DelMonte, Guidubaldo, In duos Archimedis aequeponderantium libros Paraphrasis : scholijs illustrata

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    <archimedes>
      <text>
        <body>
          <chap id="N10019">
            <pb xlink:href="077/01/109.jpg" pagenum="105"/>
            <p id="N13F36" type="margin">
              <s id="N13F38">
                <margin.target id="marg159"/>
              14.
                <emph type="italics"/>
              huius.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="N13F41" type="margin">
              <s id="N13F43">
                <margin.target id="marg160"/>
              1.
                <emph type="italics"/>
              ſexti.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="N13F4C" type="margin">
              <s id="N13F4E">
                <margin.target id="marg161"/>
              1.
                <emph type="italics"/>
              ſexti.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="N13F57" type="margin">
              <s id="N13F59">
                <margin.target id="marg162"/>
              1.
                <emph type="italics"/>
              ſexti.
                <emph.end type="italics"/>
              </s>
            </p>
            <figure id="id.077.01.109.1.jpg" xlink:href="077/01/109/1.jpg" number="67"/>
            <p id="N13F66" type="main">
              <s id="N13F68">ALITER. </s>
            </p>
            <p id="N13F6A" type="main">
              <s id="N13F6C">Sit rurſus triangulum ABC, & AD BE ab angulis ad di
                <lb/>
              midias baſes ductæ ſint erit vti〈que〉 punctum, F (vbi ſe in
                <arrow.to.target n="marg163"/>
                <lb/>
              cen fecant) centrum grauitatis triangulb ABC. Drco AF a­
                <lb/>
              pſius FD duplam eſſe. </s>
              <s id="N13F77">Iungatur DE. Quoniam enim BC
                <lb/>
                <arrow.to.target n="fig49"/>
                <lb/>
              AC in punctis DE bifariam ſecantur; erit
                <lb/>
              CD ad DB, vt CE ad EA. linea igitur
                <lb/>
              DE ipſi AB eſt æquidiſtans. </s>
              <s id="N13F84">
                <arrow.to.target n="marg164"/>
              trian­
                <lb/>
              gulum ABC ſimile eſt triangulo
                <arrow.to.target n="marg165"/>
                <lb/>
              ac propterea ita eſt BC ad CD, vt AB
                <lb/>
              ad DE. eſt autem. </s>
              <s id="N13F93">BC dupla ipſius CD
                <lb/>
              (ſiquidem punctum D bifariam diuidit
                <lb/>
              BC) erit igitur AB dupla ipſius DE. At
                <lb/>
              vero quoniam AB DE ſunt parallelæ, erit triangulum AFB
                <lb/>
              triangulo EFD ſimile. </s>
              <s id="N13F9D">& vt AB ad ED, ita AF ad FD,
                <arrow.to.target n="marg166"/>
                <lb/>
              autem AB ipſius ED dupla, ergo AF ipſius FD dupla
                <lb/>
              exiſtit. </s>
              <s id="N13FA6">quod demonſtrare oportebat. </s>
            </p>
            <p id="N13FA8" type="margin">
              <s id="N13FAA">
                <margin.target id="marg163"/>
              14.
                <emph type="italics"/>
              huius.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="N13FB3" type="margin">
              <s id="N13FB5">
                <margin.target id="marg164"/>
              2.
                <emph type="italics"/>
              ſexti.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="N13FBE" type="margin">
              <s id="N13FC0">
                <margin.target id="marg165"/>
              4.
                <emph type="italics"/>
              ſexti.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="N13FC9" type="margin">
              <s id="N13FCB">
                <margin.target id="marg166"/>
              4.
                <emph type="italics"/>
              ſexti.
                <emph.end type="italics"/>
              </s>
            </p>
            <figure id="id.077.01.109.2.jpg" xlink:href="077/01/109/2.jpg" number="68"/>
            <p id="N13FD8" type="main">
              <s id="N13FDA">Exijs, quæ demonſtrata ſunt, oſtendemus, quod paulò an
                <lb/>
              te propoiuimus, nempè cùm lineæ AD BE bifariam ſecent
                <lb/>
              BC CA. Dico lineam CF productam bifariam quo〈que〉 ſe­
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              care ipſam AB. </s>
            </p>
            <p id="N13FE2" type="main">
              <s id="N13FE4">Producatur enim (ijsdem poſitis) CFGH; quæ lineam
                <lb/>
                <arrow.to.target n="fig50"/>
                <lb/>
              AB ſecet in G. & à puncto B
                <lb/>
              ipſi AD æquidiſtans ducatur
                <lb/>
              BH. quæ ipſi CG occuriat in
                <lb/>
              H. Quoniam igitur FD, eſt i­
                <lb/>
              pſi BH ęquidiſtans, erit CD
                <lb/>
              ad DB, vt CF ad FH.
                <arrow.to.target n="marg167"/>
              ve­
                <lb/>
              rò eſt æqualis BD; ergo CF ipſi
                <lb/>
              FH æqualis exiſtit. </s>
              <s id="N13FFF">ac propterea
                <lb/>
              CH dupla eſt ipſius (F. At ve­
                <lb/>
              rò quoniam ob ſimilitudinem
                <lb/>
                <expan abbr="triangulorũ">triangulorum</expan>
              CBH CDF, ita eſt
                <lb/>
              HC ad CF, vt BH ad DF; erit & BH ipſius FD duplex. </s>
            </p>
          </chap>
        </body>
      </text>
    </archimedes>
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