DelMonte, Guidubaldo, Le mechaniche
page |< < of 270 > >|
    <archimedes>
      <text id="id.0.0.0.0.3">
        <body id="id.2.0.0.0.0">
          <chap id="N13354">
            <pb xlink:href="037/01/102.jpg"/>
            <p id="id.2.1.532.0.0" type="head">
              <s id="id.2.1.532.1.0">PROPOSITIONE VII. </s>
            </p>
            <p id="id.2.1.533.0.0" type="main">
              <s id="id.2.1.533.1.0">Sia la linea retta AB, à cui ſtia à piombo AD, laquale allun­
                <lb/>
              ghiſi dalla parte di D come pare ſin'à C, & congiungaſi C
                <lb/>
              B, laquale etiandio ſi allunghi fin'ad E; & ſimilmente tra
                <lb/>
              AB BE ſiano, come pare, tirate BF BG eguali ad eſſa AB,
                <lb/>
              & da punti FG ſiano
                <lb/>
              tirate le linee FH GK
                <lb/>
              pur eguali ad eſſa AD,
                <lb/>
              & à piombo di BF BG,
                <lb/>
              come ſe BA AD foſ­
                <lb/>
              ſero moſſe in BF FH
                <lb/>
              BG GK: & congiun­
                <lb/>
              ganſi CH CK, lequali
                <lb/>
              taglino le linee allunga
                <lb/>
              te BF BG ne' punti
                <lb/>
              MN. </s>
              <s id="id.2.1.533.2.0">Dico che BN è
                <lb/>
              maggiore di BM, &
                <lb/>
              BM di eſſa BA. </s>
            </p>
            <figure id="id.037.01.102.1.jpg" xlink:href="037/01/102/1.jpg" number="96"/>
            <p id="id.2.1.535.0.0" type="main">
              <s id="id.2.1.535.1.0">
                <emph type="italics"/>
              Congiunganſi BD BH BK, &
                <lb/>
              co'l centro B, & con lo ſpatio
                <lb/>
              BD deſcriuaſi il cerchio. </s>
              <s id="id.2.1.535.2.0">ſimil­
                <lb/>
              mente come nella precedente, di­
                <lb/>
              moſtreremo i punti KHDOP
                <lb/>
              eſſere nella circonferenza del cer
                <lb/>
              chio; & i
                <expan abbr="triāgoli">triangoli</expan>
              ABD FBH
                <lb/>
              GBK eſſere tra loro eguali, &
                <lb/>
              la linea PK eſſere maggiore
                <lb/>
              della OH, & l'angolo PKB
                <lb/>
              eſſere minore dell'angolo OHB.
                <lb/>
              </s>
              <s id="id.2.1.535.3.0">Percioche
                <expan abbr="dũque">dunque</expan>
              l'angolo BHF
                <lb/>
              è eguale all'angolo BKG, ſarà
                <lb/>
              tutto l'angolo PKG minore
                <lb/>
              dell'angolo OHF. </s>
              <s id="id.2.1.535.4.0">Per laqual
                <lb/>
              coſa il reſtante G
                <emph.end type="italics"/>
              K
                <emph type="italics"/>
              N ſarà
                <lb/>
              maggiore del reſtante FHM.
                <lb/>
              </s>
              <s id="id.2.1.535.5.0">Se
                <expan abbr="dũque">dunque</expan>
              ſi ſarà l'angolo G
                <emph.end type="italics"/>
              K
                <emph type="italics"/>
              Q
                <emph.end type="italics"/>
              </s>
            </p>
          </chap>
        </body>
      </text>
    </archimedes>
Impressum