Gravesande, Willem Jacob 's, An essay on perspective

Table of contents

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[131.] Operation.
[132.] Demonstration.
[133.] Remark.
[134.] Problem IV.
[135.] Problem V.
[136.] Operation.
[137.] Demonstration.
[138.] Problem VI.
[139.] Method II.
[140.] Operation.
[141.] Demonstration.
[142.] Method III.
[143.] CHAP. VI.
[144.] Prob. I.
[145.] Prob. II.
[146.] Demonstration.
[147.] Corollary.
[148.] Method II.
[149.] Operation,
[150.] Demonstration.
[151.] Remarks.
[152.] Method III.
[153.] Operation.
[154.] Demonstration.
[155.] H I: T H:: a X: a T.
[156.] Prob. III.
[157.] Operation.
[158.] Demonstration.
[159.] Prob. IV.
[160.] Method II.
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page |< < (109) of 237 > >|
214109on PERSPECTIVE. ved backwards or forwards, or elſe the Looking-
glaſs raiſed or lower’d, until the Rays proceed-
ing from the Statue may be reflected by the Mir-
rour upon the Convex Glaſs.
When theſe Alte-
rations of the Box, or Mirrour, are not ſufficient to
throw the Rays upon the Convex Glafs, the whole
Machine muſt be removed backwards or for-
wards.
Demonstration.
Concerning the before-mention’d Inclination of the
Mirrours.
19. In order to demonſtrate, that the Mirrour
L hath been conveniently inclin’d, we need on-
ly prove, that the reflected Rays fall upon the
Table A under the ſame Angle, as the direct
Rays do upon a Plane, having the ſame Situation
as one would give to the Picture.
Now let A B be a Ray falling from a Point of
11Fig. 71. ſome Object upon the Mirrour G H, and from
thence is reflected in the Point a upon the Table
of the Machine:
We are to demonſtrate, that if
the Line D I be drawn, making an Angle with
FE equal to the Inclination of the Picture;
that
is, if the Angle DIE be the double of the 2215, 16. D F I;
I ſay, we are to demonſtrate, that the
Angle B a f is equal to the Angle BCD.
The Angle DIE, by Conſtruction, is the double
of the Angle DFI;
and conſequently this laſt Angle
is equal to the Angle I D F;
and ſince the Angle
of Incidence C B D is equal to the Angle of Re-
flection a B F, the Triangle BCD is ſimilar to
the Triangle F a B:
Whence it follows, that the
Angle Ba F is equal to the Angle BCD.
Which
was to be demonſtrated.

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