DelMonte, Guidubaldo, Le mechaniche

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    <archimedes>
      <text id="id.0.0.0.0.3">
        <body id="id.2.0.0.0.0">
          <chap id="N13354">
            <p id="id.2.1.621.0.0" type="main">
              <s id="id.2.1.621.1.0">
                <pb pagenum="51" xlink:href="037/01/117.jpg"/>
                <emph type="italics"/>
              proportione maggiore, che il peſo C alla poſſanza in B. </s>
              <s id="id.2.1.621.2.0">Dico che il peſo C ſa­
                <lb/>
              rà moſſo dalla poſſanza in B. </s>
              <s id="id.2.1.621.3.0">Facciaſi come BD à DA, coſi il peſo E alla
                <emph.end type="italics"/>
                <arrow.to.target n="note179"/>
                <lb/>
                <emph type="italics"/>
              poſſanza in B; & appicchiſi parimente il peſo E in A: egliè chiaro che la poſ­
                <lb/>
              ſanza in B pe­
                <lb/>
              ſa
                <expan abbr="egualmēte">egualmente</expan>
                <expan abbr="cõ">con</expan>
                <lb/>
              eſſo E; cioè che
                <lb/>
              ſoſtiene il detto
                <lb/>
              peſo E. </s>
              <s id="id.2.1.621.4.0">& per­
                <lb/>
              cioche BD ha
                <lb/>
              proportion mag
                <lb/>
              giore à DA che
                <lb/>
              C alla poſſanza
                <lb/>
              in B. </s>
              <s id="N147D2">& come
                <lb/>
              BD à DA, coſi
                <emph.end type="italics"/>
                <lb/>
                <figure id="id.037.01.117.1.jpg" xlink:href="037/01/117/1.jpg" number="110"/>
                <lb/>
                <emph type="italics"/>
              è il peſo F. </s>
              <s id="N147E2">alla poſſanza: adunque E haurà proportione maggiore alla poſſan­
                <emph.end type="italics"/>
                <arrow.to.target n="note180"/>
                <lb/>
                <emph type="italics"/>
              za, che il peſo C alla poſſanza iſteſſa. </s>
              <s id="id.2.1.621.5.0">Per laqual coſa il peſo E ſarà maggiore
                <lb/>
              del peſo C. </s>
              <s id="N147F2">& perche la poſſanza peſa egualmente con eſſo E; dunque la poſſan
                <lb/>
              za non peſerà egualmente con eſſo C, ma per la forza ſua inchinerà al baſſo. </s>
              <s id="id.2.1.621.6.0">dun
                <lb/>
              que il peſo C ſarà moſſo dalla poſſanza in B con la leua AB, il cui ſoſtegno
                <lb/>
              è in D.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.623.0.0" type="margin">
              <s id="id.2.1.623.1.0">
                <margin.target id="note179"/>
                <emph type="italics"/>
              Per la prima di questo.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.624.0.0" type="margin">
              <s id="id.2.1.624.1.0">
                <margin.target id="note180"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              10.
                <emph type="italics"/>
              del quinto.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.625.0.0" type="main">
              <s id="id.2.1.625.1.0">
                <emph type="italics"/>
              Ma ſe la leua foſſe AB, & il ſoſtegno A, & il peſo C appiccato in D, & la
                <lb/>
              poſſanza in B, & BA haueſſe proportione maggiore ad AD, che il peſo C
                <lb/>
              alla poſſanza in B. </s>
              <s id="id.2.1.625.2.0">Dico che il peſo C moueraſſi dalla poſſanza in B. </s>
              <s id="id.2.1.625.3.0">facciaſi co
                <emph.end type="italics"/>
                <arrow.to.target n="note181"/>
                <lb/>
                <emph type="italics"/>
              me BA ad AD, coſi il pe­
                <lb/>
              ſo E alla poſſanza in B: &
                <lb/>
              ſe E ſarà appiccato in D, la
                <lb/>
              poſſanza in B ſoſtenterà il pe­
                <lb/>
              ſo E. </s>
              <s id="id.2.1.625.4.0">Ma per hauere BA pro­
                <lb/>
              portione maggiore ad AD,
                <lb/>
              che il peſo C alla poſſanza in
                <lb/>
              B; & come BA ad AD,
                <lb/>
              coſi è il peſo E alla poſſanza in
                <lb/>
              B; dunque il peſo E haurà pro
                <lb/>
              portione maggiore alla poſſan
                <emph.end type="italics"/>
                <arrow.to.target n="note182"/>
                <lb/>
                <figure id="id.037.01.117.2.jpg" xlink:href="037/01/117/2.jpg" number="111"/>
                <lb/>
                <emph type="italics"/>
              za che è in B, che il peſo C all'iſteſſa poſſanza: & perciò il peſo E ſarà maggio
                <lb/>
              re del peſo C; & la poſſanza in B ſoſtiene il peſo E; dunque la poſſanza in B
                <lb/>
              con la leua AB mouerà il peſo C minore del peſo E appiccato in D, il cui ſo­
                <lb/>
              stegno è A.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.627.0.0" type="margin">
              <s id="id.2.1.627.1.0">
                <margin.target id="note181"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              2.
                <emph type="italics"/>
              di questo.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.628.0.0" type="margin">
              <s id="id.2.1.628.1.0">
                <margin.target id="note182"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              10.
                <emph type="italics"/>
              del quinto.
                <emph.end type="italics"/>
              </s>
            </p>
          </chap>
        </body>
      </text>
    </archimedes>
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