Mersenne, Marin; Galilei, Galileo, Qvestions physico-mathematiqves : et Les mechaniqves du sieur Galilee : avec Les Prelvdes de l' harmonie vniuerselle vtiles aux philosophes, aux medecins, aux astrologues, aux ingenieurs, & aux musiciens Les questions theologiques, physiques, morales, et mathematiques, 1635

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          <p>
            <s xml:id="echoid-s4484" xml:space="preserve">
              <pb o="53" file="00332" n="331" rhead="de Galilée Florentin."/>
            litude des triangles KBF & </s>
            <s xml:id="echoid-s4485" xml:space="preserve">KFH, qu’il
              <lb/>
            y a meſme raiſon de FK à FH que de
              <lb/>
            KB à BF. </s>
            <s xml:id="echoid-s4486" xml:space="preserve">D’où nous conclüons que la
              <lb/>
            proportion du moment total & </s>
            <s xml:id="echoid-s4487" xml:space="preserve">abſolu
              <lb/>
            du mobile dans la perpendiculaire de
              <lb/>
            l’orizon auec le moment qu’il a ſur le
              <lb/>
            plan incliné HF eſt la meſme que la
              <lb/>
            proportion de FH à FK.</s>
            <s xml:id="echoid-s4488" xml:space="preserve"/>
          </p>
          <p>
            <s xml:id="echoid-s4489" xml:space="preserve">Ce qui ſe void plus diſtinctement
              <lb/>
              <figure xlink:label="fig-00332-01" xlink:href="fig-00332-01a" number="34">
                <image file="00332-01" xlink:href="http://echo.mpiwg-berlin.mpg.de/zogilib?fn=/permanent/library/xxxxxxxx/figures/00332-01"/>
              </figure>
            dans le triangle A
              <lb/>
            BC car le moment
              <lb/>
            du mobile ſur le
              <lb/>
            plan AC eſt d’au-
              <lb/>
            tãt moindre que le
              <lb/>
            moment qu’il a dãs
              <lb/>
            la perpendiculaire CB, que CB eſt
              <lb/>
            moindre que C A. </s>
            <s xml:id="echoid-s4490" xml:space="preserve">Et parce qu’il ſuffit
              <lb/>
            pour mouuoir le fardeau, que la force
              <lb/>
            ſurpaſſe inſenſiblemĕt celle quile ſou-
              <lb/>
            ſtient en quelque lieu que cèſoit, nous
              <lb/>
            faisõs icy cette propoſition vniuerſelle.</s>
            <s xml:id="echoid-s4491" xml:space="preserve"/>
          </p>
          <p>
            <s xml:id="echoid-s4492" xml:space="preserve">Que ſur le plan elcué la force a la meſ-
              <lb/>
              <emph style="bf">me proportion au poids que la perpen-</emph>
              <lb/>
              <emph style="bf">diculaire tirée de l’extremité du plan ſur</emph>
              <lb/>
              <emph style="bf">l orizon à la longueur dudit plan, c’ eſt à dire</emph>
              <lb/>
              <emph style="bf">que la tangente à la ſecante</emph>
            , car FK eſt la
              <lb/>
            tangente du cercle deſcrit ſur le dia-
              <lb/>
            mettre KH, & </s>
            <s xml:id="echoid-s4493" xml:space="preserve">FH eſt la ſecante.</s>
            <s xml:id="echoid-s4494" xml:space="preserve"/>
          </p>
        </div>
      </text>
    </echo>
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