Fabri, Honoré, Tractatus physicus de motu locali, 1646

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              <s id="N1EAF3">Denique poteſt deſcendere per plura plana inclinata AKLMNO
                <lb/>
              PQRST, ſiue ducantur perpendiculariter, ſcilicet AK in BC, KL in B
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              D, atque ita deinceps; </s>
              <s id="N1EAFB">ſiue non perpendiculariter, modò DL ſit maior C
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              K, EM maior DL, at que ita deinceps; attamen vltimum planum TB non
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              erit inclinatum, ſed perpendiculum, vt patet. </s>
            </p>
            <p id="N1EB03" type="main">
              <s id="N1EB05">
                <emph type="center"/>
                <emph type="italics"/>
              Theorema
                <emph.end type="italics"/>
              98.
                <emph.end type="center"/>
              </s>
            </p>
            <p id="N1EB11" type="main">
              <s id="N1EB13">
                <emph type="italics"/>
              Poſſunt eſſe infinita plana inter orbem terræ, & horizontale per quæ globus
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              ſeu corpus graue non deſcendet
                <emph.end type="italics"/>
              ; </s>
              <s id="N1EB1E">ſit enim centrum terræ C, ex quo deſcri­
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              batur arcus QMH ducta diametro MCA in M; </s>
              <s id="N1EB24">ducatur Tangens NM
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              L; </s>
              <s id="N1EB2A">hæc erit horizontale planum, vt conſtat; </s>
              <s id="N1EB2E">tùm ex aliquo puncto infra C
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              putà ex A deſcribatur arcus SMK; </s>
              <s id="N1EB34">cercè ſi ponatur globus in M non
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              deſcendet per arcum MG, quia potiùs aſcenderet; </s>
              <s id="N1EB3A">immò ſi ponatur
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              in T deſcendet in M, immò faciliùs pelleretur corpus graue per arcum
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              MT, quàm per horizontalem MN, vt patet; </s>
              <s id="N1EB42">igitur potentia illa, quæ per
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              horizontalem pellit non eſt omnium minima, quæ per arcum MQ pel­
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              lit; quia in eo nullo modo globus aſcendit, ſed ſemper à centro C æqui­
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              diſtat. </s>
              <s id="N1EB4C">Si verò aſſumas quæcumque centra ſupra B putà D, & E, & ducas
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              arcus TMGPOMF; </s>
              <s id="N1EB52">certè globus deſcendet per MO, & MP, vt manife­
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              ſtum eſt ex dictis, & hoc fortè ludicrum cuiquam videbitur; </s>
              <s id="N1EB58">ſi enim col­
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              locetur globus in T, deſcendit verſus M; </s>
              <s id="N1EB5E">ſi verò in Y deſcendet verſus
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              P; </s>
              <s id="N1EB64">licèt V & T non diſtét pollice; </s>
              <s id="N1EB68">poſſunt enim accipi minima illa ſpatia
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              verſus M, vbi eſt angulus contingentiæ; </s>
              <s id="N1EB6E">nulla tamen poteſt duci recta ab
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              M infra MN, per quam globus non deſcendat velociùs initio, quàm per
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              vllum arcum, ſiue MP, ſiue MO, ſiue quemcumque alium quamtumuis
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              maximè incuruatum vel inclinatum; </s>
              <s id="N1EB78">quia ſcilicet recta illa ducta ex M
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              infra MN ſecat omnes illos arcus, vt patet; </s>
              <s id="N1EB7E">igitur initio facit planum
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              inclinatius: dixi initio, quia deinde in arcu multùm inualeſcit motus,
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              cum ſemper deficiat in recta, vt diximus abundè ſuprà. </s>
            </p>
            <p id="N1EB86" type="main">
              <s id="N1EB88">
                <emph type="center"/>
                <emph type="italics"/>
              Theorema
                <emph.end type="italics"/>
              99.
                <emph.end type="center"/>
              </s>
            </p>
            <p id="N1EB94" type="main">
              <s id="N1EB96">
                <emph type="italics"/>
              Si quadrans ita diſtet à centro mundi, vt tùm alter eius radius, tùm Tan­
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              gens ipſi parallela cenſeantur perpendiculares, globus deſcendet ex eius vertice
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              per arcum
                <emph.end type="italics"/>
              : </s>
              <s id="N1EBA3">Sit enim quadrans ATE erectus ſupra horizontem, ita vt
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              AE ſit horizontalis, & tùm TA, tùm 3. A perpendiculares; </s>
              <s id="N1EBA9">certè deſcen­
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              det globus per eius conuexum VBA in eadem proportione, in qua deſ­
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              cerdit per ſemicirculum, de quo ſuprà; </s>
              <s id="N1EBB1">Igitur motus per quadrantem T
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              BE eſt ad motum per ipſum perpendiculum in eadem ratione, in qua eſt
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              ad motum per ſemicirculum; </s>
              <s id="N1EBB9">quippe motus in T nullus eſt per arcum TE; </s>
              <s id="N1EBBD">
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              5.verò motus per arcum 5.E, initio ſcilicet, vt ſæpè dictum eſt, eſt ad mo­
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              tum per ipſam perpendicularem vt A 7.ad A 5.in 4.vt A 7.ad A 4. in B
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              vt A
                <foreign lang="grc">δ</foreign>
              ad AB, in D vt AH ad AD in X vt AF ad AX, in E, vt AE ad A
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              E; </s>
              <s id="N1EBCC">vides autem tranſire motum hunc ferè per omnes gradus tarditatis: </s>
              <s id="N1EBD0">di­
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              co ferè, quia reuerâ non tranſit per omnes; quippe ſi fieret maior qua­
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              drans tangens iſtum in T, motus eſſet iuxta initium præſertim tar­
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              dior. </s>
            </p>
          </chap>
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    </archimedes>
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