Salusbury, Thomas
,
Mathematical collections and translations (Tome I)
,
1667
Text
Text Image
Image
XML
Thumbnail overview
Document information
None
Concordance
Figures
Thumbnails
Page concordance
<
1 - 30
31 - 60
61 - 90
91 - 120
121 - 150
151 - 180
181 - 210
211 - 240
241 - 270
271 - 300
301 - 330
331 - 360
361 - 390
391 - 420
421 - 450
451 - 480
481 - 510
511 - 540
541 - 570
571 - 600
601 - 630
631 - 660
661 - 690
691 - 701
>
Scan
Original
211
212
213
214
215
216
217
218
219
220
221
222
223
224
225
226
227
228
229
230
231
232
233
234
235
236
237
238
239
240
<
1 - 30
31 - 60
61 - 90
91 - 120
121 - 150
151 - 180
181 - 210
211 - 240
241 - 270
271 - 300
301 - 330
331 - 360
361 - 390
391 - 420
421 - 450
451 - 480
481 - 510
511 - 540
541 - 570
571 - 600
601 - 630
631 - 660
661 - 690
691 - 701
>
page
|<
<
of 701
>
>|
<
archimedes
>
<
text
>
<
body
>
<
chap
>
<
p
type
="
main
">
<
s
>
<
pb
xlink:href
="
040/01/307.jpg
"
pagenum
="
287
"/>
T I F, which is alſo rectangular, there is known the angle F,
<
lb
/>
ken by the parallax. </
s
>
<
s
>Then note in ſome place apart the two
<
lb
/>
gles I O T and I F T, and of them take the ſines, which are
<
lb
/>
here ſet down to them, as you ſeen. </
s
>
<
s
>And becauſe in the triangle
<
lb
/>
I O T, the ſine T I is 92276. of thoſe parts, whereof the whole
<
lb
/>
ſine TO is 100000; and moreover in the triangle I F T, the ſine T I
<
lb
/>
is 582. of thoſe parts, whereof the whole ſine T F is 100000, to
<
lb
/>
find how many T F is of thoſe parts, whereof T O is 100000;
<
lb
/>
we will ſay by the Rule of three: If T I be 582. T F is an
<
lb
/>
100000. but if T I were 92276. how much would T F be.
<
lb
/>
</
s
>
<
s
>Let us multiply 92276. by 100000. and the product will be
<
lb
/>
9227600000. and this muſt be divided by 582. and the quotient
<
lb
/>
will be 15854982. and ſo many ſhall there be in T F of thoſe
<
lb
/>
parts, of which there are in T O an 100000. So that if it were
<
lb
/>
required to know how many lines T O, are in T F, we would
<
lb
/>
divide 15854982 by 100000. and there will come forth 158. and
<
lb
/>
very near an half; and ſo many diameters ſhall be the diſtance
<
lb
/>
of the ſtar F, from the centre T, and to abreviate the
<
lb
/>
tion, we ſeeing, that the product of the multiplication of 92276.
<
lb
/>
by 100000, ought to be divided firſt by 582, and then the
<
lb
/>
tient of that diviſion by 100000. we may without multiplying
<
lb
/>
92276. by 100000. and with one onely diviſion of the ſine
<
lb
/>
92276. by the ſine 582. ſoon obtain the ſame ſolution, as may
<
lb
/>
be ſeen there below; where 92276. divided by 582. giveth us the
<
lb
/>
ſaid 158 1/2, or thereabouts. </
s
>
<
s
>Let us bear in mind therefore, that
<
lb
/>
the onely diviſion of the ſine T I, as the ſine of the angle T O I
<
lb
/>
by the ſine T I, as the ſine of the angle I F T, giveth us the
<
lb
/>
ſtance ſought T F, in ſo many diameters T
<
lb
/>
<
arrow.to.target
n
="
table59
"/>
<
lb
/>
<
arrow.to.target
n
="
table60
"/>
<
lb
/>
<
arrow.to.target
n
="
table61
"/>
</
s
>
</
p
>
</
chap
>
</
body
>
</
text
>
</
archimedes
>