Valerio, Luca, De centro gravitatis solidorvm libri tres

Table of figures

< >
[Figure 51]
[Figure 52]
[Figure 53]
[Figure 54]
[Figure 55]
[Figure 56]
[Figure 57]
[Figure 58]
[Figure 59]
[Figure 60]
[Figure 61]
[Figure 62]
[Figure 63]
[Figure 64]
[Figure 65]
[Figure 66]
[Figure 67]
[Figure 68]
[Figure 69]
[Figure 70]
[Figure 71]
[Figure 72]
[Figure 73]
[Figure 74]
[Figure 75]
[Figure 76]
[Figure 77]
[Figure 78]
[Figure 79]
[Figure 80]
< >
page |< < of 283 > >|
    <archimedes>
      <text>
        <body>
          <chap>
            <p type="main">
              <s>
                <pb xlink:href="043/01/021.jpg" pagenum="13"/>
              EF. quæ ſuntin latera homologa duorum triangulorum
                <lb/>
              ABC, DEF. </s>
              <s>Ex definitione igitur, duo puncta G, H,
                <lb/>
              in triangulis ABC, DEF, ſimiliter poſita erunt. </s>
              <s>At
                <lb/>
              enim ſi fieri poteſt ſit aliud punctum K, in triangulo
                <lb/>
              DEF, ſimiliter poſitum puncto G. </s>
              <s>Vel igitur punctum
                <lb/>
              K in aliquo triangulorum, quorum eſt communis vertex
                <lb/>
              H, vel in aliquo eorundem latere cadet. </s>
              <s>cadat in latere
                <lb/>
              FH, & iungatur DK: triangulum ergo DFK, ſimile
                <lb/>
              erit triangulo ACG. </s>
              <s>Sed & triangulum EDF, ſimile
                <lb/>
              eſt triangulo BAC; vtraque igitur horum ad illorum ſi­
                <lb/>
              bi reſpondens triangulorum duplicatam eorundem late­
                <lb/>
              rum homologorum AC, DF, habebunt proportionem:
                <lb/>
              vt igitur eſt triangulum EDF, ad triangulum BAC, ita
                <lb/>
              erit triangulum DFK, ad triangulum ACG: & per­
                <lb/>
              mutando, vt triangulum ACG, ad triangulum ABC,
                <lb/>
              ita triangulum DFK, ad triangulum EDF: eadem ra­
                <lb/>
              tione, vt triangulum ACG, ad triangulum ABC, ita
                <lb/>
              erit triangulum DFH, ad triangulum DEF: vt igitur
                <lb/>
              triangulum DFK, ad triangulum EDF; ita erit trian­
                <lb/>
              gulum DFH, ad triangulum EDF; triangulum ergo
                <lb/>
              DFK, triangulo DFH, æquale erit, pars toti, quod eſt
                <lb/>
              abſurdum: idem autem abſurdum ſequeretur, ſi punctum
                <lb/>
                <emph type="italics"/>
              K
                <emph.end type="italics"/>
              , poneretur in aliquo prædictorum triangulorum, vt in
                <lb/>
              triangulo DFH; Non igitur aliud punctum à puncto H,
                <lb/>
              in triangulo EDF, ſimiliter poſitum erit puncto G.
                <lb/>
              </s>
              <s>Quod demonſtrandum erat. </s>
            </p>
            <p type="head">
              <s>
                <emph type="italics"/>
              PROPOSITIO V.
                <emph.end type="italics"/>
              </s>
            </p>
            <p type="main">
              <s>Cuilibet figuræ planæ rectangulum æquale
                <lb/>
              poteſt eſſe. </s>
            </p>
          </chap>
        </body>
      </text>
    </archimedes>