Gravesande, Willem Jacob 's, An essay on perspective

Table of contents

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[121.] Problem I.
[122.] Problem II.
[123.] Operation.
[124.] Demonstration.
[125.] Remark.
[126.] Problem III.
[127.] Method II.
[128.] Operation.
[129.] Demonstration.
[130.] Method III.
[131.] Operation.
[132.] Demonstration.
[133.] Remark.
[134.] Problem IV.
[135.] Problem V.
[136.] Operation.
[137.] Demonstration.
[138.] Problem VI.
[139.] Method II.
[140.] Operation.
[141.] Demonstration.
[142.] Method III.
[143.] CHAP. VI.
[144.] Prob. I.
[145.] Prob. II.
[146.] Demonstration.
[147.] Corollary.
[148.] Method II.
[149.] Operation,
[150.] Demonstration.
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            <s xml:id="echoid-s1425" xml:space="preserve">
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            tal Plane, or one of the Points of Diſtance on the
              <lb/>
            Horizontal Line.</s>
            <s xml:id="echoid-s1426" xml:space="preserve"/>
          </p>
          <p>
            <s xml:id="echoid-s1427" xml:space="preserve">The Repreſentation of two Points of theſe
              <lb/>
            Figures muſt be firſt found ; </s>
            <s xml:id="echoid-s1428" xml:space="preserve">and then by
              <note symbol="*" position="left" xlink:label="note-0110-01" xlink:href="note-0110-01a" xml:space="preserve">24.</note>
            of theſe two Points the Appearances of others
              <lb/>
            may be had .</s>
            <s xml:id="echoid-s1429" xml:space="preserve"/>
          </p>
          <note symbol="*" position="left" xml:space="preserve">38.</note>
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        <div xml:id="echoid-div212" type="section" level="1" n="112">
          <head xml:id="echoid-head118" xml:space="preserve">
            <emph style="sc">Example</emph>
          .</head>
          <p>
            <s xml:id="echoid-s1430" xml:space="preserve">Let A B C D E, be a Pentagon, whoſe Ap-
              <lb/>
              <note position="left" xlink:label="note-0110-03" xlink:href="note-0110-03a" xml:space="preserve">Fig. 40.</note>
            pearance is requir’d; </s>
            <s xml:id="echoid-s1431" xml:space="preserve">V the Point of Sight; </s>
            <s xml:id="echoid-s1432" xml:space="preserve">and
              <lb/>
            V F the ſixth Part of the Eye’s Diſtance from
              <lb/>
            the perſpective Plane. </s>
            <s xml:id="echoid-s1433" xml:space="preserve">Now find b and e
              <note symbol="*" position="left" xlink:label="note-0110-04" xlink:href="note-0110-04a" xml:space="preserve">24.</note>
            Appearance of B and E, by means of which,
              <lb/>
            the Appearance of the Point A will be had .</s>
            <s xml:id="echoid-s1434" xml:space="preserve">
              <note symbol="*" position="left" xlink:label="note-0110-05" xlink:href="note-0110-05a" xml:space="preserve">38.</note>
            In like Manner, by means of the Repreſenta-
              <lb/>
            tion of A and E, will that of D be had; </s>
            <s xml:id="echoid-s1435" xml:space="preserve">and
              <lb/>
            by uſing B and A, the Perſpective of C may be
              <lb/>
            found.</s>
            <s xml:id="echoid-s1436" xml:space="preserve"/>
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          <p>
            <s xml:id="echoid-s1437" xml:space="preserve">76. </s>
            <s xml:id="echoid-s1438" xml:space="preserve">Note, the Perſpective of Lines perpendicu-
              <lb/>
            lar to the Geometrical Plane ; </s>
            <s xml:id="echoid-s1439" xml:space="preserve">as alſo of
              <note symbol="*" position="left" xlink:label="note-0110-06" xlink:href="note-0110-06a" xml:space="preserve">55.</note>
            inclined thereto , may be found by the
              <note symbol="*" position="left" xlink:label="note-0110-07" xlink:href="note-0110-07a" xml:space="preserve">69.</note>
            of the precedent Chapter.</s>
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        <div xml:id="echoid-div215" type="section" level="1" n="113">
          <head xml:id="echoid-head119" xml:space="preserve">
            <emph style="sc">Problem</emph>
          II.</head>
          <p style="it">
            <s xml:id="echoid-s1441" xml:space="preserve">77. </s>
            <s xml:id="echoid-s1442" xml:space="preserve">To throw Figures, which are in the Geometri-
              <lb/>
            cal Plane into Perſpective, when the Eye is ſo oblique
              <lb/>
            that it cannot be marked in the Horizontal Plane,
              <lb/>
            or the Point of Sight in the Horizontal Line.</s>
            <s xml:id="echoid-s1443" xml:space="preserve"/>
          </p>
          <p>
            <s xml:id="echoid-s1444" xml:space="preserve">We muſt proceed here according to the Di-
              <lb/>
            rections of the precedent Problem, after having
              <lb/>
            found the Perſpective of ſeveral Points of the
              <lb/>
            given Figures.</s>
            <s xml:id="echoid-s1445" xml:space="preserve"/>
          </p>
          <p>
            <s xml:id="echoid-s1446" xml:space="preserve">At any Point C, taken at Pleaſure in the Baſe
              <lb/>
            Line, draw the Perpendicular C D to the ſaid
              <lb/>
              <note position="left" xlink:label="note-0110-08" xlink:href="note-0110-08a" xml:space="preserve">Fig. 41.</note>
            Line, and likewiſe draw the Line C E from the
              <lb/>
            ſame Point in ſuch manner, that if it could </s>
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