DelMonte, Guidubaldo, Le mechaniche

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        <body id="id.2.0.0.0.0">
          <chap id="N14EBE">
            <pb pagenum="57" xlink:href="037/01/129.jpg"/>
            <p id="id.2.1.712.0.0" type="head">
              <s id="id.2.1.712.1.0">LEMMA. </s>
            </p>
            <p id="id.2.1.713.0.0" type="main">
              <s id="id.2.1.713.1.0">Siano due linee rette AB CD egualmente diſtanti, lequali
                <lb/>
              tocchino il cerchio ACE ne' punti AC, il centro delqual
                <lb/>
              cerchio ſia F, & ſi congiunghino FA & FC. </s>
              <s id="id.2.1.713.2.0">dico che la
                <lb/>
              linea AFC è retta. </s>
            </p>
            <p id="id.2.1.714.0.0" type="main">
              <s id="id.2.1.714.1.0">
                <emph type="italics"/>
              Tiriſi la linea FE egualmente diſtante dal­
                <emph.end type="italics"/>
                <arrow.to.target n="note208"/>
                <lb/>
                <emph type="italics"/>
              le linee AB CD. </s>
              <s id="id.2.1.714.2.0">Et percioche AB
                <lb/>
              & FE ſono egualmente diſtanti, &
                <emph.end type="italics"/>
                <arrow.to.target n="note209"/>
                <lb/>
                <emph type="italics"/>
              l'angolo BAF èretto: ſarà anco A
                <lb/>
              FE retto, & all'iſteſſo modo CFE ſa
                <emph.end type="italics"/>
                <arrow.to.target n="note210"/>
                <lb/>
                <emph type="italics"/>
              rà retto: adunque la linea AFC èret­
                <lb/>
              ta, ilche s'hauea à dimoſtrare.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.715.0.0" type="margin">
              <s id="id.2.1.715.1.0">
                <margin.target id="note208"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              18.
                <emph type="italics"/>
              del terzo.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.716.0.0" type="margin">
              <s id="id.2.1.716.1.0">
                <margin.target id="note209"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              29.
                <emph type="italics"/>
              del primo.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.717.0.0" type="margin">
              <s id="id.2.1.717.1.0">
                <margin.target id="note210"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              14.
                <emph type="italics"/>
              del primo.
                <emph.end type="italics"/>
              </s>
            </p>
            <figure id="id.037.01.129.1.jpg" xlink:href="037/01/129/1.jpg" number="126"/>
            <p id="id.2.1.719.0.0" type="head">
              <s id="id.2.1.719.1.0">PROPOSITIONE I. </s>
            </p>
            <p id="id.2.1.720.0.0" type="main">
              <s id="id.2.1.720.1.0">Se la corda ſi condurrà intorno alla girella della taglia, che ſia
                <lb/>
              attaccata di ſopra, & che vno delli ſuoi capi ſi leghi al peſo, &
                <lb/>
              l'altro tratanto ſia preſo dalla poſsanza, che ſoſtiene il detto
                <lb/>
              peſo; la poſsanza ſarà eguale al peſo. </s>
            </p>
          </chap>
        </body>
      </text>
    </archimedes>
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