Casati, Paolo, Fabrica, et uso del compasso di proportione, dove insegna à gli artefici il modo di fare in esso le necessarie divisioni, e con varij problemi ...

Table of figures

< >
[Figure 51]
[Figure 52]
[Figure 53]
[Figure 54]
[Figure 55]
[Figure 56]
[Figure 57]
[Figure 58]
[Figure 59]
[Figure 60]
[Figure 61]
[Figure 62]
[Figure 63]
[Figure 64]
[Figure 65]
[Figure 66]
[Figure 67]
[Figure 68]
[Figure 69]
[Figure 70]
[Figure 71]
[Figure 72]
[Figure 73]
[Figure 74]
[Figure 75]
< >
page |< < (171) of 279 > >|
    <echo version="1.0RC">
      <text xml:lang="it" type="free">
        <div xml:id="echoid-div100" type="section" level="1" n="54">
          <p>
            <s xml:id="echoid-s3196" xml:space="preserve">
              <pb o="171" file="0187" n="190" rhead="Gradi del Circolo"/>
            80. </s>
            <s xml:id="echoid-s3197" xml:space="preserve">aggiontigradi 28, tutto l’arco BD, e per conſeguenzala
              <lb/>
            quantità dell’angolo dato BAD, ègr. </s>
            <s xml:id="echoid-s3198" xml:space="preserve">108.</s>
            <s xml:id="echoid-s3199" xml:space="preserve"/>
          </p>
        </div>
        <div xml:id="echoid-div102" type="section" level="1" n="55">
          <head xml:id="echoid-head98" xml:space="preserve">QVESTIONE TERZA.</head>
          <head xml:id="echoid-head99" style="it" xml:space="preserve">come con lo Stromento ſi poſa pratticare tutta la Trigonometria
            <lb/>
          ſenza Tauole.</head>
          <p>
            <s xml:id="echoid-s3200" xml:space="preserve">SE Bene di queſto ſi parlò qualche coſa nel cap. </s>
            <s xml:id="echoid-s3201" xml:space="preserve">2. </s>
            <s xml:id="echoid-s3202" xml:space="preserve">Queſt.
              <lb/>
            </s>
            <s xml:id="echoid-s3203" xml:space="preserve">6, ad ogni modo ſarà meglio più vniuerſalmente ſpie-
              <lb/>
            gare quì l’vſo dello Stromento nella ſolutione prattica de’
              <lb/>
            triangoli, e ſeruirà per quelli che non ſi curano di tanta pre-
              <lb/>
            ciſione, quanta oprando co’numeri ſi troua coforme alle re-
              <lb/>
            gole della Trigonometria.</s>
            <s xml:id="echoid-s3204" xml:space="preserve"/>
          </p>
          <p>
            <s xml:id="echoid-s3205" xml:space="preserve">E quì ſuppongo ciò che è noto, che delle ſei parti, cioè di
              <lb/>
            tre lati, etre angoli, che ſono in vn triangolo, conuien ſaper-
              <lb/>
            ne tre, per conoſcere l’altre tre. </s>
            <s xml:id="echoid-s3206" xml:space="preserve">Se ſono datitutti tre gl’an-
              <lb/>
            goli, non ſi può conoſcere, quanta ſia la longhezza de’lati,
              <lb/>
            ma ſolo la proportione, che li lati hanno tra di loro, eſſendo-
              <lb/>
            che li triangoli equiangoli, eſimili tra di loro, hanno ben ſi i
              <lb/>
            lati proportionali, ma non vguali. </s>
            <s xml:id="echoid-s3207" xml:space="preserve">Onde ſe ſaranno dati tre
              <lb/>
              <figure xlink:label="fig-0187-01" xlink:href="fig-0187-01a" number="54">
                <image file="0187-01" xlink:href="http://echo.mpiwg-berlin.mpg.de/zogilib?fn=/permanent/library/xxxxxxxx/figures/0187-01"/>
              </figure>
            angoli d’vn triangolo, facciaſi qualunque
              <lb/>
            triangolo con detti tre angoli, enella linea
              <lb/>
            Aritmet. </s>
            <s xml:id="echoid-s3208" xml:space="preserve">applicato vno de’lati all’interuallo,
              <lb/>
            che più piacerà, ſi troueranno gl’altri, e ſarà
              <lb/>
            manifeſta la lor proportione. </s>
            <s xml:id="echoid-s3209" xml:space="preserve">Siano litte
              <lb/>
            angoli dati gr. </s>
            <s xml:id="echoid-s3210" xml:space="preserve">25. </s>
            <s xml:id="echoid-s3211" xml:space="preserve">m. </s>
            <s xml:id="echoid-s3212" xml:space="preserve">20, gr. </s>
            <s xml:id="echoid-s3213" xml:space="preserve">19. </s>
            <s xml:id="echoid-s3214" xml:space="preserve">m. </s>
            <s xml:id="echoid-s3215" xml:space="preserve">40, gradi
              <lb/>
            135. </s>
            <s xml:id="echoid-s3216" xml:space="preserve">Sopra la linea RT, faccio l’angolo
              <lb/>
            TRC gr. </s>
            <s xml:id="echoid-s3217" xml:space="preserve">25. </s>
            <s xml:id="echoid-s3218" xml:space="preserve">m. </s>
            <s xml:id="echoid-s3219" xml:space="preserve">20, el’angolo RTC digradi
              <lb/>
            19. </s>
            <s xml:id="echoid-s3220" xml:space="preserve">m. </s>
            <s xml:id="echoid-s3221" xml:space="preserve">40, ecosì rieſce il terzo angolo </s>
          </p>
        </div>
      </text>
    </echo>