DelMonte, Guidubaldo
,
In duos Archimedis aequeponderantium libros Paraphrasis : scholijs illustrata
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113
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<
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">Curautem hoc modo centra grauitatum in præfatis figu
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ris poſitione tantùm, & non determinatè ea indeterminata,
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linea, & in tali ſitu exiſtere inuenerimus, vt in parallelogram
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mis & in triangulis factum fuitab Archimede; explicabitur in
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ſecundo libro poſt tertiam proportionem; vbi oſtendemus,
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in quibus figuris determinatè inueniri poteſt centrum graui
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tatis. </
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<
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">Antequam autem finem primolibro imponamus,
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abbr
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reliquũ
">reliquum</
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eſt; vt ea quæ in præfatione ſuppoſuimus, oſtendamus. </
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<
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mùm què quando ſecundùm rectam lineam aliqua diuiditur
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figura per centrum grauitatis, aliquando diuidi in partes ſem
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per ęquales, & aliquando in partes inæquales. </
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<
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">Figura dari poteſt, quę per centrum grauitatis recta li
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nea diuiſa, ſemper in partes diuidatur æquales. </
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type
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<
s
id
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parallelogrammũ
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fig57
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ABCD, cuius
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abbr
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centrũ
">centrum</
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gra
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uitatis E. Ducaturquè per
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E
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vtcunq́
">vtcun〈que〉</
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; linea GEF, quę
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vel diameter eſt, vel min^{9}.
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ſi eſt diameter, iam
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abbr
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cõſtat
">conſtat</
expan
>
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<
expan
abbr
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parallelogrãmum
">parallelogrammum</
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in duo
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ęqua eſſe diuiſum. </
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<
s
id
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N14555
">Si verò non eſt diameter,
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abbr
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ducãtur
">ducantur</
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marg189
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AC BD, quæ per E tranſibunt. </
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<
s
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">Quoniam igitur AF eſt æqui
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diftans ipſi CG, eritangulus EAF ipſi ECG, & EFA ipſi
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æqualis, eſt autem AEF ipſi GEC ad verticem æqualis,
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latusq́
">latus〈que〉</
expan
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AE ipſi EC æquale; erit triangulum AEF triangulo CEG ęqua
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le. </
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<
s
id
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N14574
">eodemquè modo oſtendetur triangulum FEB triangulo
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EGD. & triangulum AED ipſi BEC æquale. </
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<
s
id
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N14578
">Ex quibus patet.
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figuram ex tribus triangulis compoſitam, hoc eſt figuram
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FGDA ipſi FGCB æqualem eſſe. </
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<
s
id
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N1457E
">diuiditurergo
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parallelogrã-mum
">parallelogran
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mum</
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à linea per centrum grauitatis ducta in partes ſem perç
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quales. </
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<
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id
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N14588
">quod demonſtrare oportebat. </
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