
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        <div xml:id="echoid-div60" type="section" level="1" n="30">
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            <emph style="sc">Remarks</emph>
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          <p>
            <s xml:id="echoid-s523" xml:space="preserve">24. </s>
            <s xml:id="echoid-s524" xml:space="preserve">If the Diſtance of the Eye be ſo great, that
              <lb/>
            one of the Points of Diſtance cannot be deno-
              <lb/>
            ted upon the horizontal Line; </s>
            <s xml:id="echoid-s525" xml:space="preserve">another Point, F,
              <lb/>
            muſt be uſed, diſtant from the Point of Sight
              <lb/>
            by about one third, or fourth Part of the Di-
              <lb/>
            ſtance of the Eye. </s>
            <s xml:id="echoid-s526" xml:space="preserve">But then, a correſpondent
              <lb/>
            Part of the Perpendicular A B muſt be likewiſe
              <lb/>
            taken, and laid off from B to G, in the Baſe
              <lb/>
            Line.</s>
            <s xml:id="echoid-s527" xml:space="preserve"/>
          </p>
          <p>
            <s xml:id="echoid-s528" xml:space="preserve">25. </s>
            <s xml:id="echoid-s529" xml:space="preserve">And in this manner may the Repreſentation
              <lb/>
            of a very diſtant Point be found, if its Diſtance
              <lb/>
            from the Perſpective Plane be known, together
              <lb/>
            with the Place wherein a Perpendicular drawn
              <lb/>
            from that Point cuts the Baſe Line. </s>
            <s xml:id="echoid-s530" xml:space="preserve">For, having
              <lb/>
            firſt drawn a Line, as B V, from the ſaid Point
              <lb/>
            of Concurrence to the Point of Sight, then B E
              <lb/>
            muſt be aſſum’d in the Baſe Line; </s>
            <s xml:id="echoid-s531" xml:space="preserve">for Example,
              <lb/>
            equal to the tenth Part of the Diſtance of the
              <lb/>
            Point whoſe Repreſentation is ſought; </s>
            <s xml:id="echoid-s532" xml:space="preserve">and V H
              <lb/>
            in the Horizontal Line, likewiſe equal to the
              <lb/>
            tenth Part of the Eye’s Diſtance. </s>
            <s xml:id="echoid-s533" xml:space="preserve">Then C, the
              <lb/>
            Interſection of B V and E H, will be the Appear-
              <lb/>
            ance ſought.</s>
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          <p>
            <s xml:id="echoid-s535" xml:space="preserve">Note, By this Method may be found the Deep-
              <lb/>
            nings in Pictures.</s>
            <s xml:id="echoid-s536" xml:space="preserve"/>
          </p>
          <p>
            <s xml:id="echoid-s537" xml:space="preserve">The Appearance of the Point A may yet be
              <lb/>
            otherwiſe found, without drawing the Line B V
              <lb/>
            from the Point A, in taking B I equal to B </s>
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