Clavius, Christoph, Geometria practica

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10272GEOMETR. PRACT. intueri poſsit, longitu dinem A B, venabimur. Sinamque ex C, ad ſiniſtram,
vel dextram procedemus, donec in D, vtrumq;
extremũ videamus, inuenietur
tranſuerſa longitu do AB, per problema 10.
vt prius. Neque vero refert, ſiue per
angulum rectum BCD, recedatur in latus, ſiue per angulum acutum BAD, &
c.
3. Operatio ſine numeris inſtituenda eſt, vt in ſuperioribus.
4. Qvando menſor in A, exiſtens videre poteſt extremum B, inueſtigabi-
tur longitudo AB, per problema 8.
Si autem è directo longitudinis exiſtat in C, & vtrumque etremum cernat,
explorabitur per problema 9.
eadem longitudo A B.
DISTANTIAM alicuius ſigni in Horizonte poſiti, à ſummitate tur-
ris, vel muri alicuius, licet ad ipſum ſignum acceſſus non pateat, per
quadrantem colligere.
PROBLEMA XIII.
1. In Horizontis plano punctum A, diſtet à ſummi-
37[Figure 37] tate D, alicuius altitudinis CD, per rectam AD, quam me-
tiri iubemur, Vbicunq;
oculus menſoris exiſtat, nimirum
in B, vt ſit ſtatura menſoris BG, inueſtigentur per proble-
ma 6.
diſtantiæ punctorum A, D, ab oculo menſoris B.
Deinde angulus exploretur A B D, quem nobis præ-
bebit Quadrãs cum dioptra, ſi ad oculum ita applicetur,
vt eius planum per tria puncta B, A, D, tranſeat, poſito centro in B;
atque vnum
eius latus rectæ B A, incumbat, dioptra vero ad punctum D, dirigatur, &
c. Itaq;
cum in triangulo B A D, duo latera nota B A, B D, angulum notum contineant
B;
cognoſcetur quo que latus AD.
1110. triang.
rectil.
2. Qva ratione eadem diſtantia AD, exquirenda ſit abſque numeris, do-
cuimus Num.
5. problematis 7.
ALTITVDINEM inacceſſibilem, cuius baſis non videatur, & ad
quam per nullum ſpatium ſecundum lineam rectam accedere poſſi-
mus, aut recedere, vt duæ ſtationes fieri poſſint, ſed ſolũ ad dextram,
ſiniſtramue ad locum, è quo eius baſis appareat, per Quadrantem ex-
plorare.
PROBLEMA XIV.
38[Figure 38]
1. Sit altitudo A B, ad quam ex C, loco menſoris
non liceat accedere, aut ab earecedere ſecundum li-
neam rectam, ſed ſolum in latus, verbigratia vſque ad
D, vnde baſem videre poſsimus.
Inquiratur per pro-
blema 10.
longitudo tranſuerſa A C, ex loco D: inſpi-
ciatur que vertex B, ex C, per angulum ACB.
Et quia,
poſito ſinu toto A C, altitudo A B, Tangens eſt an-
guli obſeruationis ACB, ſi fiat.
224. Triang.
rectil.

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