DelMonte, Guidubaldo, Le mechaniche

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        <body id="id.2.0.0.0.0">
          <chap id="N17D85">
            <pb pagenum="106" xlink:href="037/01/227.jpg"/>
            <p id="id.2.1.1221.0.0" type="head">
              <s id="id.2.1.1221.1.0">COROLLARIO. </s>
            </p>
            <p id="id.2.1.1222.0.0" type="main">
              <s id="id.2.1.1222.1.0">Da queſte coſe è manifeſto, che quanto più ageuolmente ſi mo
                <lb/>
              ue il peſo, tanto il tempo è anco maggiore; & quanto più ma­
                <lb/>
              lageuolmente, tanto il tempo eſſere minore. </s>
              <s id="id.2.1.1222.2.0">& coſi per lo
                <lb/>
              contrario. </s>
            </p>
            <p id="id.2.1.1223.0.0" type="head">
              <s id="id.2.1.1223.1.0">PROPOSITIONE II. </s>
            </p>
            <p id="id.2.1.1224.0.0" type="head">
              <s id="id.2.1.1224.1.0">PROBLEMA. </s>
            </p>
            <p id="id.2.1.1225.0.0" type="main">
              <s id="id.2.1.1225.1.0">Far che ſi moua vn dato peſo, con l'aſſe nella rota da vna data
                <lb/>
              poſſanza. </s>
            </p>
            <p id="id.2.1.1226.0.0" type="main">
              <s id="id.2.1.1226.1.0">
                <emph type="italics"/>
              Sia il dato peſo ſeſſanta, & la poſſanza come dieci. </s>
              <s id="id.2.1.1226.2.0">Facciaſi vna linea retta AB, laquale
                <lb/>
              ſi diuida in C, ſi fattamente che AC habbia la proportione iſteſſa à CB, che ha
                <lb/>
              ſeſſanta à diece. </s>
              <s id="id.2.1.1226.3.0">& ſe CB
                <lb/>
              foſſe il mezo diametro del­
                <lb/>
              l'aſſe, & CA il mezo dia
                <emph.end type="italics"/>
                <arrow.to.target n="note306"/>
                <lb/>
                <emph type="italics"/>
              metro della rota co'raggi;
                <lb/>
              egli è chiaro, che la poſſan­
                <lb/>
              za come dieci poſta in A
                <emph.end type="italics"/>
                <arrow.to.target n="note307"/>
                <lb/>
                <emph type="italics"/>
              peſerebbe egualmente co'l
                <emph.end type="italics"/>
                <lb/>
                <figure id="id.037.01.227.1.jpg" xlink:href="037/01/227/1.jpg" number="205"/>
                <lb/>
                <emph type="italics"/>
              peſo ſeſſanta poſto in B. </s>
              <s id="id.2.1.1226.4.0">ma pigliſi tra BC qual ſi voglia punto, & ſia D; &
                <lb/>
              facciaſi BD il mezo diametro dell'aſſe, & DA il mezo diametro della rota co'rag
                <lb/>
              gi, & pongaſi il peſo ſeſſanta in B con vna corda inuolta d'intorno all'aſſe, & la poſ
                <emph.end type="italics"/>
                <arrow.to.target n="note308"/>
                <lb/>
                <emph type="italics"/>
              ſanza in A. </s>
              <s id="id.2.1.1226.5.0">Hor percioche AD ha proportione maggiore à DB, che AC à
                <lb/>
              CB: haurà proportione maggiore AD à DB, che il peſo ſeſſanta appiccato in
                <lb/>
              B alla poſſanza di dieci posta in A. </s>
              <s id="id.2.1.1226.6.0">Per laqual coſa la poſſanza di A mouerà il
                <lb/>
              peſo di ſeſſanta con l'aſſe nella rota, il mezo diametro delquale è BD, & DA è
                <lb/>
              il mezo diametro della rota co'raggi. </s>
              <s id="id.2.1.1226.7.0">ilche era da farſi.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.1229.0.0" type="margin">
              <s id="id.2.1.1229.1.0">
                <margin.target id="note306"/>
                <emph type="italics"/>
              Per la precedente.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.1230.0.0" type="margin">
              <s id="id.2.1.1230.1.0">
                <margin.target id="note307"/>
                <emph type="italics"/>
              Per il lemma nella prima di questo della leua.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.1231.0.0" type="margin">
              <s id="id.2.1.1231.1.0">
                <margin.target id="note308"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              11.
                <emph type="italics"/>
              di questo della leua.,
                <emph.end type="italics"/>
              </s>
            </p>
          </chap>
        </body>
      </text>
    </archimedes>
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