DelMonte, Guidubaldo
,
Mechanicorvm Liber
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<
s
id
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">Et ſi funis in K per alium circumuoluatur
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orbiculum, cuius centrum ſit N; qui dein
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de trochleæ inferiori religetur in O; & po
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tentia in M ſuſtineat pondus D. </
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<
s
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">dico pro
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portionem potentiæ ad pondus ſeſquiter
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tiam eſſe.
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<
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">Quoniam enim potentia in E ſuſtinens
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pondus D fune ECB AKPO ſubtripla eſt
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ipſius D, ipſius autem E dupla eſt potentia
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in H; erit potentia in H ſubſeſquialtera pon
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deris D. </
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<
s
id
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">ſimili quoq; modo quoniam po
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tentia in O, quæ eſt, ac ſi eſſet in centro or
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<
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n
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biculi ABC, ſubtripla eſt ponderis D; ip
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ſius autem O dupla eſt potentia in N; erit
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quoq; potentia in N ſubſeſquialtera ponde
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ris D. </
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>
<
s
id
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N158D6
">quare duæ ſimul potentiæ in HN pon
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dus D ſuperant tertia parte, ſe ſe habentq; ad
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D in ratione ſeſquitertia: & cùm potentia
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in M duabus ſit potentiis in HN ſimul ſum
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ptis æqualis, ſuperabit itidem potentia in
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M pondus D tertia parte. </
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>
<
s
id
="
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">ergo proportio
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potentiæ in M ad pondus D ſeſquitertia
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eſt. </
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<
s
id
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">quod demonſtrare oportebat. </
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5
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Huius.
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Ex
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15
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huius.
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3, 15,
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Huius.
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</
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<
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id
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">Si autem in M ſit potentia mouens pon
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dus, ſimili modo oſtendetur ſpatium ponderis D ſpatii potentiæ in
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M ſeſquitertium eſſe. </
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>
</
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<
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<
s
id
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">Et ſi funis in O per alium circumuoluatur orbiculum, qui tro
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chleæ ſuperiori deinde religetur; eodem modo demonſtrabimus
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proportionem potentiæ in M pondus ſuſtinentis ad pondus ſeſ
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quiquartam eſſe. </
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<
s
id
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">& ſi in M ſit potentia mouens, ſimiliter oſten
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detur ſpatium ponderis ſpatii potentiæ ſeſquiquartum eſſe. </
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>
<
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id
="
id.2.1.189.2.1.3.0
">pro
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cedendoq; hoc modo in infinitum quamcunq; proportionem
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potentiæ ad pondus ſuperparticularem inueniemus; ſemper〈qué〉 </
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