Bernstein, Aaron, Naturwissenschaftliche Volksbücher, Bd. 1/5, 1897

Table of figures

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        <div xml:id="echoid-div175" type="section" level="1" n="134">
          <p>
            <s xml:id="echoid-s4516" xml:space="preserve">
              <pb o="43" file="335" n="335"/>
            1. </s>
            <s xml:id="echoid-s4517" xml:space="preserve">3. </s>
            <s xml:id="echoid-s4518" xml:space="preserve">5. </s>
            <s xml:id="echoid-s4519" xml:space="preserve">7. </s>
            <s xml:id="echoid-s4520" xml:space="preserve">9. </s>
            <s xml:id="echoid-s4521" xml:space="preserve">11. </s>
            <s xml:id="echoid-s4522" xml:space="preserve">In dieſen gewiß ſehr leicht aufzuſtellenden
              <lb/>
            Zahlen beſitzt man alſo eine vollſtändige Tabelle für die Fall-
              <lb/>
            räume in jeder der ſechs erſten Sekunden.</s>
            <s xml:id="echoid-s4523" xml:space="preserve"/>
          </p>
          <p>
            <s xml:id="echoid-s4524" xml:space="preserve">Aus dieſer Tabelle erſehen wir, daß der Stein während
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            der erſten Sekunde
              <emph style="sp">einen</emph>
            Fallraum durchläuft, in der zweiten
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            dritten durchläuft er 5 Fallräume, in der
              <lb/>
              <figure xlink:label="fig-335-01" xlink:href="fig-335-01a" number="58">
                <caption xml:id="echoid-caption53" xml:space="preserve">Fig. 4.</caption>
                <variables xml:id="echoid-variables22" xml:space="preserve">a</variables>
              </figure>
            vierten durchläuft er 7 Fallräume, in der
              <lb/>
            fünften durchläuft er 9 Fallräume und
              <lb/>
            während der ſechsten Sekunde durchläuft
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            der Stein 11 Fallräume. </s>
            <s xml:id="echoid-s4525" xml:space="preserve">Will man nun
              <lb/>
            wiſſen, wie viel Fallräume der Stein in
              <lb/>
            allen ſechs Sekunden durchlaufen hat, ſo
              <lb/>
            braucht man nur zu berechnen, daß 1 und
              <lb/>
            3 und 5 und 7 und 9 und 11 gerade 36
              <lb/>
            betragen, ſo hat man’s heraus, daß ein
              <lb/>
            Stein in ſechs Sekunden 36 Fallräume
              <lb/>
            durchfällt, und da jeder Fallraum 5 Meter
              <lb/>
            beträgt, ſo iſt es leicht ausrechnen, daß
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            5 mal 36 ſo viel iſt wie 180 und daraus
              <lb/>
            erſieht man, daß ein Stein, der in ſechs
              <lb/>
            Sekunden zur Erde herabfällt, 180 Meter
              <lb/>
            durchlaufen hat.</s>
            <s xml:id="echoid-s4526" xml:space="preserve"/>
          </p>
          <p>
            <s xml:id="echoid-s4527" xml:space="preserve">Daß dieſes Geſetz richtig iſt, kann
              <lb/>
            man an der ſogenannten
              <emph style="sp">Atwoodſchen</emph>
              <lb/>
            Fallmaſchine (Fig. </s>
            <s xml:id="echoid-s4528" xml:space="preserve">4) ſehen. </s>
            <s xml:id="echoid-s4529" xml:space="preserve">An dieſer
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            Maſchine ſind 2 Gewichte a von gleicher Schwere befeſtigt, die,
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            durch einen über eine Rolle geleiteten Faden mit einander
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            verbunden, ſich im Gleichgewicht halten. </s>
            <s xml:id="echoid-s4530" xml:space="preserve">Beſchwert man nun das
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            eine von beiden durch ein kleines Übergewicht, ſo beginnt es
              <lb/>
            zu fallen, allerdings infolge der verhältnismäßig ſehr ſtarken
              <lb/>
            Reibung des Fadens an der Rolle viel, viel langſamer, als
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            beim freien Fall. </s>
            <s xml:id="echoid-s4531" xml:space="preserve">Sobald man nun weiß, wie groß die </s>
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