Valerio, Luca
,
De centro gravitatis solidorum
,
1604
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[Figure 191]
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[Figure 192]
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[Figure 195]
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[Figure 196]
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[Figure 197]
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LM altitudo autem eadem priſmati HKF, hoc eſt priſma
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ACGLFM illi æquale per vltimam XI. elem. </
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HKF: vt igitur prima cum quinta, rectangulum DGE
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vna cum quadrato EG, hoc eſt rectangulum DEG, ad
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ſecundam quadratum DE, ita erit tertia cum ſexta, duo
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priſmata BGL, ACGLFM, ad quartam priſma HKF.
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>Præterea quoniam vt quadratum DG ad quadratum
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DE, ita erat triangulum DGM ad triangulum DEF: ſed
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vt triangulum DGM ad triangulum DEF, ita eſt priſma,
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HGM, ad priſma HKF: & tertiæ antecedentium par
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tes, videlicet, vt tertia pars quadrati DG, ad quadra
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tum DE, ita pyramis ADGM ad priſma HKF: ſed
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vt rectangulum DEG ad DE quadratum, ita erant duo
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priſmata BGL, ACGLFM, ad priſma HKF; vt igi
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tur prima cum quinta, rectangulum DEG vna cum ter
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tia parte DG quadrati, ad quadratum GD ſecundam,
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ita erit tertia cum ſexta, duo priſmata BGL, ACGLFM
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vna cum pyramide ADGM, hoc eſt integrum fruſtum
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ABCDEF ad priſma HKF quartam. </
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cunda pars propoſiti. </
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>Quoniam enim eſt vt rectangulum
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DEG, vna cum tertia parte quadrati DG, ad quadra
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tum DE, ita fruſtum ABGDEF ad priſma HKF: vt
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autem quadratum DE, ad tertiam ſui partem, ita eſt priſ
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ma HKF ad pyramidem, cuius baſis triangulum DEF,
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altitudo eadem priſmati HKF; erit ex æquali vt re
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ctangulum DEG vna cum tertia parte quadrati DG
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ad tertiam partem quadrati DE, ita fruſtum ABCDEF,
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ad pyramidem ſi compleatur ADEF. </
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igitur propoſitum. </
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