Tartaglia, Niccolo, Quesiti et inventioni diverse, 1554

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              <p type="main">
                <s id="s.003243">
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                medema radice ſe puo anchora trouar ſopra el maggior nome, cioe ſopra
                  <emph.end type="italics"/>
                <22>. </s>
                <s id="s.003244">108.
                  <emph type="italics"/>
                per
                  <lb/>
                el medeſimo modo, ma la radice cu. </s>
                <s id="s.003245">del noſtro numero cubo ſara el maggior nome del­
                  <lb/>
                la noſtra binomial radice, ouer reſiduale eſſendo reſiduo eſſempi gratia, faremo, pur
                  <lb/>
                de
                  <emph.end type="italics"/>
                <22>. </s>
                <s id="s.003246">108
                  <emph type="italics"/>
                ſimplicemente due tal parti, che luna ſia
                  <emph.end type="italics"/>
                <22>.
                  <emph type="italics"/>
                de un numero cubo & che l'al­
                  <lb/>
                tra ſia diuiſibile per. </s>
                <s id="s.003247">3. come radice, cioe per el quadrato de. </s>
                <s id="s.003248">3. ch'è. </s>
                <s id="s.003249">9. Onde
                  <expan abbr="inueſtigãdo">inueſtigando</expan>
                  <lb/>
                come di ſopra fu fatto ſopra li numeri cubi ſe ritrouara che tal
                  <emph.end type="italics"/>
                <22>.
                  <emph type="italics"/>
                de numero cubo ſa
                  <lb/>
                ra la
                  <emph.end type="italics"/>
                <22>. </s>
                <s id="s.003250">27.
                  <emph type="italics"/>
                hor dico che la radice cu.de
                  <emph.end type="italics"/>
                <22>. </s>
                <s id="s.003251">27. (
                  <emph type="italics"/>
                qual è
                  <emph.end type="italics"/>
                <22>. </s>
                <s id="s.003252">3.)
                  <emph type="italics"/>
                ſara el maggior nomè
                  <lb/>
                del noſtro Radical binomio, (ouer reſiduo) ſe fuſſe reſiduo & queſta parte de
                  <emph.end type="italics"/>
                <22>. </s>
                <s id="s.003253">27.
                  <lb/>
                  <emph type="italics"/>
                  <expan abbr="ſottrahẽdo">ſottrahendo</expan>
                la del tutto, cioe de
                  <emph.end type="italics"/>
                <22>. </s>
                <s id="s.003254">108.
                  <emph type="italics"/>
                reſtara pur
                  <emph.end type="italics"/>
                <22>. </s>
                <s id="s.003255">27.
                  <emph type="italics"/>
                della quale
                  <expan abbr="pigliãdone">pigliandone</expan>
                la ſua
                  <lb/>
                terza parte, come radice, (che ſara la nona) ne uenira
                  <emph.end type="italics"/>
                <22>. </s>
                <s id="s.003256">3.
                  <emph type="italics"/>
                & queſta
                  <expan abbr="partẽdola">partendola</expan>
                per el
                  <lb/>
                noſtro primo nome, (cioe <21> la
                  <emph.end type="italics"/>
                <22>.
                  <emph type="italics"/>
                cu.della noſtra
                  <emph.end type="italics"/>
                <22>. </s>
                <s id="s.003257">27.
                  <emph type="italics"/>
                qual è pur
                  <emph.end type="italics"/>
                <22>. </s>
                <s id="s.003258">3.)
                  <emph type="italics"/>
                de tal parti
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                  <expan abbr="mẽto">mento</expan>
                ne uenira. </s>
                <s id="s.003259">1. et la
                  <emph.end type="italics"/>
                <22>.
                  <emph type="italics"/>
                de. </s>
                <s id="s.003260">1. qual è pur. </s>
                <s id="s.003261">1. ſara el menor nome del noſtro radical bi­
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                nomio ouer reſiduo, cioe che la radice cu.de
                  <emph.end type="italics"/>
                <22>. </s>
                <s id="s.003262">108.
                  <emph type="italics"/>
                piu. </s>
                <s id="s.003263">10. ſaria
                  <emph.end type="italics"/>
                <22>. </s>
                <s id="s.003264">3.
                  <emph type="italics"/>
                piu. </s>
                <s id="s.003265">1. e de
                  <emph.end type="italics"/>
                <22>. </s>
                <s id="s.003266">108
                  <lb/>
                  <emph type="italics"/>
                men. </s>
                <s id="s.003267">10 la ſaria
                  <emph.end type="italics"/>
                <22>. </s>
                <s id="s.003268">3.
                  <emph type="italics"/>
                men. </s>
                <s id="s.003269">1. ſi come fu anchor a determinato, ouer trouato ſopra el. </s>
                <s id="s.003270">10.
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                & per tal uia ſi puo anchora conoſcere ſe uno binomio, ouer reſiduo propoſto è cubo,
                  <lb/>
                ouer non cubo, perche s'eglie cubo biſogna che il nostro operare ſe incontri in luno et
                  <lb/>
                laltro nome et non potendoli far incontrare, tal binomio, ouer reſiduo non ſaria cubo.
                  <emph.end type="italics"/>
                </s>
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              <p type="main">
                <s id="s.003271">D
                  <emph type="italics"/>
                apoi uedo anchora che lui ſe laſſa dar ad intendere dal detto
                  <emph.end type="italics"/>
                M. Z
                  <emph type="italics"/>
                uane, che lui
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                habbia ritrouato il modo, ouer regola di ſoluere quella queſtione, che dice, fame di. </s>
                <s id="s.003272">10.
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                tre parti continue proportionale, che la prima moltiplicata nella ſeconda faccia. </s>
                <s id="s.003273">8. Et
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                gli crede fermamente per hauerli fatto offerta de inſignarglila ſe gli renoncia la lettu­
                  <lb/>
                ra, et non ſi auede il poueretto, che il non gli fa tal oblatione ſe non per fargli credere,
                  <lb/>
                che habbia detta regola, accio che habbia tema di lui, perche luiſa bene, che non ui re­
                  <lb/>
                nontiaria la lettura per inſignargli la regola di riſoluere tal ragione, non tanto per la
                  <lb/>
                lettura, ma per la uergogna, che gli ne ſeguiria, e pero uedo che eglie di poco ingegno.
                  <emph.end type="italics"/>
                </s>
              </p>
              <p type="main">
                <s id="s.003274">D
                  <emph type="italics"/>
                apoi dice, che il detto
                  <emph.end type="italics"/>
                M.Z
                  <emph type="italics"/>
                uane confeſſa non ſaper ſoluere quell'altra ſua propo­
                  <lb/>
                ſta ragione, et che la è ſolubile, perche il detto
                  <emph.end type="italics"/>
                M.Z
                  <emph type="italics"/>
                uane gli ha detto, che la ſe riſolue
                  <lb/>
                per un certo andare, et non ſe auede, che lui dice due coſe contrarie, cioe che il non la ſa
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                riſoluere, et che la ſe riſolue per un certo andar, perche ſe il non la ſa riſoluere manco
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                el puo ſapere perche uia, ouer perche andar laſe riſolue. </s>
                <s id="s.003275">Dapoi dice che lui ha la de­
                  <lb/>
                moſtratione
                  <expan abbr="qualmẽte">qualmente</expan>
                il cerchio é di maggior contenuta de ogni altra figura, & li pa
                  <lb/>
                re a lui che queſto ſia troppo gran coſa, la quale quantunque alcun autor non haueſſe
                  <lb/>
                mai parlato, ſe potria trouar di dimostrarla in piu modi, cioe ch'eglie piu capace de
                  <lb/>
                ogni figura iſoperimetra per le coſe dimostrate da Archimede, & anchora dal Cardi
                  <lb/>
                nal de Cuſa. </s>
                <s id="s.003276">In quello de traſmutatiouibus Geometricis, e per queſto conoſco che con­
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                tien poco ſugo. </s>
                <s id="s.003277">Dapoi uedendo anchora che lui non ſa riſoluere quella ultima queſtio
                  <lb/>
                ne geometrica ch'é una coſa facile, (perche la maggior difficulta che occorra nella ri
                  <lb/>
                ſolution di quella é à ſaper ritrouar le due partiale linee.c.e.et.a.f.le quale ſon medie
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                continua proportionalita fra li dui lati del paralellogramo.a.c. </s>
                <s id="s.003278">delli quali luno é. </s>
                <s id="s.003279">2.
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                & laltro. </s>
                <s id="s.003280">3. dal preſuppoſito & trouate quelle con facilita ſe ritrouara la quanti­
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                ta de la linea.d.e.ouer.d.f.) lo giudico di poco diſcorſo. </s>
                <s id="s.003281">Et per queſto non li uo­
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                glio dar altrariſpoſta, perche è non ui ho piu affetione à lui che à meſſer Zuanne, e
                  <emph.end type="italics"/>
                </s>
              </p>
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