DelMonte, Guidubaldo, Le mechaniche

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          <chap id="N14EBE">
            <pb pagenum="92" xlink:href="037/01/199.jpg"/>
            <p id="id.2.1.1067.0.0" type="head">
              <s id="id.2.1.1067.1.0">PROPOSITIONE XXIIII. </s>
            </p>
            <p id="id.2.1.1068.0.0" type="main">
              <s id="id.2.1.1068.1.0">Se à tre girelle di due taglie, l'vna delle quali, che habbia vna gi
                <lb/>
              rella ſolamente ſia ſoſtenuta di ſopra dalla poſſanza, & l'altra
                <lb/>
              poſta di ſotto con due girelle, & legata al peſo, ſarà girata in­
                <lb/>
              torno la corda: eſſendo li due ſuoi capi
                <expan abbr="legat">legati</expan>
              in qualche luo
                <lb/>
              go, ma non già nella taglia di ſopra: il peſo ſarà il doppio del
                <lb/>
              la poſſanza. </s>
            </p>
            <p id="id.2.1.1069.0.0" type="main">
              <s id="id.2.1.1069.1.0">
                <emph type="italics"/>
              Siano AB i centri delle girelle della
                <lb/>
              taglia legata al peſo C: & il D
                <lb/>
              ſia il centro della girella di ſopra;
                <lb/>
              ſia dapoi la corda riuolta d'intorno
                <lb/>
              à tutte le girelle, & rilegata in EF;
                <lb/>
              & ſia in G la poſſanza, che ſo­
                <lb/>
              ſtiene il peſo C. </s>
              <s id="id.2.1.1069.2.0">Dico, che il peſo
                <lb/>
              C è due volte tanto quanto la
                <lb/>
              poſſanza G. </s>
              <s id="id.2.1.1069.3.0">Hor percioche ſe in
                <lb/>
              HK foſſero due poſſanze, che ſo­
                <lb/>
              ſteneſſero il peſo con due corde ri­
                <lb/>
              uolte d'intorno alle girelle ſolamen
                <lb/>
              te della taglia di ſotto, ſarebbe per
                <lb/>
              certo l'vna & l'altra poſſanza po­
                <emph.end type="italics"/>
                <arrow.to.target n="note269"/>
                <lb/>
                <emph type="italics"/>
              ſta in KH vn quarto del peſo C;
                <lb/>
              Ma la poſſanza di G è eguale alle
                <lb/>
              poſſanze di HK preſe inſieme:
                <emph.end type="italics"/>
                <arrow.to.target n="note270"/>
                <lb/>
                <emph type="italics"/>
              percioche è due volte tanto quan­
                <lb/>
              to ciaſcuna delle poſſanze di H,
                <lb/>
              & K; ſarà la poſſanza di G la
                <lb/>
              metà del peſo C. </s>
              <s id="N17267">il peſo dunque
                <lb/>
              ſarà il doppio della poſſanza. </s>
              <s id="id.2.1.1069.4.0">che
                <lb/>
              biſognaua moſtrare.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.1070.0.0" type="margin">
              <s id="id.2.1.1070.1.0">
                <margin.target id="note269"/>
                <emph type="italics"/>
              Dalla
                <emph.end type="italics"/>
              7.
                <emph type="italics"/>
              di questo.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.1071.0.0" type="margin">
              <s id="id.2.1.1071.1.0">
                <margin.target id="note270"/>
                <emph type="italics"/>
              Dalla
                <emph.end type="italics"/>
              15.
                <emph type="italics"/>
              di questo.
                <emph.end type="italics"/>
              </s>
            </p>
            <figure id="id.037.01.199.1.jpg" xlink:href="037/01/199/1.jpg" number="184"/>
          </chap>
        </body>
      </text>
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