DelMonte, Guidubaldo, Le mechaniche

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    <archimedes>
      <text id="id.0.0.0.0.3">
        <body id="id.2.0.0.0.0">
          <chap id="N14EBE">
            <p id="id.2.1.966.0.0" type="main">
              <s id="N168C9">
                <pb pagenum="83" xlink:href="037/01/181.jpg"/>
                <emph type="italics"/>
              & l'altra in C: & l'vna, & l'altra inſieme ſoſteneſſe il peſo Q. </s>
              <s id="N168E0">La poſſanza
                <lb/>
              dunque di R è quattro volte tanto quanto il peſo Q. </s>
              <s id="N168E4">che biſognaua dimoſtrare.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.968.0.0" type="margin">
              <s id="id.2.1.968.1.0">
                <margin.target id="note252"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              16.
                <emph type="italics"/>
              di questo.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.969.0.0" type="margin">
              <s id="id.2.1.969.1.0">
                <margin.target id="note253"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              15.
                <emph type="italics"/>
              di questo.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.970.0.0" type="head">
              <s id="id.2.1.970.1.0">COROLLARIO</s>
            </p>
            <p id="id.2.1.971.0.0" type="main">
              <s id="id.2.1.971.1.0">Dalla qual coſa è manifeſto, che ſe la corda ſarà legata in G, &
                <lb/>
              riuolta d'intorno alle girelle, i cui centri ſono BCD; ſarà
                <lb/>
              la poſſanza di R che ſoſtiene quat
                <lb/>
              tro volte tanto, ſimilmente quan­
                <lb/>
              to il peſo Q. </s>
              <s id="N16920">Percioche la girel­
                <lb/>
              la il cui centro è A non fà nulla. </s>
            </p>
            <p id="id.2.1.972.0.0" type="main">
              <s id="id.2.1.972.1.0">Che ſe la poſſanza mouènte il peſo ſa
                <lb/>
              rà in R. </s>
              <s id="id.2.1.972.2.0">Dico lo ſpatio del peſo
                <lb/>
              moſſo eſſere quattro volte tanto
                <lb/>
              quanto lo ſpatio della poſſanza. </s>
            </p>
            <figure id="id.037.01.181.2.jpg" xlink:href="037/01/181/2.jpg" number="169"/>
            <p id="id.2.1.974.0.0" type="main">
              <s id="id.2.1.974.1.0">
                <emph type="italics"/>
              Siano moſſi i centri CD delle girelle fin ad ST;
                <lb/>
              ſaranno per le coſe di ſopra dette CS DT
                <lb/>
              eguali allo ſpatio della poſſanza; & per SDT
                <lb/>
              ſiano condotte le linee HK VX NO
                <foreign lang="grc">Υ</foreign>
              Z
                <lb/>
              egualmente diſtanti dall'orizonte; & mentre
                <lb/>
              li centri CD ſono in ST, ſia il peſo Q,
                <lb/>
              cioè il punto P moſſo in
                <foreign lang="el">*s</foreign>
              . </s>
              <s id="id.2.1.974.2.0">& percioche
                <lb/>
              la corda EFGHKLMNOP eguale è al
                <lb/>
              la corda EFGVXLM
                <foreign lang="grc">Υ</foreign>
              Z
                <foreign lang="el">*s</foreign>
              ; eſſendo vna
                <lb/>
              medeſima corda: & le corde poſte d'intorno à
                <lb/>
              mezi cerchi NIOH
                <foreign lang="grc">α</foreign>
              K ſiano eguali alle cor
                <lb/>
              de, lequali ſono intorno à i mezi cerchi
                <foreign lang="grc">Υδ</foreign>
              Z
                <lb/>
              V
                <foreign lang="grc">β</foreign>
              X; tolte via dunque le communi EFGH
                <lb/>
              KLMN & O
                <foreign lang="el">*s</foreign>
              ; ſarà P
                <foreign lang="el">*s</foreign>
              eguale ad eſſe
                <lb/>
              N
                <foreign lang="grc">Υ</foreign>
              ZO VH XK inſieme preſe, ma le quat
                <lb/>
              tro N
                <foreign lang="grc">Υ</foreign>
              ZO VH XK tutte inſieme ſono
                <lb/>
              quattro volte tanto quanto DT cioè lo ſpa­
                <lb/>
              tio della poſſanza. </s>
              <s id="id.2.1.974.3.0">Lo ſpatio dunque PQ del
                <lb/>
              peſo è quattro volte tanto quanto lo ſpatio
                <lb/>
              della poſſanza. </s>
              <s id="id.2.1.974.4.0">che era da moſtrarſi.
                <emph.end type="italics"/>
              </s>
            </p>
          </chap>
        </body>
      </text>
    </archimedes>
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