Jordanus de Nemore, [Liber de ratione ponderis], 1565
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                <s id="id.2.11.00.01">Quaestio decima.
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                <s id="id.2.11.01.01">Si per diuersarum obliquitatum uias duo pondera descen­
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                dant, fiantque declinationum, et ponderum vna proportio, eo­
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                dem ordine sumpta vna erit utriusque uirtus in descendendo.
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                <s id="id.2.11.02.01">Sit linea a, b, c, aequedistans orizonti, et super
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                eam orthogonaliter erecta sit b, d, á qua descen
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                dant hinc, inde lineae d, a, d, c, sitque d, c, maioris
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                obliquitatis proportione igitur declinationum dico
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                non angulorum, sed linearum usque ad aequedistan
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                tem resecationem, in qua aequaliter sumunt de dire
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                cto. </s>
                <s id="id.2.11.02.02">Sit ergo e, pondus super d, c, et h, super d, a, et
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                sit e, ad b, sicut d, c, ad a, d. </s>
                <s id="id.2.11.02.03">Dico ea pondera esse vni­
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                us uirtutis in hoc situ, sit enim d, k, linea vnius ob­
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                liquitatis, cum d, c, et pondus super eam. </s>
                <s id="id.2.11.02.04">ergo aequa
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                le est e, quae sit 6. </s>
                <s id="id.2.11.02.05">Si igitur possibile est, descendat e,
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                in l, et trahat h, in m, sitque 6, n, aequale h, m, quod
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                etiam aequale est e, l, et transeat per 6. et h, perpen
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                dicularis, super d, b. </s>
                <s id="id.2.11.02.06">Sitque 6, h, y, et ab 1, sit l, t, sunt
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                et tunc super 6, h, y, n, z, m, x, et super l, t, erit e, r,
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                quia igitur proportio n, z, ad n, 6, sicut ad d, 6, d, y,
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                propter similitudinem triangulorum, et ideo sicut
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                d, b, ad d, k, et quia similiter m, x, ad m, h, sicut d,
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                b, ad d, a. </s>
                <s id="id.2.11.02.07">Erit propter aequalem proportionalitatem per
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                turbata m, x, ad n, z, sicut d, k, ad d, a, et hoc est
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                sicut 6, ad h, sed quia r, e, non sufficit attollere 6, in
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                n, nec sufficiet attollere m, in m, sic ergo manebunt.
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                <s id="id.2.12.00.01">Quaestio vndecima.
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                <s id="id.2.12.01.01">Quum sit responsa libre vnius ponderis,
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                et grossiciei per totum: et ipsa in pondere
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                data super inaequalia diuidatur, atque ex
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                parte breuiore dependeat aequabiliter pon­
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                dus datum, erunt et portiones, et regulae,
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                quae sunt a centro examinis similiter datae.
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                </s>
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                <s id="id.2.12.02.01">Sit responsa a, b, c, data in pondere, et aequalis in grossicie, et dependeat</s>
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