Casati, Paolo, Fabrica, et uso del compasso di proportione, dove insegna à gli artefici il modo di fare in esso le necessarie divisioni, e con varij problemi ...

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        <div xml:id="echoid-div144" type="section" level="1" n="83">
          <p>
            <s xml:id="echoid-s4454" xml:space="preserve">
              <pb o="236" file="0256" n="260" rhead="CAPO X."/>
            dà vn quadrato vguale à quel ſegmento. </s>
            <s xml:id="echoid-s4455" xml:space="preserve">Dunque dato qua-
              <lb/>
            lunque ſegmento di circolo, la metà della ſua corda ſi appli-
              <lb/>
            chi all’interuallo *** ***: </s>
            <s xml:id="echoid-s4456" xml:space="preserve">poi ritenuta l’apertura medeſima
              <lb/>
            dello Stromento ſi veda à che interuallo delli numeri eſteriori
              <lb/>
            capiſca l’altezza data del ſegmento, e ſia per eſſempio alli
              <lb/>
            punti 3. </s>
            <s xml:id="echoid-s4457" xml:space="preserve">3. </s>
            <s xml:id="echoid-s4458" xml:space="preserve">eſteriori; </s>
            <s xml:id="echoid-s4459" xml:space="preserve">perciò prendendoſi l’interuallo 3. </s>
            <s xml:id="echoid-s4460" xml:space="preserve">3.
              <lb/>
            </s>
            <s xml:id="echoid-s4461" xml:space="preserve">delli numeri interiori ſi haurà la linea, che dà il quadrato
              <lb/>
            vguale al dato ſegmento.</s>
            <s xml:id="echoid-s4462" xml:space="preserve"/>
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        <div xml:id="echoid-div148" type="section" level="1" n="84">
          <head xml:id="echoid-head156" xml:space="preserve">QVESTIONE PRIMA.</head>
          <head xml:id="echoid-head157" style="it" xml:space="preserve">Se due Circoli diſuguali ſi tagliano, come ſi troui la quantità
            <lb/>
          dell’area, in cui communicano, e la lunula che reſta.</head>
          <p>
            <s xml:id="echoid-s4463" xml:space="preserve">HAbbiaſi riceuuta ſopra vna carta la ſpecie optica dell’
              <lb/>
            Ecliſſe del Sole, e ſia ADB il termine dell’oſcuratione,
              <lb/>
            e vogliaſi ſapere, quanta ſia la parte del diſco Solare oſcura-
              <lb/>
            ta, e coperta dalla luna. </s>
            <s xml:id="echoid-s4464" xml:space="preserve">Tiriſi alli punti A & </s>
            <s xml:id="echoid-s4465" xml:space="preserve">B, doue le cir-
              <lb/>
            conferenze ſi tagliano, la corda A B, e queſta diuiſa per mez-
              <lb/>
            zo in F ſia tagliata dalla perpendicolare DC: </s>
            <s xml:id="echoid-s4466" xml:space="preserve">Quindi la metà
              <lb/>
            della corda A B, cioè F B, ſi applichi nelle linee Quadratrici
              <lb/>
            all’interuallo *** ***, poi preſa l’altezza
              <lb/>
              <figure xlink:label="fig-0256-01" xlink:href="fig-0256-01a" number="71">
                <image file="0256-01" xlink:href="http://echo.mpiwg-berlin.mpg.de/zogilib?fn=/permanent/library/xxxxxxxx/figures/0256-01"/>
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            FD veggaſi à quall’interuallo de’nume-
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            ri eſteriori
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            ella capiſca; </s>
            <s xml:id="echoid-s4467" xml:space="preserve">& </s>
            <s xml:id="echoid-s4468" xml:space="preserve">alli numeri
              <lb/>
            interiori corriſpondenti ſi haurà la li-
              <lb/>
            nea del quadrato vguale al ſegmento
              <lb/>
            A D B F.</s>
            <s xml:id="echoid-s4469" xml:space="preserve"/>
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          <p>
            <s xml:id="echoid-s4470" xml:space="preserve">Similmente preſa la altezza FC, & </s>
            <s xml:id="echoid-s4471" xml:space="preserve">
              <lb/>
            applicata alli numeri eſteriori, doue
              <lb/>
            capiſce, ſi vedrà qual interuallo </s>
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