Casati, Paolo, Fabrica, et uso del compasso di proportione, dove insegna à gli artefici il modo di fare in esso le necessarie divisioni, e con varij problemi ...

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          <p>
            <s xml:id="echoid-s3252" xml:space="preserve">
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            oppoſto ad vn di loro; </s>
            <s xml:id="echoid-s3253" xml:space="preserve">e ſimilmente ò è l’angolo compreſo
              <lb/>
            dalli due lati dati, ouero oppoſto ad vno di detti lati.</s>
            <s xml:id="echoid-s3254" xml:space="preserve"/>
          </p>
          <p>
            <s xml:id="echoid-s3255" xml:space="preserve">Sia dato vn lato, e gl’angoli adiacenti; </s>
            <s xml:id="echoid-s3256" xml:space="preserve">ſia AB parte delſa
              <lb/>
            riua d’vn fiume, conoſciuta in miſura di piedi 90; </s>
            <s xml:id="echoid-s3257" xml:space="preserve">e ſi deſideri
              <lb/>
            ſapere la diſtanza AC, che trauerſa il fiume. </s>
            <s xml:id="echoid-s3258" xml:space="preserve">Sia oſſeruato in
              <lb/>
            A l’angolo CAB, di gradi 78, & </s>
            <s xml:id="echoid-s3259" xml:space="preserve">in B l’angolo ABC di gradi
              <lb/>
            35; </s>
            <s xml:id="echoid-s3260" xml:space="preserve">deſcriuo nell’eſtremità della linea AB li due angoli con-
              <lb/>
            forme alle ſopradette miſure oſſeruate, cioè ABC gr. </s>
            <s xml:id="echoid-s3261" xml:space="preserve">35, e
              <lb/>
            BAC gr. </s>
            <s xml:id="echoid-s3262" xml:space="preserve">78; </s>
            <s xml:id="echoid-s3263" xml:space="preserve">onde le linee BC, AC ſi rincontrano in C. </s>
            <s xml:id="echoid-s3264" xml:space="preserve">Ap-
              <lb/>
            plicata dunque la linea AB sù la linea Aritmetica alli punti
              <lb/>
            90. </s>
            <s xml:id="echoid-s3265" xml:space="preserve">90, trouo, che AC cade nell’interuallo 56. </s>
            <s xml:id="echoid-s3266" xml:space="preserve">56, dal che cõ-
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              <figure xlink:label="fig-0189-01" xlink:href="fig-0189-01a" number="55">
                <image file="0189-01" xlink:href="http://echo.mpiwg-berlin.mpg.de/zogilib?fn=/permanent/library/xxxxxxxx/figures/0189-01"/>
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            chiudo, che la diſtanza dal
              <lb/>
            punto A al punto C, che tra-
              <lb/>
            uerſa il fiume è di piedi 56:
              <lb/>
            </s>
            <s xml:id="echoid-s3267" xml:space="preserve">e così la diſtanza BC è di
              <lb/>
            piedi 95 {1/2}.</s>
            <s xml:id="echoid-s3268" xml:space="preserve"/>
          </p>
          <p>
            <s xml:id="echoid-s3269" xml:space="preserve">Mà ſe foſſe dato illato A
              <lb/>
            B con l’angolo B adiacente,
              <lb/>
            e l’angolo C oppoſto, ſarà
              <lb/>
            anche noto il terzo angolo
              <lb/>
            A, che è complemento alli
              <lb/>
            due retti; </s>
            <s xml:id="echoid-s3270" xml:space="preserve">e così ſi deſcriuerà la figura, come ſe foſſe dato il
              <lb/>
            lato con li due angoli B, & </s>
            <s xml:id="echoid-s3271" xml:space="preserve">A adiacenti, e s’operarà, come
              <lb/>
            poco fà ſi diceua.</s>
            <s xml:id="echoid-s3272" xml:space="preserve"/>
          </p>
          <p>
            <s xml:id="echoid-s3273" xml:space="preserve">Ora ſian dati due lati con l’angolo compreſo: </s>
            <s xml:id="echoid-s3274" xml:space="preserve">deſcriuaſi
              <lb/>
            l’angolo dato, come s’è detto nella prima Queſtione, e ſi
              <lb/>
            prenda la lunghezza de’lati proportionata à ilati dati; </s>
            <s xml:id="echoid-s3275" xml:space="preserve">poile
              <lb/>
            eſtremità de’lati ſi congiungano, e s’haurà il triangolo, in cui
              <lb/>
            ſi conoſceranno l’altre parti, come ſopra. </s>
            <s xml:id="echoid-s3276" xml:space="preserve">Sia nella figura
              <lb/>
            antecedente, dato l’angolo compreſo dalli lati dati di gr. </s>
            <s xml:id="echoid-s3277" xml:space="preserve">25.</s>
            <s xml:id="echoid-s3278" xml:space="preserve"/>
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