DelMonte, Guidubaldo, Le mechaniche

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          <chap id="N13354">
            <p id="id.2.1.542.0.0" type="main">
              <s id="id.2.1.542.5.0">
                <pb pagenum="45" xlink:href="037/01/105.jpg"/>
                <emph type="italics"/>
              da K le linee HL KM à piombo de'loro orizonti, lequali ſi andaranno à tro­
                <lb/>
              uare nel centro del mondo, & ſia HL à piombo anche di eſſa AB. </s>
              <s id="id.2.1.542.6.0">Dapoi ſia
                <lb/>
              tirata la linea KN à piombo di EF, laquale ſarà eguale ad HL, & la CN
                <lb/>
              eguale ad eſſa CL. </s>
              <s id="id.2.1.542.7.0">Hor percioche HL è à piombo dell'orizonte, la poſſanza
                <lb/>
              in A ſoſtenente il peſo BD haurà quella proportione ad eſſo peſo, che CL à
                <emph.end type="italics"/>
                <arrow.to.target n="note151"/>
                <lb/>
                <emph type="italics"/>
              CA. </s>
              <s id="id.2.1.542.8.0">Di nuouo, percioche KM è à piombo dell'orizonte, la poſſanza in E ſo­
                <lb/>
              ſtenente il peſo FG coſi ſarà al peſo come CM à CE. </s>
              <s id="N14051">& per eſſere CN NK
                <lb/>
              eguali ad eſſe CL LH, & contenere angoli retti, ſarà CM minore di eſſa CL;
                <emph.end type="italics"/>
                <arrow.to.target n="note152"/>
                <lb/>
                <emph type="italics"/>
              Dunque CM à CA haurà proportione minore, che CL à CA; & CA
                <lb/>
              è eguale à CE, dunque haurà CM proportione minore à CE, che CL à
                <emph.end type="italics"/>
                <arrow.to.target n="note153"/>
                <lb/>
                <emph type="italics"/>
              CA: & per eſſerei peſi BD FG eguali, però che è il peſo medeſimo. </s>
              <s id="id.2.1.542.9.0">Dun­
                <lb/>
              que ſarà minore proportione della poſſanza in E ſoſtenente il peſo FG ad eſſo
                <lb/>
              peſo, che della poſſanza in A ſoſtenente il peſo BD ad eſſo peſo. </s>
              <s id="id.2.1.542.10.0">Per laqual
                <lb/>
              coſa minore poſſanza poſta in E ſoſtenterà il peſo FG, che la poſſanza in A
                <emph.end type="italics"/>
                <arrow.to.target n="note154"/>
                <lb/>
                <emph type="italics"/>
              il peſo BD. </s>
              <s id="N1407E">& quanto più ſarà inalzato il peſo, ſempre ſi moſtrerà poſſanza
                <emph.end type="italics"/>
                <arrow.to.target n="note155"/>
                <lb/>
                <emph type="italics"/>
              anche minore douer ſoſtenere il peſo, per eſſere la linea PC minore della CM.
                <lb/>
              </s>
              <s id="id.2.1.542.11.0">Sia dapoi la leua in QR, & il peſo in QS, il cui centro della grauezza ſia O.
                <lb/>
              </s>
              <s id="id.2.1.542.12.0">Dico che poſſanza maggiore ſi richiede in R per ſoſtenere il peſo QS, che in
                <lb/>
              A per ſostentare il peſo BD. </s>
              <s id="id.2.1.542.13.0">Tiriſi dal centro O della grauezza la linea OT
                <lb/>
              a piombo dell'orizonte. </s>
              <s id="id.2.1.542.14.0">& percioche le linee HL OT ſe ſaranno allungate dal­
                <lb/>
              la parte di L, & di T ſi andranno à ritrouare nel centro del mondo, ſarà la CT mag
                <lb/>
              giore della CL: & è la CA eguale ad eſſa CR, dunque la TC haurà pro­
                <emph.end type="italics"/>
                <arrow.to.target n="note156"/>
                <lb/>
                <emph type="italics"/>
              portione maggiore à CR, che LC à CA. </s>
              <s id="id.2.1.542.15.0">Maggiore dunque ſarà la poſſan­
                <emph.end type="italics"/>
                <arrow.to.target n="note157"/>
                <lb/>
                <emph type="italics"/>
              za in R ſoſtenente il peſo QS, che in A ſoſtenente il BD. </s>
              <s id="id.2.1.542.16.0">Similmente mo­
                <lb/>
              ſtreraſſi, che quanto la leua RQ abbaſſandoſi, ſarà più diſtante dalla leua AB,
                <emph.end type="italics"/>
                <arrow.to.target n="note158"/>
                <lb/>
                <emph type="italics"/>
              ſempre più ſi ricercherà poſſanza maggiore à ſoſtenere il peſo: peroche la diſtanza
                <emph.end type="italics"/>
                <arrow.to.target n="note159"/>
                <lb/>
                <emph type="italics"/>
              CV è più lunga di CT. </s>
              <s id="id.2.1.542.17.0">Quanto dunque il peſo ſi alzerà più dal ſito egualmente
                <lb/>
              diſtante dall'orizonte, ſarà ſempre ſoſtenuto da poſſanza minore; & quanto più ſi
                <lb/>
              abbaſſerà, di poſſanza maggiore haurà meſtieri per eſſer ſoſtentato. </s>
              <s id="id.2.1.542.18.0">che biſogna­
                <lb/>
              ua moſtrare.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.544.0.0" type="margin">
              <s id="id.2.1.544.1.0">
                <margin.target id="note151"/>
                <emph type="italics"/>
              Per la quinta di questo.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.545.0.0" type="margin">
              <s id="id.2.1.545.1.0">
                <margin.target id="note152"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              6.
                <emph type="italics"/>
              di questo.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.546.0.0" type="margin">
              <s id="id.2.1.546.1.0">
                <margin.target id="note153"/>
                <emph type="italics"/>
              Per la ottaua del quinto.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.547.0.0" type="margin">
              <s id="id.2.1.547.1.0">
                <margin.target id="note154"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              10.
                <emph type="italics"/>
              del quinto.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.548.0.0" type="margin">
              <s id="id.2.1.548.1.0">
                <margin.target id="note155"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              6.
                <emph type="italics"/>
              di questo.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.549.0.0" type="margin">
              <s id="id.2.1.549.1.0">
                <margin.target id="note156"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              6.
                <emph type="italics"/>
              di questo.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.550.0.0" type="margin">
              <s id="id.2.1.550.1.0">
                <margin.target id="note157"/>
                <emph type="italics"/>
              Per la ottaua del
                <emph.end type="italics"/>
              5. </s>
            </p>
            <p id="id.2.1.551.0.0" type="margin">
              <s id="id.2.1.551.1.0">
                <margin.target id="note158"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              10.
                <emph type="italics"/>
              del quinto.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.552.0.0" type="margin">
              <s id="id.2.1.552.1.0">
                <margin.target id="note159"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              6.
                <emph type="italics"/>
              di questo.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.553.0.0" type="main">
              <s id="id.2.1.553.1.0">Quinci facilmente ſi caua, che la posſanza in A alla poſsanza
                <lb/>
              in E coſi è, come CL à CM. </s>
            </p>
            <p id="id.2.1.554.0.0" type="main">
              <s id="id.2.1.554.1.0">
                <emph type="italics"/>
              Imperoche coſiè LC à CA, come la poſſanza in A al peſo; & come CA,
                <lb/>
              cioè CE à CM, coſi è il peſo alla poſſanza in E; Per laqual coſa per la pro­
                <emph.end type="italics"/>
                <arrow.to.target n="note160"/>
                <lb/>
                <emph type="italics"/>
              portion eguale, la poſſanza in A alla poſſanza in E ſarà come CL à CM.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.555.0.0" type="margin">
              <s id="id.2.1.555.1.0">
                <margin.target id="note160"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              22.
                <emph type="italics"/>
              del quinto.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.556.0.0" type="main">
              <s id="id.2.1.556.1.0">
                <emph type="italics"/>
              Con ſimile ragione moſtreraßi non ſolamente che la poſſanza in A coſi è alla poſ­
                <lb/>
              ſanza in R, come CL à CT, ma che la poſſanza in E ancora alla poſſanza
                <lb/>
              in R è coſi, come CM à CT, & coſi nel reſto.
                <emph.end type="italics"/>
              </s>
            </p>
          </chap>
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