Voltaire, Elémens de la philosophie de Neuton : mis à la portée de tout le monde

Table of handwritten notes

< >
[Handwritten note 1]
Page: 3
[Handwritten note 2]
Page: 4
[Handwritten note 3]
Page: 4
[Handwritten note 4]
Page: 4
< >
page |< < (69) of 430 > >|
    <echo version="1.0RC">
      <text xml:lang="fr" type="free">
        <div xml:id="echoid-div35" type="section" level="1" n="13">
          <p>
            <s xml:id="echoid-s915" xml:space="preserve">
              <pb o="69" file="0089" n="89" rhead="DE NEUTON."/>
            (figure ſeconde). </s>
            <s xml:id="echoid-s916" xml:space="preserve">Or l’angle qui ſe forme
              <lb/>
            dans votre rétine & </s>
            <s xml:id="echoid-s917" xml:space="preserve">dont votre rétine eſt
              <lb/>
            la baze, eſt comme l’angle dont l’objet eſt
              <lb/>
            la baze. </s>
            <s xml:id="echoid-s918" xml:space="preserve">Ce ſont des angles oppoſez au ſom-
              <lb/>
            met: </s>
            <s xml:id="echoid-s919" xml:space="preserve">donc par les premieres notions des E-
              <lb/>
            lémens de la Géométrie ils ſont égaux; </s>
            <s xml:id="echoid-s920" xml:space="preserve">donc
              <lb/>
            ſi l’angle formé dans l’œil A. </s>
            <s xml:id="echoid-s921" xml:space="preserve">eſt double de
              <lb/>
            l’angle formé dans l’œil B.</s>
            <s xml:id="echoid-s922" xml:space="preserve">, cet objet paraitra
              <lb/>
            une fois plus grand à l’œil A. </s>
            <s xml:id="echoid-s923" xml:space="preserve">qu’à l’œil B.</s>
            <s xml:id="echoid-s924" xml:space="preserve"/>
          </p>
          <p>
            <s xml:id="echoid-s925" xml:space="preserve">Maintenant pour que l’œil étant en B.
              <lb/>
            </s>
            <s xml:id="echoid-s926" xml:space="preserve">voye l’objet auſſi grand, que le voit l’œil en
              <lb/>
            A.</s>
            <s xml:id="echoid-s927" xml:space="preserve">, il faut faire en ſorte que cet œil B. </s>
            <s xml:id="echoid-s928" xml:space="preserve">re-
              <lb/>
            çoive un angle auſſi grand que celui de l’œil
              <lb/>
            A. </s>
            <s xml:id="echoid-s929" xml:space="preserve">qui eſt une fois plus près. </s>
            <s xml:id="echoid-s930" xml:space="preserve">Le
              <unsure/>
            s verres
              <lb/>
            d’un téleſcope feront cet effet.</s>
            <s xml:id="echoid-s931" xml:space="preserve"/>
          </p>
          <p>
            <s xml:id="echoid-s932" xml:space="preserve">Ne mettons ici qu’un ſeul verre pour plus
              <lb/>
            de facilité, & </s>
            <s xml:id="echoid-s933" xml:space="preserve">faiſons abſtraction des autres
              <lb/>
            effets de pluſieurs verres. </s>
            <s xml:id="echoid-s934" xml:space="preserve">L’objet H. </s>
            <s xml:id="echoid-s935" xml:space="preserve">K.
              <lb/>
            </s>
            <s xml:id="echoid-s936" xml:space="preserve">(troiſième figure) envoye ſes rayons à
              <lb/>
            ce verre. </s>
            <s xml:id="echoid-s937" xml:space="preserve">Ils ſe réuniſſent à quelque diſtance
              <lb/>
            du verre. </s>
            <s xml:id="echoid-s938" xml:space="preserve">Concevons un verre taillé de
              <lb/>
            ſorte, que ces rayons ſe croiſent pour aller
              <lb/>
            former dans l’œil en C. </s>
            <s xml:id="echoid-s939" xml:space="preserve">un angle auſſi grand
              <lb/>
            que celui de l’œil en A. </s>
            <s xml:id="echoid-s940" xml:space="preserve">alors l’œil, nous
              <lb/>
            dit-on, juge par cet angle. </s>
            <s xml:id="echoid-s941" xml:space="preserve">Il voit </s>
          </p>
        </div>
      </text>
    </echo>
Impressum