DelMonte, Guidubaldo, Le mechaniche

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          <chap id="N18810">
            <p id="id.2.1.1358.0.0" type="main">
              <s id="N18D66">
                <pb pagenum="123" xlink:href="037/01/261.jpg"/>
                <emph type="italics"/>
              al cuneo GFEKL; ſarà TR eguale ad eſſa PN, & al Perimetro del cilindro
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              & QR eguale à GE. </s>
              <s id="N18D73">& per eſſere GE maggiore di AC, ſarà anco RQ mag
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              giore di MN. </s>
              <s id="id.2.1.1358.4.0">tagliſi RQ in V, & facciaſi RV eguale ad eſſa MN, & con­
                <lb/>
              giungaſi TV: ſarà il triangolo TVR eguale al triangolo MPN; percioche le
                <lb/>
              due linee TRRV ſono eguali alle due PN NM, & gli angoli i quali conten­
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              gono ſono eguali, cioè retti. </s>
              <s id="id.2.1.1358.5.0">dunque l'angolo RTV ſarà eguale all'angolo NPM.
                <emph.end type="italics"/>
                <arrow.to.target n="note316"/>
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              </s>
              <s id="N18D89">
                <emph type="italics"/>
              Per laqual coſa l'angolo MPN è minore dell'angolo QTR; & i doppi di queſti,
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              cioè l'angolo MPO è minore dell'angolo QTS. </s>
              <s id="id.2.1.1358.6.0">Hor percioche il cuneo, ilquale hà
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              l'angolo alla cima minore più facilmente moue, & fende, che quello che l'ha maggio
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              re. </s>
              <s id="id.2.1.1358.7.0">dunque il cuneo MPO più facilmente mouerà, che QTS. </s>
              <s id="id.2.1.1358.8.0">piu facilmente dun
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              que ſarà moſſo il peſo dal cuneo ADCHI, che dal cuneo GFEKL. </s>
              <s id="N18D9E">dunque il
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              peſo più facilmente ſarà moſſo ſoprala helice CDA, che ſopra la EFG. </s>
              <s id="N18DA2">& nel
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              modo iſteſſo proueraſſi, che quanto minore ſarà AC tanto più ageuolmente ſi mo
                <lb/>
              uerà il peſo. </s>
              <s id="id.2.1.1358.9.0">il che biſognaua moſtrare.
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              </s>
            </p>
            <p id="id.2.1.1360.0.0" type="margin">
              <s id="id.2.1.1360.1.0">
                <margin.target id="note314"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              1.
                <emph type="italics"/>
              di questo.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.1361.0.0" type="margin">
              <s id="id.2.1.1361.1.0">
                <margin.target id="note315"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              1.
                <emph type="italics"/>
              di questo.
                <emph.end type="italics"/>
              </s>
            </p>
            <p id="id.2.1.1362.0.0" type="margin">
              <s id="id.2.1.1362.1.0">
                <margin.target id="note316"/>
                <emph type="italics"/>
              Per la
                <emph.end type="italics"/>
              4.
                <emph type="italics"/>
              del primo.
                <emph.end type="italics"/>
              </s>
            </p>
          </chap>
        </body>
      </text>
    </archimedes>
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