Clavius, Christoph, Geometria practica

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269239LIBER SEXTVS.
PROBLEMA 1. PROPOSITIO 2.
DATO rectilineo ſuper datam rectam inter alias duas rectas interce-
ptam, conſtituere quadrilaterum æquale, cuius latus oppoſitum in-
ter duas eaſdem rectas, interceptum datæ rectæ ſit parallelum.
Et
datis duobus rectilineis inæqualibus quibuſcunque, ex maiore per
lineam vni lateri parallelam detrahere rectilineum minori æquale,
quando id fieri poteſt, quod ex ipſa problematis ſolutione cogno-
ſcetur.
Sit rectilineum datum A, & recta data B C, inter duas rectas B D, C E,
intercepta:
oporteatque primum conſtitue-
173[Figure 173] rerectilineo A, æquale quadrilaterum ſuper da-
tam rectam B C, cuius latus oppoſitum inter
eaſdem rectas BD, C E, interceptum datærectæ
BC, ſit parallelum.
Et ſi quidem duæ rectæ BD,
C E, ſint parallelæ (quodtum demum eueniet,
cum duo anguli B, C, æquales ſunt, duobus
rectis) efficietur problema, ſi ſuper rectam B C, conſtituetur 1145. primi. grammum B E, ſiue in angulo B C E, ſiue in angulo C B D, rectilineo A, æ-
quale.
2. Qvando anguli B, C, rectiſunt, facilius problema effi ciemus hac ra-
tione.
Rectilineo dato A, conſtituatur per ea, quæ in ſcholio propoſ. 14. lib.
2. Euclid. vel potius per ea, quæ Num. 4. cap. 4. lib. 4. huius Geometriæ pra-
cticæ ſcripſimus, quadratum F G H, æquale:
reſoluendo videlicet rectili-
n@um in triangula, vel trapezia, &
cuilibet triangulo, vel trapezio æquale qua-
174[Figure 174] dratum conſtituendo, ac tandem omnia illa quadrata ad vnum redigendo, vt
locis citatis fusè explicauimus.
Deinde duabus rectis B C, F G,

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