Harriot, Thomas, Mss. 6782

Page concordance

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Scan Original
251 126
252 126v
253 127
254 127v
255 128
256 128v
257 129
258 129v
259 130
260 130v
261 131
262 131v
263 132
264 132v
265 133
266 133v
267 134
268 134v
269 135
270 135v
271 136
272 136v
273 137
274 137v
275 138
276 138v
277 139
278 139v
279 140
280 140v
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page |< < (126) of 1011 > >|
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            <p>
              <s xml:space="preserve">[
                <emph style="bf">Commentary:</emph>
              </s>
            </p>
            <p>
              <s xml:space="preserve"> On this folio and the next (Add MS
                <ref target="http://echo.mpiwg-berlin.mpg.de/ECHOdocuView?url=/permanent/library/HSPGZ0AE&start=250&viewMode=image&pn=251"> f. </ref>
                <ref target="http://echo.mpiwg-berlin.mpg.de/ECHOdocuView?url=/permanent/library/HSPGZ0AE&start=250&viewMode=image&pn=253"> f. </ref>
              ), Harriot has used the formulae from page 17 (Add MS 6782
                <ref target="http://echo.mpiwg-berlin.mpg.de/ECHOdocuView?url=/permanent/library/HSPGZ0AE&start=240&viewMode=image&pn=247"> f. </ref>
              ) to write equations for
                <math>
                  <mstyle>
                    <mi>a</mi>
                  </mstyle>
                </math>
              ,
                <math>
                  <mstyle>
                    <mi>b</mi>
                  </mstyle>
                </math>
              ,
                <math>
                  <mstyle>
                    <mi>c</mi>
                  </mstyle>
                </math>
              ,
                <math>
                  <mstyle>
                    <mi>d</mi>
                  </mstyle>
                </math>
              ,
                <math>
                  <mstyle>
                    <mi>f</mi>
                  </mstyle>
                </math>
              , and
                <math>
                  <mstyle>
                    <mi>g</mi>
                  </mstyle>
                </math>
              in terms of
                <math>
                  <mstyle>
                    <mi>A</mi>
                  </mstyle>
                </math>
              ,
                <math>
                  <mstyle>
                    <mi>B</mi>
                  </mstyle>
                </math>
              ,
                <math>
                  <mstyle>
                    <mi>C</mi>
                  </mstyle>
                </math>
              ,
                <math>
                  <mstyle>
                    <mi>D</mi>
                  </mstyle>
                </math>
              ,
                <math>
                  <mstyle>
                    <mi>F</mi>
                  </mstyle>
                </math>
              , and
                <math>
                  <mstyle>
                    <mi>G</mi>
                  </mstyle>
                </math>
              . He has solved first for
                <math>
                  <mstyle>
                    <mi>a</mi>
                  </mstyle>
                </math>
              in terms of
                <math>
                  <mstyle>
                    <mi>A</mi>
                  </mstyle>
                </math>
              , then for
                <math>
                  <mstyle>
                    <mi>b</mi>
                  </mstyle>
                </math>
              in terms of
                <math>
                  <mstyle>
                    <mi>A</mi>
                  </mstyle>
                </math>
              and
                <math>
                  <mstyle>
                    <mi>B</mi>
                  </mstyle>
                </math>
              , then for
                <math>
                  <mstyle>
                    <mi>c</mi>
                  </mstyle>
                </math>
              in terms of
                <math>
                  <mstyle>
                    <mi>A</mi>
                  </mstyle>
                </math>
              ,
                <math>
                  <mstyle>
                    <mi>B</mi>
                  </mstyle>
                </math>
              , and
                <math>
                  <mstyle>
                    <mi>C</mi>
                  </mstyle>
                </math>
              , and so on. He has ended each calculation with 'RE', indicating 'recto' or 'correct'. </s>
              <s xml:space="preserve">]</s>
            </p>
          </div>
          <head xml:space="preserve"/>
          <p>
            <s xml:space="preserve"> 1. Canon.
              <math>
                <mstyle>
                  <mi>g</mi>
                </mstyle>
              </math>
              <lb/>
            [
              <emph style="bf">Translation: </emph>
            Canon for
              <math>
                <mstyle>
                  <mi>g</mi>
                </mstyle>
              </math>
            </s>
          </p>
        </div>
      </text>
    </echo>