DelMonte, Guidubaldo, Le mechaniche

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          <chap id="N13354">
            <pb xlink:href="037/01/110.jpg"/>
            <p id="id.2.1.583.0.0" type="head">
              <s id="id.2.1.583.1.0">PROPOSITIONE IX. </s>
            </p>
            <p id="id.2.1.584.0.0" type="main">
              <s id="id.2.1.584.1.0">La poſſanza ſoſtenente il peſo, che habbia il centro della ſua gra
                <lb/>
              uezza ſotto la leua egualmente diſtante dall'orizonte, quanto
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              più il peſo ſarà alzato da queſto ſito con la leua, haurà egli ſem
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              pre anco meſtieri di poſſanza maggiore ad eſſere ſoſtenuto;.
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              </s>
              <s id="id.2.1.584.1.0.a">Ma ſe abbaſſato, di minore. </s>
            </p>
            <p id="id.2.1.585.0.0" type="main">
              <s id="id.2.1.585.1.0">
                <emph type="italics"/>
              Sia la leua AB egualmente
                <expan abbr="diſtāte">diſtante</expan>
              dall'orizonte, il cui ſoſtegno ſia C, & ſia il peſo AD,
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              il cui centro L della grauezza ſia ſotto la leua, & ſia in B la poſſanza ſoſtenen­
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              te il peſo AD: mouaſi dopo la leua in FG, & il peſo in FH. </s>
              <s id="id.2.1.585.2.0">Dico prima,
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              che poſſanza maggiore ſi ricerca in G per ſoſtenere il peſo FH con la leua FG,
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              di quel che ſia la poſſanza in B eſſendo il peſo AD, ma con la leua AB. </s>
              <s id="id.2.1.585.3.0">ſia
                <emph.end type="italics"/>
                <lb/>
                <figure id="id.037.01.110.1.jpg" xlink:href="037/01/110/1.jpg" number="103"/>
                <lb/>
                <emph type="italics"/>
              M il centro della grauezza del peſo FH, & da punti LM ſiano tirate le linee
                <emph.end type="italics"/>
                <lb/>
                <arrow.to.target n="note171"/>
                <emph type="italics"/>
              LK MN à piombo de'loro orizonti; & ſia tirata la linea MS à piombo di FG,
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              che ſarà eguale ad LK, & CK ſarà etiandio eguale ad eſſa CS. </s>
              <s id="id.2.1.585.4.0">Percioche dun
                <emph.end type="italics"/>
                <lb/>
                <arrow.to.target n="note172"/>
                <emph type="italics"/>
              que CN è maggiore di CK haurà NC proportione maggiore à CG, che CK
                <lb/>
              à CB; & la poſſanza in B al peſo AD ha la medeſma proportione, che KC
                <emph.end type="italics"/>
                <lb/>
                <arrow.to.target n="note173"/>
                <emph type="italics"/>
              à CB: & come la poſſanza in G al peſo FH, coſi è NC à CG; dunque la
                <emph.end type="italics"/>
                <lb/>
                <arrow.to.target n="note174"/>
                <emph type="italics"/>
              poſſanza in G hauerà maggiore proportione al peſo FH, che la poſſanza in B
                <lb/>
              al peſo AD. </s>
              <s id="id.2.1.585.5.0">Maggiore dunque è la poſſanza in G della poſſanza in B. </s>
              <s id="N144DC">che ſe
                <emph.end type="italics"/>
              </s>
            </p>
          </chap>
        </body>
      </text>
    </archimedes>
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