Angeli, Stefano degli, Della gravita' dell' aria e fluidi : esercitata principalmente nelli loro homogenei

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            <s xml:id="echoid-s5616" xml:space="preserve">
              <pb o="92" file="00186" n="186" rhead="DIALOGO"/>
            A, al peſo B. </s>
            <s xml:id="echoid-s5617" xml:space="preserve">Da ciò ne naſce il beneſitio, che ne cauiamo
              <lb/>
            dalla leua; </s>
            <s xml:id="echoid-s5618" xml:space="preserve">cioè che con poca forza potemo ſoſtenere vn
              <lb/>
            gran peſo, ogni qual volta applichiamo la forza alla parte
              <lb/>
            maggiore. </s>
            <s xml:id="echoid-s5619" xml:space="preserve">Per eſempio ſia AC, centupla di CB; </s>
            <s xml:id="echoid-s5620" xml:space="preserve">vna forza
              <lb/>
            in A, valeuole, ſenza la leua, a ſoſtenere vn peſo d’vna lib-
              <lb/>
            bra; </s>
            <s xml:id="echoid-s5621" xml:space="preserve">potrà mediāte la leua ſoſtenere vn peſo di libb. </s>
            <s xml:id="echoid-s5622" xml:space="preserve">100. </s>
            <s xml:id="echoid-s5623" xml:space="preserve">col
              <lb/>
            locato in B. </s>
            <s xml:id="echoid-s5624" xml:space="preserve">Onde queſta forza accreſciuta ogni pochino,
              <lb/>
            non ſolo lo ſoſtenirà, ma anco l’alzerà.</s>
            <s xml:id="echoid-s5625" xml:space="preserve"/>
          </p>
          <p>
            <s xml:id="echoid-s5626" xml:space="preserve">_Mat_. </s>
            <s xml:id="echoid-s5627" xml:space="preserve">Ma ſe le braccia AC, CB, della leua ſaranno vguali, che
              <lb/>
            beneſitio ne caueremo da eſſa?</s>
            <s xml:id="echoid-s5628" xml:space="preserve"/>
          </p>
          <p>
            <s xml:id="echoid-s5629" xml:space="preserve">_Ofr_ Niuno certamente per queſto capo. </s>
            <s xml:id="echoid-s5630" xml:space="preserve">Perche in queſto ca-
              <lb/>
            ſo quanto ſarà il peſo, tanta forza vi vorrà a ſoſtenerlo, e
              <lb/>
            maggiore ad alzarlo. </s>
            <s xml:id="echoid-s5631" xml:space="preserve">Onde tanto ſarà alzarlo con la leua,
              <lb/>
            come ſenza eſſa.</s>
            <s xml:id="echoid-s5632" xml:space="preserve"/>
          </p>
          <p>
            <s xml:id="echoid-s5633" xml:space="preserve">_Mat_. </s>
            <s xml:id="echoid-s5634" xml:space="preserve">E ſe la leua ſarà de braccia ineguali, e nel fine del mag-
              <lb/>
            giore come in A, collocaremo il peſo, e la forza in B, che
              <lb/>
            vtile n’haueremo?</s>
            <s xml:id="echoid-s5635" xml:space="preserve"/>
          </p>
          <p>
            <s xml:id="echoid-s5636" xml:space="preserve">_Ofr_. </s>
            <s xml:id="echoid-s5637" xml:space="preserve">Non vtile, ma danno; </s>
            <s xml:id="echoid-s5638" xml:space="preserve">perche ſe A C, ſarà centupla di C B,
              <lb/>
            a ſoſtenere vna libbra dipeſo poſto in A, vi vorrà forza
              <lb/>
            equiualente a libbre 100. </s>
            <s xml:id="echoid-s5639" xml:space="preserve">poſta in B, per ſoſtenerlo. </s>
            <s xml:id="echoid-s5640" xml:space="preserve">E pure
              <lb/>
            ad alzarlo ſenza leua vi vorra forza poco più d’vna libbra,
              <lb/>
            come à ſoſtenerlo d’vna libbra ſolamente.</s>
            <s xml:id="echoid-s5641" xml:space="preserve"/>
          </p>
          <p>
            <s xml:id="echoid-s5642" xml:space="preserve">_Mat._ </s>
            <s xml:id="echoid-s5643" xml:space="preserve">Tutte queſte dottrine V. </s>
            <s xml:id="echoid-s5644" xml:space="preserve">S. </s>
            <s xml:id="echoid-s5645" xml:space="preserve">l’hà cauate dalle viſcere delle
              <lb/>
            mecaniche. </s>
            <s xml:id="echoid-s5646" xml:space="preserve">Hora in vece della leua A B, conſideriamo la.
              <lb/>
            </s>
            <s xml:id="echoid-s5647" xml:space="preserve">D A B, ancinata, & </s>
            <s xml:id="echoid-s5648" xml:space="preserve">angolara rettamente, & </s>
            <s xml:id="echoid-s5649" xml:space="preserve">imaginiamo
              <lb/>
            che D A, ſia linea retta collocata nell’orizonte, e A B, ſopra
              <lb/>
            eſſo perpendicolare; </s>
            <s xml:id="echoid-s5650" xml:space="preserve">immaginiamo parimente che in D,
              <lb/>
            ſia poſto il peſo, & </s>
            <s xml:id="echoid-s5651" xml:space="preserve">in B la forza. </s>
            <s xml:id="echoid-s5652" xml:space="preserve">Allora il ſoſtentacolo del-
              <lb/>
            la leua ſarà il punto A; </s>
            <s xml:id="echoid-s5653" xml:space="preserve">e parimente la forza in B, al peſo in
              <lb/>
            D, hauerà la proportione, che ha reciprocamente D A, ad
              <lb/>
            AB. </s>
            <s xml:id="echoid-s5654" xml:space="preserve">In queſto caſo quali benefitii ne sõminiſtrerà la leua?</s>
            <s xml:id="echoid-s5655" xml:space="preserve"/>
          </p>
          <p>
            <s xml:id="echoid-s5656" xml:space="preserve">_Ofred._ </s>
            <s xml:id="echoid-s5657" xml:space="preserve">Li medemi che l’altra prima A B, orizontale. </s>
            <s xml:id="echoid-s5658" xml:space="preserve">Se B A, ſa-
              <lb/>
            rà maggiore d’ A D, quanto più eccederà, con tanto minor
              <lb/>
            forza B, potremo alzare il peſo D. </s>
            <s xml:id="echoid-s5659" xml:space="preserve">Se D A, A B, ſaranno
              <lb/>
            vguali, vi vorrà tanta forza quanto peſo. </s>
            <s xml:id="echoid-s5660" xml:space="preserve">E ſe D A, ſarà
              <lb/>
            maggior d’A B, vi vorrà più forza che non è il detto peſo.</s>
            <s xml:id="echoid-s5661" xml:space="preserve"/>
          </p>
          <p>
            <s xml:id="echoid-s5662" xml:space="preserve">_Cont._ </s>
            <s xml:id="echoid-s5663" xml:space="preserve">Queſta ſorte di leua adoperiamo quando con il martel-
              <lb/>
            lo vogliamo cauare vn chiodo fitto nel muro, ò in </s>
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