Clavius, Christoph - Geometria practica

Clavius, Christoph, Geometria practica

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10878GEOMETR. PRACT. quam BC, ſecluſa menſoris ſtatura CF. Altitudo namq; BC, exaltitudine A C,
detracta notam relinquet altitudinem AB, quæ quæritur.

3. Inventa diſtantia DC, per ea, quæ in problemate 1. & 2. tradidimus,
ſi fiat,

114. Triang.
rectil.22
Vt ſin{us} to- \\ t{us} DC, # ad diſtantiam cogni- \\ tam DC, # Ita A C, Tangens maioris anguli \\ obſeruati ADC, # ad AC,

reperietur|altitudo maior A C, in partibus diſtantiæ inuentæ D C. Et 334. Triang.
rectil. ſus fiat,

44
Vt ſin{us} to- \\ t{us} DC, # ad diſtantiam in- \\ uentam DC: # Ita BC, Tangens minoris anguli ob- \\ ſeruati BDC, # ad B C,

cognita fiet altitudo minor BC, in partibus eiuſdem diſtantiæ inuentæ DC, quæ
dempta ex maiore altitudine A C, notam relinquet altitudinem turris B A,
quæſitam.

Atqve hæc ratio commodiſsima eſt, quando in turri aliqua, vel ædificio,
cuius diſtantia à menſore cognita ſit, metiendum eſt interuallum perpendicu-
lare inter duas feneſtras.

4. Inventa rurſum diſtantia DC, per ea, quæin problemate 1. & 2. ſcripſi-
mus; detrahatur Tangens B C, (poſito ſinu toto D C,) minoris anguli obſer-
uati A D C, vt nota remaneat AB, differen@a dictarum Tangentium. Nam ſi fiat,

55
Vt ſin{us} to- \\ t{us} DC, # ad diſtantiam in- \\ uentam DC, # ita A B, differentia Tangen- \\ tium AC, BC, # ad A B, altitu- \\ dinem,

procreabitur altitudo quæſita AB, in partibus diſtantiæ inuentæ D C.

5. Inventa per problema 2. vel 15. altitudine montis B C, obſeruen-
tur anguli B D C, A D C, per radios D B, D A. Poſito namque ſinu toto
D C, ſi fiat,

66
Vt B C, Tangens \\ minoris anguli \\ obſeruati B D C, # ad B C, altitu- \\ dinem inuen- \\ tam: # Ita A B, differentia Tangen- \\ tium AC, CB, angulorum \\ obſeruatorum ADC, B DC. # ad A B

prodibitrurſus altitudo nota AB, quam quærimus.

Si autem media aliqua portio IB, cognoſcenda eſt, coniicienda rurſus erit
vtraque altitudo IC, BC, vt earum differentia IB, nota red datur.

Si deniqueinferior pars B C, proponitur inquirenda, fiet id per Problema
2. vel 15.

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