DelMonte, Guidubaldo
,
In duos Archimedis aequeponderantium libros Paraphrasis : scholijs illustrata
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CAB æqualis; reliquus igitur angulus LFD reliquo HAB
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æqualis exiſtit. </
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">& quoniam ita eſt CF ad FA, vt CL ad
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cùm ſint FL AH ęquidiſtantes. </
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<
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">CF verò dimidia eſt ipſius
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CA, erit & CL ipſius quo〈que〉 CH dimidia. </
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<
s
id
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N13BB6
">at CD ipſius
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CB dimidia exiſtit; erit igitur DL ipſi BH ęquidiſtans. </
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<
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propterea angulus LDC eſt ipſi HBC ęqualis, & LDF
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HBA ęqualis. </
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<
s
id
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">cùm ſittotus CDF toti CBA ęqualis; anguli
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verò ACH & HCB tam ſunt trianguli ABC, quàm FDC.
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Obeandem autem rationem trianguli EBD centrum grauitatis est
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pũ-
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ctum K.
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ſimiliter enim oſtendetur punctum K in triangu
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lo EBD eſſe ſimiliter poſitum, vt H in triangulo ABC.
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Quare magnitudinis ex vtriſquè triangulis EBD FDC compoſitæ
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centrum grauitatis eſt in medietate lineæ
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k
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L. cum triangula EBD
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FDC ſint æqualia.
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ſunt enim in ęqualibus baſibus BD
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& in ijſdem parallelis EF BC, ſiquidem eſt AE ad EB,
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AF ad FC. quippè cùm latera AB AC ſint bifariam diui
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ſa.
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medium veròipſius
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k
<
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L eſt punctum N; cùm ſit
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KE ipſi AH
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ęquidiſtans, & ob id ſit
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BE ad EA, vt B
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k
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ad
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k
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H.
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& vt
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ad EA, ita CF ad FA;
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vt autem CF ad FA, ſic CL ad LH.
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type
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"/>
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quare vt BK ad KH, ita CL ad LH.
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type
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Si autem hoc. </
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<
s
id
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N13C34
">æquidi-
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ſtans est BC ipſi
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k
<
emph
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L, & iuncta est DH, erit igitur BD ad DC, vt
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KN ad NL.
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D verò medium eſt ipſius BC. ergo &
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me
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dium eſt ipſius KL.
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Quare magnitudinis ex vtriſquè
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dictorũ
">dictorum</
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trian
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gulorum
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type
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italics
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EBD & FDC
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compoſitæ centrum
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emph.end
type
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grauitatis
<
emph
type
="
italics
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est punctum
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<
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<
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N. parallelogrammi verò AEDF centrum grauitatis eſt punctum M,
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emph.end
type
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italics
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vbi ſimiliter diametri concurrunt,
<
emph
type
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ac propterea magnitudinis ex
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<
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omnibus
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triangulis EBD FDC vna
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expan
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cũ
">cum</
expan
>
parallelogramo AEDF
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<
emph
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compoſitæ centrum grauitatis eſt in linea MN. Verùm
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<
expan
abbr
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triangulorũ
">triangulorum</
expan
>
<
lb
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EBD FDC, ſimulquè parallelogrammi AEDF, hoc eſt totius
<
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<
emph
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trianguli ABC grauitatis centrum est punctum H; linea igitur MN pro
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<
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ducta tranſibit per punctum H. quod eſſe non poteſt.
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etenim cùm ſit
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KN ipſi BD æquidiſtans; erit BK ad KH, vt DN ad
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NH: vt autem BK ad KH, ita eſt BE ad EA, & vt BE ad
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EA, ita eſt DM ad MA, cùm ſit EM ipſi BD æquidiſtans.
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erit igitur DM ad MA, vt DN ad NH. quare MN ipſi AH
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eſt ęquidiſtans; ideoquè MN numquam cùm AH conueni
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re poteſt.
<
emph
type
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italics
"/>
Non est igitur
<
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"/>
punctum
<
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type
="
italics
"/>
H centrum grauitatis trianguli
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