DelMonte, Guidubaldo, Le mechaniche

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    <archimedes>
      <text id="id.0.0.0.0.3">
        <body id="id.2.0.0.0.0">
          <chap id="N181D6">
            <pb xlink:href="037/01/236.jpg"/>
            <p id="id.2.1.1267.0.0" type="main">
              <s id="id.2.1.1267.1.0">Hora moſtriamo in che modo, quelle coſe lequali ſono feſſe, ſi
                <lb/>
              mouano come ſopra piani inchinati all'orizonte. </s>
            </p>
            <p id="id.2.1.1268.0.0" type="main">
              <s id="id.2.1.1268.1.0">
                <emph type="italics"/>
              Sia il cuneo ABC, & AB ſia eguale ad eſſa BC. </s>
              <s id="id.2.1.1268.2.0">Diuidaſi AC in due parti in
                <lb/>
              D, & ſia congiunta BD. </s>
              <s id="N18423">ſia dopo la linea EF, per laquale paßi il piano egual­
                <lb/>
              mente diſtante dall'orizonte, & ſia BD nella medeſima linea EF; & mentre il
                <emph.end type="italics"/>
                <lb/>
                <figure id="id.037.01.236.1.jpg" xlink:href="037/01/236/1.jpg" number="213"/>
                <lb/>
                <emph type="italics"/>
              cuneo è percoſſo, & mentre ſi moue in verſo E, ſempre BD ſia nella linea EF. </s>
              <s id="N18433">
                <lb/>
              & quel che ſi ha da fendere ſia GHLM, dentro alquale ſia la parte del cuneo
                <lb/>
              KBI: egli è manifeſto, che mentre il cuneo ſi moue in verſo E, la parte KG mo­
                <lb/>
              uerſi in verſo N; & la parte HI in verſo O. </s>
              <s id="id.2.1.1268.3.0">percotaſi il cuneo per modo che la
                <lb/>
              linea AC ſia nella linea NO; allhora K ſarà in A, & I in C: & K per le
                <lb/>
              coſe ſudette ſarà moſſo ſopra KA, & I ſopra IC. </s>
              <s id="id.2.1.1268.4.0">Per laqual coſa mentre ſi mo
                <lb/>
              ue il cuneo, la parte KG ſi mouerà ſopra il lato BA del cuneo, & la parte IH
                <lb/>
              ſopra il lato BC. </s>
              <s id="id.2.1.1268.5.0">La parte dunque KG ſi mouerà ſopra il piano inchinato all'o­
                <lb/>
              rizonte, la cui inclinatione è l'angolo FBA. </s>
              <s id="N1844D">ſimilmente IH ſi moue ſopra il
                <lb/>
              piano BC nell'angolo FBC. </s>
              <s id="id.2.1.1268.6.0">le parti dunque di quel che ſi ſende moueranſi ſo­
                <lb/>
              pra piani inchinati all'orizonte. </s>
              <s id="id.2.1.1268.7.0">& quantunque il piano BC ſia ſotto l'orizonte;
                <lb/>
              tutta via la parte IH ſi moue ſopra IC, come ſe BC foſſe ſopra l'orizonte nel­
                <lb/>
              l'angolo DBC: percioche le parti di quel che ſi fende ſi mouono nel tempo me­
                <lb/>
              deſimo dall'iſteſſa poſſanza. </s>
              <s id="id.2.1.1268.8.0">ſarà dunque la medeſima ragione del mouimento della
                <lb/>
              parte IH, & della parte KF. </s>
              <s id="id.2.1.1268.9.0">ſimilmente è l'iſteſſa ragione ſe EF è egualmente
                <lb/>
              diſtante dall'orizonte, ouero ſe è à piombo dell'orizonte, ouero in altro modo: pe
                <lb/>
              roche egli è neceſſario, che la poſſanza, laquale moue il cuneo, ſia la medeſima, re­
                <lb/>
              ſtando le altre coſe le medeſime. </s>
              <s id="id.2.1.1268.10.0">ſarà dunque la ſteſſa ragione.
                <emph.end type="italics"/>
              </s>
            </p>
          </chap>
        </body>
      </text>
    </archimedes>
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