DelMonte, Guidubaldo, Mechanicorvm Liber

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1terq; exponatur cu­
neus STQ æqualis cu
neo GFEkL; erit TR
ipſi PN, & perime­
tro cylindri æqualis; &
QR æqualis GE.
cùm autem GE ma­
ior ſit AC; erit & RQ
maior MN.
ſecetur
RQ in V; fiatq; RV
ipſi MN æqualis, &
coniungatur TV; erit
triangulum TVR tri­
angulo MPN æquale:
duæ enim TR RV
duabus PN NM ſunt
æquales, & anguli,
quos continent, ſunt
æquales, nempe recti;
angulus igitur RTV
243[Figure 243]
angulo NPM æqualis erit.
quare angulus MPN minor eſt angu­
lo QTR; & horum dupli, angulus ſcilicet MPO minor angulo
QTS.
quoniam autem cuneus, qui angulum ad verticem mino
rem habet, facilius mouet, ac ſcindit, quàm qui habet maiorem;
cuneus ergo MPO facilius mouebit, quàm QTS.
facilius igitur
pondus à cuneo ADCHI mouebitur, quàm à cuneo GFEkL.

pondus ergo ſuper helicen CDA facilius mouebitur, quàm ſuper
EFG.
eodemq; modo oſtendetur, quò minor erit AC, eò faci­
lius pondus moueri.
quod demonſtrare oportebat.
1 Huius.1 Huius.4 Primi.

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