DelMonte, Guidubaldo, Le mechaniche

Table of figures

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            <pb xlink:href="037/01/106.jpg"/>
            <p id="id.2.1.558.0.0" type="main">
              <s id="id.2.1.558.1.0">
                <emph type="italics"/>
              Sia poi la leua AB egualmente diſtante dall'orizonte, il cui ſoſtegno ſia B, & il
                <lb/>
              centro H della grauezza del peſo CD ſia ſopra la leua; & mouaſi la leua in
                <lb/>
              BE, & il peſo in FG. </s>
              <s id="id.2.1.558.2.0">Dico che minore poſſanza poſta in E ſoſtiene il peſo FG
                <lb/>
              con la leua EB, che la poſſanza in A il peſo CD con la leua AB. </s>
              <s id="id.2.1.558.3.0">Sia K
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              il centro della grauezza del peſo FG, & da i centri delle grauezze HK ſiano
                <emph.end type="italics"/>
                <lb/>
                <figure id="id.037.01.106.1.jpg" xlink:href="037/01/106/1.jpg" number="99"/>
                <lb/>
                <arrow.to.target n="note161"/>
                <emph type="italics"/>
              tirate le linee HL
                <emph.end type="italics"/>
              K
                <emph type="italics"/>
              M à piombo de'loro orizonti. </s>
              <s id="id.2.1.558.4.0">Hor percioche dalle coſe
                <lb/>
              di ſopra moſtrate BM è minore di BL, & BE è eguale à BA, haurà pro­
                <emph.end type="italics"/>
                <lb/>
                <arrow.to.target n="note162"/>
                <emph type="italics"/>
              portione minore BM à BE, che BL à BA: ma come BM à BE, coſi
                <emph.end type="italics"/>
                <lb/>
                <arrow.to.target n="note163"/>
                <emph type="italics"/>
              è la poſſanza in E ſoſtenente il peſo FG ad eſſo peſo, & come BL a BA,
                <lb/>
              coſi la poſſanza in A al peſo CD; la poſſanza in E al peſo FG haurà propor­
                <emph.end type="italics"/>
                <lb/>
                <arrow.to.target n="note164"/>
                <emph type="italics"/>
              tione minore, che la poſſanza in A al peſo CD. </s>
              <s id="id.2.1.558.5.0">Dunque la poſſanza in E ſa­
                <lb/>
              rà minore della poſſanza in A. </s>
              <s id="id.2.1.558.6.0">Similmente moſtreraſſi quanto più il peſo ſi alze­
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              rà, ſempre minore poſſanza ſoſtenere il peſo, ma ſia la leua in BO, & il peſo in
                <lb/>
              BQ, il cui centro della grauezza ſia R. </s>
              <s id="id.2.1.558.7.0">Dico, che maggior poſſanza ſi ricerca
                <lb/>
              in O per ſoſtenere il peſo PQ con la leua BO, che per ſoſtenere il peſo CD con
                <lb/>
              la leua BA. </s>
              <s id="id.2.1.558.8.0">Sia tirata dal punto R la linea RS à piombo dell'orizonte. </s>
              <s id="id.2.1.558.9.0">&
                <emph.end type="italics"/>
                <lb/>
                <arrow.to.target n="note165"/>
                <emph type="italics"/>
              percioche BS è maggiore di BL, haurà BS proportione maggiore à BO, che
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              BL à BA; Per laqual coſa la poſſanza in O ſoſtenente il peſo PQ ſarà maggio
                <lb/>
              re della poſſanza in A ſoſtenente il peſo CD. </s>
              <s id="N1421D">& à queſto modo ſi moſtrerà an­
                <lb/>
              cora che quanto la leua BO abbaſſandoſi, ſarà più diſtante dalla leua AB ſem­
                <lb/>
              pre vi vorrà poſſanza maggiore à ſoſtener il peſo.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.560.0.0" type="margin">
              <s id="id.2.1.560.1.0">
                <margin.target id="note161"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              6.
                <emph type="italics"/>
              di questo.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.561.0.0" type="margin">
              <s id="id.2.1.561.1.0">
                <margin.target id="note162"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              8.
                <emph type="italics"/>
              del quinto.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.562.0.0" type="margin">
              <s id="id.2.1.562.1.0">
                <margin.target id="note163"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              5.
                <emph type="italics"/>
              di questo.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.563.0.0" type="margin">
              <s id="id.2.1.563.1.0">
                <margin.target id="note164"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              10.
                <emph type="italics"/>
              del quinto.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.564.0.0" type="margin">
              <s id="id.2.1.564.1.0">
                <margin.target id="note165"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              6.
                <emph type="italics"/>
              di questo.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.565.0.0" type="main">
              <s id="id.2.1.565.1.0">
                <emph type="italics"/>
              Di qui parimente, come di ſopra è manifeſto, che la poſſanza in A è alla poſſanza in
                <emph.end type="italics"/>
              </s>
            </p>
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