Clavius, Christoph
,
Geometria practica
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GEOMETR. PRACT.
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intueri poſsit, longitu dinem A B, venabimur. </
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<
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xml:space
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">Sinamque ex C, ad ſiniſtram,
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vel dextram procedemus, donec in D, vtrumq; </
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<
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xml:space
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">extremũ videamus, inuenietur
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tranſuerſa longitu do AB, per problema 10. </
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<
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<
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angulum rectum BCD, recedatur in latus, ſiue per angulum acutum BAD, & </
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<
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<
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xml:space
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ſine numeris inſtituenda eſt, vt in ſuperioribus.</
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<
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<
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menſor in A, exiſtens videre poteſt extremum B, inueſtigabi-
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tur longitudo AB, per problema 8.</
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<
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autem è directo longitudinis exiſtat in C, & </
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explorabitur per problema 9. </
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">eadem longitudo A B.</
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<
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">DISTANTIAM alicuius ſigni in Horizonte poſiti, à ſummitate tur-
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ris, vel muri alicuius, licet ad ipſum ſignum acceſſus non pateat, per
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quadrantem colligere.</
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Horizontis plano punctum A, diſtet à ſummi-
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102-01
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tate D, alicuius altitudinis CD, per rectam AD, quam me-
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tiri iubemur, Vbicunq; </
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">oculus menſoris exiſtat, nimirum
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in B, vt ſit ſtatura menſoris BG, inueſtigentur per proble-
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ma 6. </
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<
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<
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">Deinde angulus exploretur A B D, quem nobis præ-
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bebit Quadrãs cum dioptra, ſi ad oculum ita applicetur,
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vt eius planum per tria puncta B, A, D, tranſeat, poſito centro in B; </
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eius latus rectæ B A, incumbat, dioptra vero ad punctum D, dirigatur, & </
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B; </
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rectil.</
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<
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ratione eadem diſtantia AD, exquirenda ſit abſque numeris, do-
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cuimus Num. </
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quam per nullum ſpatium ſecundum lineam rectam accedere poſſi-
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mus, aut recedere, vt duæ ſtationes fieri poſſint, ſed ſolũ ad dextram,
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ſiniſtramue ad locum, è quo eius baſis appareat, per Quadrantem ex-
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plorare.</
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non liceat accedere, aut ab earecedere ſecundum li-
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neam rectam, ſed ſolum in latus, verbigratia vſque ad
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D, vnde baſem videre poſsimus. </
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blema 10. </
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ciatur que vertex B, ex C, per angulum ACB. </
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poſito ſinu toto A C, altitudo A B, Tangens eſt an-
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guli obſeruationis ACB, ſi fiat.</
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rectil.</
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